Validate datetime input for scheduling - php

Question

I have a scheduling system school project,
I need to create a function that validates the date entered by the user,
check if it is 2 days ahead, not Sunday and it is between working hours.
Im using codeigniter framework.
//my controller looks like this:
public function checkDateTimeInput(){
$dateTimeInput = $this->input->post('dateTimeInput');
if($dateTimeInput /*Greater than 2 days or more*/ && /*not sunday*/ && /*between 8AM-5PM*/){
return true;
}else{
return false;
}
}
//in my view:
<?php echo form_open('schedules/checkDateTimeInput'); ?>
<input type="datetime-local" name="dateTimeInput">
<input type="submit" value="submit">
</form>

Answer 1

For completion's sake, I'm going to consider <input type="datetime-local" name="dateTimeInput"> as the input.
So this basically creates this format:
d/m/Y h:i A
I tried it on my browser (Chrome) and it does that. More info here also:
https://developer.mozilla.org/en-US/docs/Web/HTML/Element/input/datetime-local
So taking that into consideration, you can use createFromFormat to parse the input and use DateTime class.
$input = DateTimeImmutable::createFromFormat('d/m/Y h:i A', $dateTimeInput);
$dt = new DateTime; // now
if (
($input >= $input->setTime(8, 0) && $input <= $input->setTime(17, 0)) && // time is between 8 to 5
$input->format('l') !== 'Sunday' && // is not sunday
$dt->diff($input)->d >= 2 // is greater or more than two days
) {
return true;
}
return false;
Here's a sample output
Sidenote: I should also point out that type="datetime-local" is not supported in Firefox browser and should consider using a real date time plugin instead. If the user happens to use Firefox, you should prepare a fall back.

Answer 2

You can use below function and call it from your controller.
function checkDateConditions( $dateTimeInput ) {
//Make DateTime Object using the input
$inputDate = new DateTime( $dateTimeInput );
//Get the Hour from the Date Input
$inputHour = $inputDate->format('G');
//Check Time is between 8AM and 5PM ( 5PM is = 17)
if( $inputHour < 8 || $inputHour > 17) {
return false;
}
//This Returns 7 for Sunday
$dayOfWeek = $inputDate->format('N');
//If its Sunday we return false
if( $dayOfWeek == 7) {
return false;
}
//Calculate Date Difference
$now = new DateTime( Date('Y-m-d') );
$diff = $inputDate->diff($now);
//If date difference is greater than 2 days return false
if( $diff->days > 2 ) {
return false;
}
//If it reaches here it means all conditions are met so retrun true.
return true;
}