Clear all displayed records from mysql on page - php

Question

I have display.php page and all records from mysql are being displayed on this page with help of while loop. There is a search box on top, now i want when i search particular id in search box then all the displayed records should be hidden and only particular id record should be displayed on screen against which i am searching for.
i tried to hide the the div using jquery but only 1 record hide, but i want to hide all old recorrds
<?php
//all data is displaying through this code
while ($row=mysqli_fetch_assoc($n))
{
echo "<div>Student Name</div>";
echo "<div>".$row['studentName']."</div>";
}
if(isset($_POST['searchBtn']))
{
//here i want hide old data from page and then display searched data
$id=$_POST["stdID"];
$query = "SELECT * FROM std_table Where studentID='$id'" ;
$n=$connection->query($query);
if ($n->num_rows > 0)
{
while ($row=mysqli_fetch_assoc($n))
{
echo "<div>Student Name</div>";
echo "<div>".$row['studentName']."</div>";
}
}
?>
i tried to resolve this problem, but when I search id of specific data then a new row is created below the already displayed records, but i want clear the old data and want just display new data against the searched id

Answer 1

You are always printing all, and then you are asking if there is and id and printing. you want to use else for the print all part
<?php
if(isset($_POST['searchBtn']))
{
//here i want hide old data from page and then display searched data
$id=$_POST["stdID"];
$query = "SELECT * FROM std_table Where studentID='$id'" ;
$n=$connection->query($query);
if ($n->num_rows > 0)
{
while ($row=mysqli_fetch_assoc($n))
{
echo "<div>Student Name</div>";
echo "<div>".$row['studentName']."</div>";
}
}
}else{
//all data is displaying through this code
while ($row=mysqli_fetch_assoc($n)){
echo "<div>Student Name</div>";
echo "<div>".$row['studentName']."</div>";
}?>