I have an user information form in my Laravel site and trying to upload image using Ajax.
Blade
<form id="edit_form" enctype="multipart/form-data">
<input type="hidden" name="_token" id="csrf-token" value="{{ Session::token() }}" />
<div class="form-group">
<label>Image</label>
<input id="edit_form_image" type="file" class="form-control" name="user_image">
</div><!-- end form-group -->
<div class="form-group">
<label>Name</label>
<input id="edit_form_name" type="text" class="form-control" value="{{Auth::user()->name}}">
</div><!-- end form-group -->
<button type="button" id="edit_form_submit" class="btn btn-orange">Save Changes</button>
Ajax
$('#edit_form_submit').click(function(event) {
var fd = new FormData();
var edit_form_image = $('#edit_form_image')[0].files;
var edit_form_name = $('#edit_form_name').val();
var token = $('input[name=_token]').val();
fd.append( 'image', edit_form_image );
fd.append( 'name', edit_form_name );
fd.append( '_token', token );
$.ajax({
url:"{{ url('/profile-update') }}",
data: fd,
async:false,
type: 'POST',
processData: false,
contentType: false,
success:function(msg)
{
console.log(msg);
}
});
});
But in my controller I can't get the image file.
controller
if (request()->hasFile('image'))
{
return "file present";
}
else{
return "file not present";
}
Though I upload an image controller always response that `file no present'.
Where is the error? Anybody Help please ?
why dont you name your input tags as you need to send in post method in :
<input name="image" id="edit_form_image" type="file" class="form-control">
<input name="name" id="edit_form_name" type="text" class="form-control" value="{{Auth::user()->name}}">
And,
$("#edit_form").on('submit',(function(e) {
e.preventDefault();
$.ajax({
url:"{{ url('/profile-update') }}",
type: "POST",
data: new FormData(this),
processData: false,
contentType: false,
success:function(msg)
{
console.log(msg);
}
});
});
This might works.
Related
I have a jQuery function that does the insert of an image with other fields to the database. Currently my function only inserts the image but does not insert the other form fields. I am using formData object and I don't understand how to append my fields together with the image file so I can pass it to the ajax request body.
Here is what I have tried so far:
// submit function
function Submit_highschool() {
jQuery(document).ready(function($) {
$("#highschool").submit(function(event) {
event.preventDefault();
$("#progress").html(
'Inserting <i class="fa fa-spinner fa-spin" aria-hidden="true"></i></span>');
var formData = new FormData($(this)[0]);
var firstname_h = $("#firstname_h").val();
var middlename_h = $("#middlename_h").val();
formData.append(firstname_h, middlename_h);
$.ajax({
url: 'insertFunctions/insertHighSchool.php',
type: 'POST',
data: formData,
async: true,
cache: false,
contentType: false,
processData: false,
success: function(returndata) {
alert(returndata);
},
error: function(xhr, status, error) {
console.error(xhr);
}
});
return false;
});
});
}
// html form
<form method="post" enctype="multipart/form-data" id="highschool">
<div class="card" id="highschool">
<div class="col-3">
<label for="firstname">First name *</label>
<input type="text" class="form-control" id="firstname_h" placeholder="First name" />
</div>
<div class="col-3">
<label for="middlename">Middle name *</label>
<input type="text" class="form-control" id="middlename_h" placeholder="Middle name" />
</div>
<div class="col-6">
<label for="grade11_h">Grade 11 Transcript (image) *</label>
<input type="file" class="form-control" name="grade11_h" id="grade11_h" accept=".png, .jpg, .jpeg">
</div>
<button type="submit" name="submit" class="btn btn-primary float-right" onclick="Submit_highschool();">Submit</button>
</div>
</form>
The image name is succesfully inserted in the db and the image is uploaded to the required target location,However, the fields - firstname and middlename are not inserted and I don't understand how to append these properties to the formData.
How can I pass these fields to the formData please?
You can use the following approach for storing the data with image.
1.In PHP API write logic for Upload image to server using move_uploaded_file() & Insert image file name with server path in the MySQL database using PHP.
2.In JS/JQuery, Read all HTML element & create an object & POST it to the API using AJAX Call.
your JS code should be like this. Hope this will help you to fix the issue.
var RegObj = {
'Field1': $("#Field1").val(),
'Field2': $("#Field2").val(),
'logo': $("#company_logo").attr('src'),
}
console.log(RegObj);
$.ajax({
url: "API_PATH_HERE",
type: "POST",
data: JSON.stringify(RegObj),
headers: {
"Content-Type": "application/json"
},
dataType: 'text',
success: function (result) {
//
},
error: function (xhr, textStatus, errorThrown) {
}
});
Like #Professor Abronsius suggested in the comments section I only needed to add the "name" tag to the form elements and remove the append from my function thus, I have edited the function and the form as follows:
// since I have added the name tag to the form elements, there is now
// no need to use the append() thus, I have commented out the append
// lines.
function Submit_highschool() {
jQuery(document).ready(function($) {
$("#highschool").submit(function(event) {
event.preventDefault();
$("#progress").html(
'Inserting <i class="fa fa-spinner fa-spin" aria-hidden="true"></i></span>');
var formData = new FormData($(this)[0]);
// var firstname_h = $("#firstname_h").val(); // removed this
// var middlename_h = $("#middlename_h").val(); // removed this
//formData.append(firstname_h, middlename_h); // removed this
$.ajax({
url: 'insertFunctions/insertHighSchool.php',
type: 'POST',
data: formData,
async: true,
cache: false,
contentType: false,
processData: false,
success: function(returndata) {
alert(returndata);
},
error: function(xhr, status, error) {
console.error(xhr);
}
});
return false;
});
});
}
// added the "name" tag to the form elements
<form method="post" enctype="multipart/form-data" id="highschool">
<div class="card" id="highschool">
<div class="col-3">
<label for="firstname">First name *</label>
<input type="text" class="form-control" name="firstname_h" id="firstname_h" placeholder="First name" /> // added name="firstname_h"
</div>
<div class="col-3">
<label for="middlename">Middle name *</label>
<input type="text" class="form-control" name="middlename_h" id="middlename_h" placeholder="Middle name" /> // added name="middlename_h"
</div>
<div class="col-6">
<label for="grade11_h">Grade 11 Transcript (image) *</label>
<input type="file" class="form-control" name="grade11_h" id="grade11_h" accept=".png, .jpg, .jpeg">
</div>
<button type="submit" name="submit" class="btn btn-primary float-right" onclick="Submit_highschool();">Submit</button>
</div>
</form>
Im getting a empty file response when sending the formData in ajax, It has a fileupload and some input fields. I get the response in input fields but in file upload its empty. See picture below for code.
<div class="form-group">
<label for="attachments" class="control-label col-xs-1" style="padding: 0px 0px;">Add attachments</label>
<div class="col-lg-8">
<input type="file" name="attachments[]" id="attachments" class="custom-file-input" accept="application/pdf" multiple>
</div>
<div class="col-lg-8">
<input type="text" name="name_file" id="name_file">
</div>
$("#acpl_submit").on("submit", function() {
var formData = new FormData(this);
formData.append("test", "test");
$.ajax({
type: 'POST',
// enctype: 'multipart/form-data',
url: URL,
data: formData,
processData: false,
contentType: false,
cache: false,
success: function (data) {
console.log(data);
},
error: function (data)
{
console.log('Error:', data);
}
});
return false;
});
PHP file, returning the POST data for checking.
public function save_accomp() {
return response()->json(request()->all());
}
I need to handle inputs from form post and I have no idea, how to do it in php, because when I write for example $_POST["header"], it var_dumps null.
I am creating formData object and inserting all inputs from form. Then posting it with ajax.
Can you please help me? I need to handle "header", "content", "password" and files.
<form method="post" enctype="multipart/form-data" id="uploadFiles">
<label for="newsHeader" id="headerLabel">Nadpis</label>
<input type="text" name="newsHeader" id="newsHeader">
<label for="content" id="contentLabel">Text novinky</label>
<textarea name="content" id="content"></textarea>
<label for="files" id="filesLabel">Fotky</label>
<input type="file" name="files" id="files" accept="image/jpeg" multiple>
<label for="password" id="passwordLabel">Heslo pro upload</label>
<input type="text" name="password" id="password">
<button type='submit' id='uploadFilesSubmit'>NAHRÁT</button>
</form>
$("#uploadFiles").submit(function(event){
event.preventDefault();
var formDataObj = new FormData(),
header = $("#newsHeader").val(),
content = $("#content").val(),
password = $("#password").val();
formDataObj.append("header", header);
formDataObj.append("content", content);
formDataObj.append("password", password);
$.each($("#files")[0].files, function(i, file) {
formDataObj.append('file', file);
});
console.log(Array.from(formDataObj));
$("#uploadFilesSubmit").html("<div class='buttonSubmitIcon'><i class='fas fa-sync'></i></div>");
$.ajax({
method: "POST",
url: "uploadNews.php",
data: {
formDataObj: formDataObj
},
dataType: 'json',
contentType: false,
processData: false,
success: function(results){
}, error: function(){
}
});
});
In uploadNews.php I have this:
exit(json_encode(var_dump($_POST["header"])));
It always returns "Undefined index: header", same as content or count($_FILES["file"]["name"])
All I want is to get somehow to posted values.. Thank you very much
You just to pass the actual formDataObj variable via your $.ajax. This is not the correct syntax to pass FormData via ajax => formDataObj: formDataObj
A FormData itself is an object which stores your data so what you are doing is making another object on top of it when you pass it via data
You can now var_dump(header) or var_dump($_FILES["file"]["name"]) to see everything coming to your PHP file.
Live Demo: (Change you jQuery code to this below and it will just work fine)
$("#uploadFiles").submit(function(event) {
event.preventDefault();
var formDataObj = new FormData(),
header = $("#newsHeader").val(),
content = $("#content").val(),
password = $("#password").val();
formDataObj.append("header", header);
formDataObj.append("content", content);
formDataObj.append("password", password);
$.each($("#files")[0].files, function(i, file) {
formDataObj.append('file', file);
});
$("#uploadFilesSubmit").html("<div class='buttonSubmitIcon'><i class='fas fa-sync'></i></div>");
$.ajax({
method: "POST",
url: "uploadNews.php",
data: formDataObj, //just pass the form Data object.
dataType: 'json',
contentType: false,
processData: false,
success: function(results) {
},
error: function() {
}
});
});
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<form method="post" enctype="multipart/form-data" id="uploadFiles">
<label for="newsHeader" id="headerLabel">Nadpis</label>
<input type="text" name="newsHeader" id="newsHeader">
<label for="content" id="contentLabel">Text novinky</label>
<textarea name="content" id="content"></textarea>
<label for="files" id="filesLabel">Fotky</label>
<input type="file" name="files" id="files" accept="image/jpeg" multiple>
<label for="password" id="passwordLabel">Heslo pro upload</label>
<input type="text" name="password" id="password">
<button type='submit' id='uploadFilesSubmit'>NAHRÁT</button>
</form>
I have this problem that i cant seem to solve, for sure is a noob thing but here it goes, i'm trying to past values and upload file using the same form, but the file is not passing to the php function.
my html with ajax:
<form name="create_batch" method="post" role="form">
<input type="hidden" name="token" value="<?= \Middlewares\Csrf::get() ?>" required="required" />
<input type="hidden" name="request_type" value="create" />
<input type="hidden" name="project_id" value="<?= $data->project->project_id ?>" />
<input type="hidden" name="type" value="batch" />
<div class="notification-container"></div>
<div class="form-group">
<label><i class="fa fa-fw fa-signature fa-sm mr-1"></i> <?= $this->language->create_link_modal->input->location_url ?></label>
<input type="text" class="form-control" name="location_url" required="required" placeholder="<?= $this->language->create_link_modal->input->location_url_placeholder ?>" />
</div>
<div class="form-group">
<input type="file" name="file">
</div>
<div class="form-group">
<label><i class="fa fa-fw fa-link"></i> <?= $this->language->create_link_modal->input->url ?>
</label>
<input type="text" class="form-control" name="url" placeholder="<?= $this->language->create_link_modal->input->url_placeholder ?>" />
</div>
<div class="text-center mt-4">
<button type="submit" name="submit" class="btn btn-primary"><?= $this->language->create_link_modal->input->submit ?></button>
</div>
</form>
<script>
$('form[name="create_batch"]').on('submit', event => {
$.ajax({
type: 'POST',
url: 'link-ajax',
data: $(event.currentTarget).serialize(),
success: (data) => {
if(data.status == 'error') {
let notification_container = $(event.currentTarget).find('.notification-container');
notification_container.html('');
display_notifications(data.message, 'error', notification_container);
}
else if(data.status == 'success') {
/* Fade out refresh */
fade_out_redirect({ url: data.details.url, full: true });
}
},
dataType: 'json'
});
event.preventDefault();
})
</script>
this will post the data to the php file and the respective funtion, but only the fields are passing through. The file, that is a csv, is not passing. for sure i have something wrong on my ajax script that is only allow to pass the values of the form via post but not the file.
my php is something like this:
<?php
if(!empty($_FILES)){
$fh = fopen($_FILES['file']['tmp_name'], 'r+');
$i=0;
$lines = array();
while( ($row = fgetcsv($fh, 8192)) !== FALSE ) {
$lines[] = $row;
$location_url = $lines[$i][0];
$url = $lines[$i][1];
$umt_source = $lines[$i][2];
$utm_medium = $lines[$i][3];
$utm_campaign = $lines[$i][4];
$utm_term = $lines[$i][5];
$utm_content = $lines[$i][6];
$i=$i+1;
}
fclose($fh);
}
$_POST['project_id'] = (int) $_POST['project_id'];
$_POST['location_url'] = trim(Database::clean_string($_POST['location_url']));
$_POST['url'] = !empty($_POST['url']) ? get_slug(Database::clean_string($_POST['url'])) : false;
...........
Any help? Many thanks.
In order to send multipart form data, you need to create and send a form data object.
see example below -
var formdata = new FormData($('#formId')[0]);
$.ajax({
url: URL,
type: 'POST',
dataType: 'json',
async: false,
cache: false,
contentType: false,
processData: false,
data: formdata,
success: function (response) {
$('#responseMsg').html(response.msg);
}
});
On server end you can get your data by $_POST and files by $_FILES
the solution.
$("form#create_batch").submit(function(e) {
e.preventDefault();
var formData = new FormData(this);
$.ajax({
url: 'link-ajax',
type: 'POST',
data: formData,
dataType: 'json',
success: (data) => {
if(data.status == 'error') {
let notification_container = $(event.currentTarget).find('.notification-container');
notification_container.html('');
display_notifications(data.message, 'error', notification_container);
}
else if(data.status == 'success') {
/* Fade out refresh */
fade_out_redirect({ url: data.details.url, full: true });
}
},
cache: false,
contentType: false,
processData: false
});
});
I've built a simple form that posts data using jQuery AJAX to a PHP endpoint.
Everything works fine and the data is all being posted correctly.
The problem I am having is once the file is added to the input and submitted, the page refreshes. It doesn't refresh if I don't add the file, and doesn't refresh if I take the file input out altogether. Only when the file is successfully moved.
I need the page not to refresh, hence the use of AJAX in the first place.
Form:
<form id="form-send">
<div class="c-form-group grid-2">
<label for="first_name">First Name</label>
<input class="c-form-control" type="text" id="first_name" name="first_name" placeholder="Joe" value="Joe">
</div>
<div class="c-form-group grid-2">
<label for="file">Add File</label>
<input class="c-form-control c-form-control--file" type="file" id="file" name="file">
</div>
<div class="c-btn-group">
<button id="send" class="c-btn c-btn--primary" type="submit">Submit</button>
</div>
</form>
Ajax:
$("#form-send").on('submit', function(e){
e.preventDefault();
$.ajax({
type: "POST",
enctype: 'multipart/form-data',
url: '/send-form.php',
cache: false,
processData: false,
contentType: false,
data: new FormData(this),
success: function(data) {
console.log(data);
},
error: function(response) {
console.log('An error ocurred.');
},
});
})
Endpoint:
<?php
$uploadDir = 'uploads/';
// If post
if (isset($_POST)) {
// Request Values
$firstname = $_REQUEST['firstname'];
$file = $_REQUEST['file'];
// Upload to folder
if(!empty($_FILES["file"]["name"])){
// File path config
$fileName = basename($_FILES["file"]["name"]);
$targetFilePath = $uploadDir . $fileName;
$fileType = pathinfo($targetFilePath, PATHINFO_EXTENSION);
// Allow certain file formats
$allowTypes = array('pdf', 'doc', 'docx', 'jpg', 'png', 'jpeg');
if(in_array($fileType, $allowTypes)){
// Upload file to the server
if(move_uploaded_file($_FILES["file"]["tmp_name"], $targetFilePath)){
echo "Success: File uploaded.";
} else {
echo "Error: Something went wrong.";
}
} else{
echo "Error: File is not the correct format.";
}
}
}
?>
As the ajax call is asynchronous, you have to prevent the form from submitting, and then when a result is returned, you check if it matches the condition and submit the form with the native submit handler, avoiding the preventDefault() in the jQuery event handler :
$("#form-send").on('submit', function(e){
e.preventDefault();
$.ajax({
type: "POST",
enctype: 'multipart/form-data',
url: '/send-form.php',
cache: false,
processData: false,
contentType: false,
data: new FormData(this),
success: function(data) {
console.log(data);
},
error: function(response) {
console.log('An error ocurred.');
},
});
});
You can remove the form tag that is responsible for refreshing the page. Else, you can change button to
<button id="send" class="c-btn c-btn--primary" type="button">Submit</button>
This is how I am able to achieve in one of my projects.Hope it helps
AJAX CALL:
var form_data = new FormData();
form_data.append('title',title);
form_data.append('body',body);
form_data.append('link',link);
$.ajax
({
url: 'blog_insert.php',
dataType: 'text',
cache : false,
contentType : false,
processData : false,
data: form_data,
type: 'post',
success: function(php_script_response)
{
$("#success-message").css('display','active').fadeIn();
var title = $('#title').val(' ');
var body = $('.nicEdit-main').html('');
//$('#sortpicture').prop(' ')[0];
var link = $('#link').val('');
}
});
HTML
Blog posted successfully
<div class="form-group">
<label for="exampleFormControlInput1">Blog Title</label>
<input type="text" class="form-control" required="" name="title" id="title" placeholder="Enter your blog title">
</div>
<div class="form-group">
<label for="exampleFormControlTextarea1">Write your blog body here</label>
<textarea class="form-control" name="body" id="body" ></textarea>
</div>
<div id="dropzoneFrom" class="dropzone">
<div class="dz-default dz-message">Test Upload</div>
</div>
<div class="form-group">
<label for="exampleFormControlInput1">Reference Link</label>
<input type="text" class="form-control" id="link" name="link" placeholder="Post a reference link">
</div>
<button type="submit" id="submit-all" class="btn btn-primary" name="submit" >Post</button>