Give name to a function in a form - php

Question

I would like to name the function devtest() in the form as developer so when a user selects the developer it is submitted with the form.
The function I have is this and it is working, it returns the results when you select an item from the dropdown:
function devtest()
{
$db = db();
$stmt = $db->prepare('SELECT developer FROM developers');
$result = $stmt->execute();
?>
<select name="Developer">
<?php
while ($row = $result->fetchArray()) {
$dev = $row['developer'];
echo "<option value='" . $row['developer'] ."'>" . $row['developer'] ."</option>";
}
echo "</select>";
}
on the page itself where I call function and have the form I have
<form method="POST">
Enter game name:
<input type="text" name="name">
<br>
Enter Price
<input type="text" name="price">
<br>
Enter Platform
<input type="text" name="platform">
<br>
Select Developer
<!--<input type="text" name="developer">-->
<?php
devtest();
?>
<br>
Enter quantity
<input type="text" name="quantity">
<br>
Enter shipping
<input type="text" name="shipping">
<br>
<input type="submit" value="save">
</form>
That form goes to this function
function addgame()
{
#$devtest = devtest();
$db = db();
#function to add the form data from the add game page to the database
if(!empty($_POST['name']) && !empty($_POST['price']) && !empty($_POST['platform']) && !empty($_POST['quantity'])&& !empty($_POST['shipping'])){
$name = SQLite3::escapeString($_POST['name']);
$price = SQLite3::escapeString($_POST['price']);
$platform = SQLite3::escapeString($_POST['platform']);
$developer = SQLite3::escapeString($_POST['Developer']);
#$developer = devtest();
$quantity = SQLite3::escapeString($_POST['quantity']);
$shipping = SQLite3::escapeString($_POST['shipping']);
if (strlen($name) < 2)
{
echo("name be 2 char or longer");
}
if (!is_numeric($price))
{
echo("price must be numbers only");
}
if (strlen($platform) < 2)
{
echo("Platform must be 2 char or longer");
}
if (strlen($quantity) < 1)
{
echo("quantity must be more than 1");
}
/*if (strlen($shipping) < 9)
{
echo("shipping must be more than $9");
}*/
else
{
$stmt = $db->prepare("INSERT INTO game (name , price , platform , Developer, quantity, shipping) VALUES ('$name' , '$price' , '$platform' , '$developer', '$quantity' , '$shipping')");
$result = $stmt->execute();
}
}
else
{
echo "Fill in all form fields";
}
}
Without using the devtest() function in the form, and using the everything works fine, I am trying to change it so those on the list can be selected but I am not sure how to pass their select through the form.

Answer 1

you can send data to javascript and write your function in js to add a dropdown every where you need:
...
<script>
var developer = []
</script>
.
.
.
<php>
while ($row = $result->fetchArray()) {
?>
<script>
var developer[]=<?php echo $row['developer']; ?>
</script>
<?php
}
?>
js funtion:
<script>
function devtest(elementID){
developer.forEach(index,item){
$('#'+elementID).append('<select value="'+item+'">'+item+'</select>');
}
}
</script>
}