I started by googling and found the article How to write INSERT if NOT EXISTS queries in standard SQL which talks about mutex tables.
I have a table with ~14 million records. If I want to add more data in the same format, is there a way to ensure the record I want to insert does not already exist without using a pair of queries (i.e., one query to check and one to insert is the result set is empty)?
Does a unique constraint on a field guarantee the insert will fail if it's already there?
It seems that with merely a constraint, when I issue the insert via PHP, the script croaks.
Use INSERT IGNORE INTO table.
There's also INSERT … ON DUPLICATE KEY UPDATE syntax, and you can find explanations in 13.2.6.2 INSERT ... ON DUPLICATE KEY UPDATE Statement.
Post from bogdan.org.ua according to Google's webcache:
18th October 2007
To start: as of the latest MySQL, syntax presented in the title is not
possible. But there are several very easy ways to accomplish what is
expected using existing functionality.
There are 3 possible solutions: using INSERT IGNORE, REPLACE, or
INSERT … ON DUPLICATE KEY UPDATE.
Imagine we have a table:
CREATE TABLE `transcripts` (
`ensembl_transcript_id` varchar(20) NOT NULL,
`transcript_chrom_start` int(10) unsigned NOT NULL,
`transcript_chrom_end` int(10) unsigned NOT NULL,
PRIMARY KEY (`ensembl_transcript_id`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1;
Now imagine that we have an automatic pipeline importing transcripts
meta-data from Ensembl, and that due to various reasons the pipeline
might be broken at any step of execution. Thus, we need to ensure two
things:
repeated executions of the pipeline will not destroy our
> database
repeated executions will not die due to ‘duplicate
> primary key’ errors.
Method 1: using REPLACE
It’s very simple:
REPLACE INTO `transcripts`
SET `ensembl_transcript_id` = 'ENSORGT00000000001',
`transcript_chrom_start` = 12345,
`transcript_chrom_end` = 12678;
If the record exists, it will be overwritten; if it does not yet
exist, it will be created. However, using this method isn’t efficient
for our case: we do not need to overwrite existing records, it’s fine
just to skip them.
Method 2: using INSERT IGNORE Also very simple:
INSERT IGNORE INTO `transcripts`
SET `ensembl_transcript_id` = 'ENSORGT00000000001',
`transcript_chrom_start` = 12345,
`transcript_chrom_end` = 12678;
Here, if the ‘ensembl_transcript_id’ is already present in the
database, it will be silently skipped (ignored). (To be more precise,
here’s a quote from MySQL reference manual: “If you use the IGNORE
keyword, errors that occur while executing the INSERT statement are
treated as warnings instead. For example, without IGNORE, a row that
duplicates an existing UNIQUE index or PRIMARY KEY value in the table
causes a duplicate-key error and the statement is aborted.”.) If the
record doesn’t yet exist, it will be created.
This second method has several potential weaknesses, including
non-abortion of the query in case any other problem occurs (see the
manual). Thus it should be used if previously tested without the
IGNORE keyword.
Method 3: using INSERT … ON DUPLICATE KEY UPDATE:
Third option is to use INSERT … ON DUPLICATE KEY UPDATE
syntax, and in the UPDATE part just do nothing do some meaningless
(empty) operation, like calculating 0+0 (Geoffray suggests doing the
id=id assignment for the MySQL optimization engine to ignore this
operation). Advantage of this method is that it only ignores duplicate
key events, and still aborts on other errors.
As a final notice: this post was inspired by Xaprb. I’d also advise to
consult his other post on writing flexible SQL queries.
Solution:
INSERT INTO `table` (`value1`, `value2`)
SELECT 'stuff for value1', 'stuff for value2' FROM DUAL
WHERE NOT EXISTS (SELECT * FROM `table`
WHERE `value1`='stuff for value1' AND `value2`='stuff for value2' LIMIT 1)
Explanation:
The innermost query
SELECT * FROM `table`
WHERE `value1`='stuff for value1' AND `value2`='stuff for value2' LIMIT 1
used as the WHERE NOT EXISTS-condition detects if there already exists a row with the data to be inserted. After one row of this kind is found, the query may stop, hence the LIMIT 1 (micro-optimization, may be omitted).
The intermediate query
SELECT 'stuff for value1', 'stuff for value2' FROM DUAL
represents the values to be inserted. DUAL refers to a special one row, one column table present by default in all Oracle databases (see https://en.wikipedia.org/wiki/DUAL_table). On a MySQL-Server version 5.7.26 I got a valid query when omitting FROM DUAL, but older versions (like 5.5.60) seem to require the FROM information. By using WHERE NOT EXISTS the intermediate query returns an empty result set if the innermost query found matching data.
The outer query
INSERT INTO `table` (`value1`, `value2`)
inserts the data, if any is returned by the intermediate query.
In MySQL, ON DUPLICATE KEY UPDATE or INSERT IGNORE can be viable solutions.
An example of ON DUPLICATE KEY UPDATE update based on mysql.com:
INSERT INTO table (a,b,c) VALUES (1,2,3)
ON DUPLICATE KEY UPDATE c=c+1;
UPDATE table SET c=c+1 WHERE a=1;
An example of INSERT IGNORE based on mysql.com
INSERT [LOW_PRIORITY | DELAYED | HIGH_PRIORITY] [IGNORE]
[INTO] tbl_name [(col_name,...)]
{VALUES | VALUE} ({expr | DEFAULT},...),(...),...
[ ON DUPLICATE KEY UPDATE
col_name=expr
[, col_name=expr] ... ]
Or:
INSERT [LOW_PRIORITY | DELAYED | HIGH_PRIORITY] [IGNORE]
[INTO] tbl_name
SET col_name={expr | DEFAULT}, ...
[ ON DUPLICATE KEY UPDATE
col_name=expr
[, col_name=expr] ... ]
Or:
INSERT [LOW_PRIORITY | HIGH_PRIORITY] [IGNORE]
[INTO] tbl_name [(col_name,...)]
SELECT ...
[ ON DUPLICATE KEY UPDATE
col_name=expr
[, col_name=expr] ... ]
Any simple constraint should do the job, if an exception is acceptable. Examples:
primary key if not surrogate
unique constraint on a column
multi-column unique constraint
Sorry if this seems deceptively simple. I know it looks bad confronted to the link you share with us. ;-(
But I nevertheless give this answer, because it seems to fill your need. (If not, it may trigger you updating your requirements, which would be "a Good Thing"(TM) also).
If an insert would break the database unique constraint, an exception is throw at the database level, relayed by the driver. It will certainly stop your script, with a failure. It must be possible in PHP to address that case...
Try the following:
IF (SELECT COUNT(*) FROM beta WHERE name = 'John' > 0)
UPDATE alfa SET c1=(SELECT id FROM beta WHERE name = 'John')
ELSE
BEGIN
INSERT INTO beta (name) VALUES ('John')
INSERT INTO alfa (c1) VALUES (LAST_INSERT_ID())
END
REPLACE INTO `transcripts`
SET `ensembl_transcript_id` = 'ENSORGT00000000001',
`transcript_chrom_start` = 12345,
`transcript_chrom_end` = 12678;
If the record exists, it will be overwritten; if it does not yet exist, it will be created.
Here is a PHP function that will insert a row only if all the specified columns values don't already exist in the table.
If one of the columns differ, the row will be added.
If the table is empty, the row will be added.
If a row exists where all the specified columns have the specified values, the row won't be added.
function insert_unique($table, $vars)
{
if (count($vars)) {
$table = mysql_real_escape_string($table);
$vars = array_map('mysql_real_escape_string', $vars);
$req = "INSERT INTO `$table` (`". join('`, `', array_keys($vars)) ."`) ";
$req .= "SELECT '". join("', '", $vars) ."' FROM DUAL ";
$req .= "WHERE NOT EXISTS (SELECT 1 FROM `$table` WHERE ";
foreach ($vars AS $col => $val)
$req .= "`$col`='$val' AND ";
$req = substr($req, 0, -5) . ") LIMIT 1";
$res = mysql_query($req) OR die();
return mysql_insert_id();
}
return False;
}
Example usage:
<?php
insert_unique('mytable', array(
'mycolumn1' => 'myvalue1',
'mycolumn2' => 'myvalue2',
'mycolumn3' => 'myvalue3'
)
);
?>
There are several answers that cover how to solve this if you have a UNIQUE index that you can check against with ON DUPLICATE KEY or INSERT IGNORE. That is not always the case, and as UNIQUE has a length constraint (1000 bytes) you might not be able to change that. For example, I had to work with metadata in WordPress (wp_postmeta).
I finally solved it with two queries:
UPDATE wp_postmeta SET meta_value = ? WHERE meta_key = ? AND post_id = ?;
INSERT INTO wp_postmeta (post_id, meta_key, meta_value) SELECT DISTINCT ?, ?, ? FROM wp_postmeta WHERE NOT EXISTS(SELECT * FROM wp_postmeta WHERE meta_key = ? AND post_id = ?);
Query 1 is a regular UPDATE query without any effect when the data set in question is not there. Query 2 is an INSERT which depends on a NOT EXISTS, i.e. the INSERT is only executed when the data set doesn't exist.
Something worth noting is that INSERT IGNORE will still increment the primary key whether the statement was a success or not just like a normal INSERT would.
This will cause gaps in your primary keys that might make a programmer mentally unstable. Or if your application is poorly designed and depends on perfect incremental primary keys, it might become a headache.
Look into innodb_autoinc_lock_mode = 0 (server setting, and comes with a slight performance hit), or use a SELECT first to make sure your query will not fail (which also comes with a performance hit and extra code).
Update or insert without known primary key
If you already have a unique or primary key, the other answers with either INSERT INTO ... ON DUPLICATE KEY UPDATE ... or REPLACE INTO ... should work fine (note that replace into deletes if exists and then inserts - thus does not partially update existing values).
But if you have the values for some_column_id and some_type, the combination of which are known to be unique. And you want to update some_value if exists, or insert if not exists. And you want to do it in just one query (to avoid using a transaction). This might be a solution:
INSERT INTO my_table (id, some_column_id, some_type, some_value)
SELECT t.id, t.some_column_id, t.some_type, t.some_value
FROM (
SELECT id, some_column_id, some_type, some_value
FROM my_table
WHERE some_column_id = ? AND some_type = ?
UNION ALL
SELECT s.id, s.some_column_id, s.some_type, s.some_value
FROM (SELECT NULL AS id, ? AS some_column_id, ? AS some_type, ? AS some_value) AS s
) AS t
LIMIT 1
ON DUPLICATE KEY UPDATE
some_value = ?
Basically, the query executes this way (less complicated than it may look):
Select an existing row via the WHERE clause match.
Union that result with a potential new row (table s), where the column values are explicitly given (s.id is NULL, so it will generate a new auto-increment identifier).
If an existing row is found, then the potential new row from table s is discarded (due to LIMIT 1 on table t), and it will always trigger an ON DUPLICATE KEY which will UPDATE the some_value column.
If an existing row is not found, then the potential new row is inserted (as given by table s).
Note: Every table in a relational database should have at least a primary auto-increment id column. If you don't have this, add it, even when you don't need it at first sight. It is definitely needed for this "trick".
INSERT INTO table_name (columns) VALUES (values) ON CONFLICT (id) DO NOTHING;
I want to perform a mysql UPDATE query and then get an array of ids that were effected in the change.
This is my update query
mysql_query("UPDATE table SET deleted='1' WHERE id='$id' OR foo='$foo' OR bar='$bar'");
I know that I can do something like this to get the created id from an INSERT query
mysql_query("INSERT INTO table (id,foo,bar) VALUES ('$id','$foo','$bar')");
$newid = mysql_insert_id();
I don't think MySQL has anything like the OUTPUT or RETURNING clauses that other databases support. You can get the list of ids by running a select before the update:
create table temp_table ids_to_update as
SELECT id
FROM table
WHERE (deleted <> '1' or deleted is null) and *id='$id' OR foo='$foo' OR bar='$bar');
Note that MySQL doesn't do an update when the value doesn't change. Hence the first condition -- which you may or may not find important.
Then, to ensure integrity (in the event of intervening transactions that change the data), you can do:
update table t join
temp_table tt
on t.id = tt.id
set deleted = '1';
You could also wrap the two queries in a single transaction, but I think using a temp table to store the ids is probably easier.
Here is my query part of my registration PHP form.
columns account,password,email and age could be inserted by registration page user and they work well but, the column account_id needs to be increased by 1 automatically with each registration process.
Table name is Account not account and column name is account_id.
$query = "INSERT Account( account,password,email,pk_,type_ ) VALUES('$username','$converted_password','$email',1,'$age')";
$query_total = mssql_query("SELECT COUNT(account_id) FROM Account");
$results_check = mssql_query($query_check);
$results_total = mssql_fetch_row($query_total);
$result_total = $results_total['0'];
It gives me a NULL value for the (account_id) column and INSERT fails.
Perform the following query on your database: (Mysql based query!! not Mssql!!)
ALTER TABLE `Account` CHANGE `account_id` `account_id` int(11) UNSIGNED NOT NULL AUTO_INCREMENT PRIMARY KEY;
this wil result in an autoincrement.
If this fails you'll probably already own duplicates, you'd have to solve this first. There are many ways for this, though it mostly depends upon connections with other tables.
After that for each insert into account do not include the account_id.
use the mysql query:
select LAST_INSERT_ID();
to retrieve the last inserted id.
within PHP you can use http://nl1.php.net/mysql_insert_id though i'd highly advice you to start looking into http://www.php.net/PDO or http://www.php.net/mysqli with prepared statements.
Because as far as i've understood in the next version of PHP the basic Mysql functions will become deprecated. And prepared statements are better/safer. (If properly used)
Set account_id to auto increment in MySQL and just don't shoot anything to the MySQL database for the field account_id. MySQL will automatically create a new ID.
Read something about auto increment:
http://dev.mysql.com/doc/refman/5.0/en/example-auto-increment.html
*edit:
Also change
$query = "INSERT Account( account,password,email,pk_,type_ ) VALUES('$username','$converted_password','$email',1,'$age')";
to
$query = "INSERT INTO Account(account,password,email,pk_,type_) VALUES('$username','$converted_password','$email',1,'$age')";
Problem
I have a webpage that does the following (the code is much simplified to show only relevant code.
mysql_query("insert into table1 (field1) values ('value')");
$last_id = mysql_insert_id();
$result = mysql_query("select * from table1 t inner join ... where id = $last_id");
write_a_file_using_result($result);
It happened, that the file was created using a different data set than what I found in the table row.
The only explanation I have is:
call1: page was called 1. time with data set 1.
call1: data set 1 gets inserted for connection 1 but gets not committed to the table.
call2: page was called 2. time with data set 2
call2: data set 2 gets inserted for connection 2 and mysql_insert_id returns the same value
call1: file is generated with date set 1
call2: file cannot be written, because it already exists
Result: The file is generated with data set 1 while the table row contains data row 2.
Config
mysql 5.0.51b
The table:
CREATE TABLE `table1` (
`id` int(11) NOT NULL auto_increment,
(...)
Question
I know that MyISAM does not support transactions. But I really expect that it is impossible to insert two rows and get twice the same id inserted, so that the row can be overwritten.
Is MyISAM unsafe to this point or is there another explanation that I overlook ?
Note
I know the mysql extension for php is outdated, but I did not yet rewrite the application.
Is MyISAM unsafe to this point
No. mysql_insert_id guaranteed to return the right value only.
or is there another explanation that I overlook ?
Most likely. Check your code.
Haven't heard about id issues in MyISAM.
You can try to set link identifier when calling last_insert_id, for example
$link = mysql_connect(...);
mysql_query("insert into table1 (field1) values ('value')",$link);
$last_id = mysql_insert_id($link);
$result = mysql_query("select * from table1 t inner join ... where id = $last_id",$link);
write_a_file_using_result($result);
I have a simple table made up of two columns: col_A and col_B.
The primary key is defined over both.
I need to update some rows and assign to col_A values that may generate duplicates, for example:
UPDATE `table` SET `col_A` = 66 WHERE `col_A` = 70
This statement sometimes yields a duplicate key error.
I don't want to simply ignore the error with UPDATE IGNORE, because then the rows that generate the error would remain unchanged. Instead, I want them to be deleted when they would conflict with another row after they have been updated
I'd like to write something like:
UPDATE `table` SET `col_A` = 66 WHERE `col_A` = 70 ON DUPLICATE KEY REPLACE
which unfortunately isn't legal in SQL, so I need help finding another way around.
Also, I'm using PHP and could consider a hybrid solution (i.e. part query part php code), but keep in mind that I have to perform this updating operation many millions of times.
thanks for your attention,
Silvio
Reminder: UPDATE's syntax has problems with joins with the same table that is being updated
EDIT: sorry, the column name in the WHERE clause was wrong, now I fixed it
Answer to revised question:
DELETE FROM
table_A
USING
table AS table_A
JOIN table AS table_B ON
table_A.col_B = table_B.col_B AND
table_B.col_A = 70
WHERE
table_A.col_A = 66
This gets rid of the rows that would cause problems. Then you issue your UPDATE query. Ideally you will do it all inside a transaction to avoid a situation where troublesome rows are re-inserted in between the two queries.
Are there any foreign keys referencing this table? If not then the following should do:
CREATE PROCEDURE `MyProcedure` (IN invarA INT, IN invarB INT)
LANGUAGE SQL
NOT DETERMINISTIC
MODIFIES SQL DATA
SQL SECURITY DEFINER
BEGIN
DELETE FROM table WHERE col_B = invarB;
IF ROW_COUNT() > 0 THEN
INSERT INTO table (`col_A`, `col_B`) VALUES (invarA, invarB);
END IF;
END
Example call:
CALL `MyProcedure`(66, 70)