I have a MySQL table with headers "courseid", "world" and "name".
I am trying to populate an HTML dropdown box via a PHP loop and I can not get it to work.
<?php
$sql = "SELECT courseid, world, name FROM courses ORDER BY world DESC, name ASC";
$result = $link->query($sql);
if ($result->num_rows > 0) {
while($row = $result->fetch_assoc()) {
$world = '';
if ($world != $row['world']) {
echo '<option value="'.$row['courseid'].'">'.$row['name'].'</option>';
}else{
echo '<optgroup label="'.$row['world'].'">';
}
}
echo '</select>';
} else {
echo "0 results";
}
$link->close();
?>
I would like it to loop through the whole table and display as follows:
<optgroup label"world1">
<option value="courseid1">name1</option>
<option value="courseid2">name2</option>
<option value="courseid3">name3</option>
</optgroup>
<optgroup label"world2">
<option value="courseid4">name1</option>
<option value="courseid5">name2</option>
<option value="courseid6">name3</option>
</optgroup>
(courseid, world and name are values from the table)
A couple of issues. Firstly, you need to move $world = ''; before your while loop, otherwise it will cause the if test to always be true. Secondly, the if test should only be used to test whether to finish an old and start a new optgroup, not to decide whether to output an option. This should work:
if ($result->num_rows > 0) {
echo '<select>';
$world = '';
while($row = $result->fetch_assoc()) {
if ($world != $row['world']) {
if ($world != '') echo '</optgroup>';
echo '<optgroup label="'.$row['world'].'">';
$world = $row['world'];
}
echo '<option value="'.$row['courseid'].'">'.$row['name'].'</option>';
}
echo '</optgroup></select>';
}
else {
echo "0 results";
}
Related
I am struggling to get this code to work, what I want from it is to show the item (that is already in the database) to be selected in the selection form.
<label>Server Ports:</label>
<select multiple class="form-control" name="select[]">
<?php
// Get Server Information
$query = "SELECT port_no FROM _servers WHERE (server_id = '$servid') ";
$result = mysql_query($query) or die ('Unable to run query:'.mysql_error());
while($row = mysql_fetch_assoc($result)){
$no = $row['port_no'];
}
$query = "SELECT id, name, port_no, unique_id FROM ports ORDER BY name ASC";
$result = mysql_query($query) or die ('Unable to run query:'.mysql_error());
while($row = mysql_fetch_assoc($result))
{
$port_no = $row['port_no'];
$port_name = $row['name'];
$p_unique = $row['unique_id'];
}
?>
<option value="<?php echo $p_unique;?>"
<?php
if ($p_unique == $no) {
$check = 'selected';
} else {
$check = '';
}
echo $check;
?>
>
<?php
echo $row['name'];
?>
(
<?php
echo $row['port_no'];
?>
)</option>
<?php
}
?>
</select>
Are you sure your test must be if ($p_unique == $no) {} and not if ($port_no == $no) {} ?
If yes, try to checks your variables values :
Do a var_dump() of $no :
var_dump($no);
In your while() loop, you can also check values of $p_unique and $no like that :
var_dump($p_unique.'/'.$no);
Also, here is a simplest way to test for selected :
<option value="<?php echo $p_unique;?>" <?php if ($p_unique == $no) echo 'selected="selected"'; ?>><?php echo $row['name'] ;?> (<?php echo $row['port_no'] ;?>)</option>
My textboxes get autocomplete populated from mysql tables.
I want to display the output list from the textbox into a selectable option instead of an list item.
echo '<li onClick="fill(\''.$result->naam_klant.'\');">'.$result->naam_klant.'</li>';
My code so far:
'<select onClick="fill(\''.$result->naam_klant.'\');"><option value=$result->naam_klant></option></select>';
Can you guys help me with this ?
UPDATE
if(isset($_POST['queryString'])) {
$queryString = $db->real_escape_string($_POST['queryString']);
// Is the string length greater than 0?
if(strlen($queryString) >0) {
$query = $db->query("SELECT naam_klant FROM overboekingen WHERE naam_klant LIKE '$queryString%' LIMIT 10");
if($query) {
while ($result = $query ->fetch_object()) {
echo '<li onClick="fill(\''.$result->naam_klant.'\');">'.$result->naam_klant.'</li>';
'<select onClick="fill(\''.$result->naam_klant.'\');"><option value=$result->naam_klant></option></select>';
}
} else {
echo 'ERROR: There was a problem with the query.';
}
} else {
} // There is a queryString.
} else {
echo 'There should be no direct access to this naam_klant script!';
}
}
?>
You don't give enough information, how you is your results structured?
<select onchange="fill(this.value);" onfocus="this.selectedIndex = -1;">
<?
for ($i=0; $i < count(results); $i++) {
$result = results[i];
echo "<option value='{$result->naam_klant}'>option {$result->naam_klant}</option>\r\n";
}
?>
</select>
Update
Since you want a selectable option instead of an list item
if ($query) {
echo '<select onchange="fill(this.value);" onfocus="this.selectedIndex = -1;">\r\n';
while ($result = $query->fetch_object()) {
echo '<option value={$result->naam_klant}>{$result->naam_klant}</option>\r\n';
}
echo '</select>\r\n';
}
<div class="select_list">
<div class="labels">Category:</div>
<?php
if(!isset($_POST['postbtn)){
echo "<script>$(document).ready(function(){
$('.category').val(0);
})
</script>";
}
echo "<select name='category' id='catg_list' class='list_catg'>
<option value='0'";
if(isset($_POST['category']) && $_POST['category']=='0'){
echo "selected";
}
echo">none</option>";
$query = mysql_query("SELECT id, name from table1");
while($query_fetch = mysql_fetch_assoc($query)){
echo "<option value='".$query_fetch['id']."'";
if(isset($_POST['category']) && $_POST['category']==$query_fetch['id'])
{
echo "selected";
}
echo ">".$query_fetch['name']."</option>";
}
echo "</select>";
?>
</div>
The problem with the above code is that the selected element stays selected after the submission is done. I need the select option to return back to 'none' when the form is submitted successfully. How can that be done?
You have an syntax error in your line:
if(!isset($_POST['postbtn)){
change it to:
if(!isset($_POST['postbtn'])){
I'm guessing some things you didn't mention:
You validate your script above the code you posted, and you want - if the script was validated successfully - that the "none" option is selected.
$selected_value = $validation ? $_POST['category'] : false;
Only if the Validation is correct the value will be set, else it will be set to false;
<?php
echo "<select name='category' id='catg_list' class='list_catg'>
<option value='0'";
//CHANGE
if($selected_value == 0){ //Or if($selected_value === FALSE ||$selected_value === 0)
echo "selected";
}
echo">none</option>";
$query = mysql_query("SELECT id, name from table1");
while($query_fetch = mysql_fetch_assoc($query)){
echo "<option value='".$query_fetch['id']."'";
//CHANGE
if($selected_value !== FALSE && $selected_value == $query_fetch['id'])
{
echo "selected";
}
echo ">".$query_fetch['name']."</option>";
}
echo "</select>";
?>
Simplify your code as following to do required task.
$category = isset($_POST['category']) ? $_POST['category'] : 0;
$array["0"]="none";
$query = mysql_query("SELECT id, name from table1");
while($query_fetch = mysql_fetch_assoc($query)){
$id = $query_fetch['id'];
$array[$id] = $query_fetch['name'];
}
echo "<select name='category' id='catg_list' class='list_catg'>";
foreach($array as $id=>$name) {
$selected = $category==$id ? "selected" : "";
echo "<option value='".$id."' ".$selected." >".$name."</option>";
}
echo "</select>";
<select name="corequisite">
<option value="" selected="selected">No Corequisite</option>';
$res = mysql_query("SELECT * FROM course");
while($row = mysql_fetch_array($res)){
echo'<option value="'.$row['Code'].'"';if($row['Code']==$result['corequisite']) echo'
selected="selected"';;echo'>'.$row['Name'].'</option>';
}
echo'</select>';
I want the 'No Corequisite' value to be selected if no other options will be match with $result['corequisite']. But the first item in the table will be selected!
How can I fix it?
It may be fixed by inserting 'corequisite' as the first record. A good way?
Answering your last question, probably a bad way.
Try this code, currently on the laptop so haven't tested it.
<select name="corequisite">
<?php
$res = mysql_query("SELECT * FROM course");
$rows = mysql_num_rows($res);
if ($rows == 0)
{
$sel = 'selected';
} else
{
$sel = '';
}
echo '<option '.$sel.' value="">No Corequisite</option>';
while($row = mysql_fetch_array($res))
{
$sel = '';
if ($row['Code'] == $result['corequisite'])
{
$sel = 'selected';
}
echo '<option '.$sel.' value="'.$row['Code'].'">' . $row['Name'] . '</option>';
}
?>
</select>
I haven't tested it, but this should work
<select name="corequisite">
<?php
// this is your string that will return all your results
$to_echo = '';
// this will check if any value inside is selected ( this will be useful later )
$any_item_selected = false;
$res = mysql_query("SELECT * FROM course");
while($row = mysql_fetch_array($res))
{
if($row['Code']==$result['corequisite']) // OK! so one item is selected, remember it!
{
$to_echo .= '<option selected="selected" value="'.$row['Code'].'">'.$row['Name'].'</option>';
$any_item_selected = true;
}
else
$to_echo .= '<option value="'.$row['Code'].'">'.$row['Name'].'</option>';
}
// Now we can check if anything were selected, and prepend the "No corequisite" option, selected or not! :)
if( ! $any_item_selected)
$to_echo = '<option value="" selected="selected">No Corequisite</option>' . $to_echo;
else
$to_echo = '<option value="">No Corequisite</option>' . $to_echo;
echo $to_echo;
?>
</select>
If in the browser I have parameters like:
http://localhost/specials.php?year=2009&make=honda&model=civic
and the dropdown looks something like this:
<select name="year">
<?php
$query = mysql_query("select distinct year from tbl_content where year = '$year'");
while($row = mysql_fetch_assoc($query)) {
echo "<option value=\"{$row['year']}\">{$row['year']}</option>";
}
?>
</select>
Now what I'm trying to do is show select when the dropdown options value is equal to the parameter year in the browser URL.
I tried this:
<select name="year">
<?php
$query = mysql_query("select * from tbl_year
while($row = mysql_fetch_assoc($query)) {
#=============================
if(isset($_GET['year'])) {
$year = (int)$_GET['year'];
if($year == $row['year'] { $selected = "selected"; }
else { $selected = "";
}
echo "<option value=\"{$row['year']}\" {$selected}>{$row['year']}</option>";
}
?>
</select>
Maybe try "selected='selected'" to make it valid xml.
<select name="year">
<?php
$selectedYear = NULL;
if(isset($_GET['year']))
$selectedYear = (int)$_GET['year'];
$query = mysql_query('SELECT year FROM tbl_year GROUP BY year ORDER BY year ASC');
while($row = mysql_fetch_assoc($query)) {
echo '<option value="' . htmlspecialchars($row['year']) . '"';
if($selectedYear === (int)$row['year']) {
echo ' selected="selected"';
}
echo '>' . htmlspecialchars($row['year']) . '</option>";
}
?>
</select>
Fell free to separate functionality!
<?php
function selectList($name,$values,$labels=null,$selected=null){
if($labels==null) $labels=&$values;
$data="<select name='$name'>";
foreach($values as $k=>$v){
$selected=($v==$selected)?'selected="selected"':false;
$data.="<option value='$v' $selected>".htmlspecialchars($labels[$k])."</option>";
}
$data.="</select>";
return $data;
}
$select=isset($_REQUEST['year'])?(int) $_REQUEST['year']:null;
$query=mysql_query("SELECT DISTINCT `year` FROM `tbl_year` ORDER BY `year`");
while(($row=mysql_fetch_assoc($query))!==false){
$values[]=$row['year'];
}
echo selectList("year",$values,null,$select);
?>