PHP how to pass a variable inside a class - php

Question

I have tried the solutions indicated here on stackoverflow, the code below uses one of them, recommended and voted as the right way to do it, but it doesn't work for me, why?
In fact the href results empty.
<?php
//URLS LIST
$nameA = 'http://www.example.com';
$nameB = 'http://www.example.com';
$nameC = 'http://www.example.com';
class bannClass {
private $class_varA;
private $class_varB;
private $class_varC;
public $username = '';
public function __construct($nameA, $nameB, $nameC) {
$this->class_varA = $nameA;
$this->class_varB = $nameB;
$this->class_varC = $nameC;
}
public function check_userOne() {
$url = 'https://example.com/wp-content/uploads/sponsor/' . $this->username . '/sponsor1.jpg';
return '<img src="' . $url . '" alt="Sponsor"/>';
}
public function check_userTwo() {
$url = 'https://example.com/wp-content/uploads/sponsor/' . $this->username . '/sponsor2.jpg';
return '<img src="' . $url . '" alt="Sponsor"/>';
}
public function check_userThree() {
$url = 'https://example.com/wp-content/uploads/sponsor/' . $this->username . '/sponsor3.jpg';
return '<img src="' . $url . '" alt="Sponsor"/>';
}
}
Also how can i make those 3 variables at the top dynamic in php? instead of "name" something like $($this->username . 'A') , $($this->username . 'B') , etc.
EDIT: the above class is being instantiated in another php file like so:
<?php
require_once('myclass.php');
$bannClass = new bannClass();
$bannClass->username = $data['username'];
//etc.
and used like:
<?php echo $bannClass->check_userOne();?>

Answer 1

As it is written, you must inject 3 values when it is instantiated. If you have error reporting turned on in your development environment (and you really should), it would have complained when you instantiated it as $bannClass = new bannClass();
This is how this object should be instantiated:
$nameA = 'http://www.example.com';
$nameB = 'http://www.example.com';
$nameC = 'http://www.example.com';
$bannClass = new bannClass($nameA, $nameB, $nameC);
I would make a few suggestions:
Don’t mix logic and presentation. A good rule of thumb to follow is no html outside of the view. Objects are generally for logic, not formatting html. Leave html for helper functions and the “view” portion of the script (which should be the very last thing that happens)
Keep it DRY (don’t repeat yourself). If you have methods doing the same thing, it’s time to refactor. Pass in a variable or an array for the method to work with.
—-
Further ideas relating to your comment:
The collection of the urls would typically be the job of an object. (Look into the PDO object. Helpful reference )
In all my projects, I use an object (named Database) to wrap around php’s db access, similar to pdo. It includes the following 3 methods (code is omitted for brevity):
public function prepare(string $query) { ... }
public function execute(array $params) { ... }
public function nextRecord() {...}
In a procedural script, you would first do whatever initialization is needed, deal with any user input using the PRG pattern, and any other logic. Then you would output the html, using php only to loop and insert variables. In OOP terms, this roughly corresponds to the MVC pattern (which is well worth learning).
So, for the example, let’s say that we have a database of urls:
ID URL Image
1 foo.com Image1.com
2 bar.com Image2.com
3 baz.com Image3.com
A procedural script could go as follows:
<?php
require(‘database.php’);
// optionally deal with user input
$url = new Database; // example is assuming connection is handled in the object
$url->prepare(“select url, image from sometable”);
$url->execute();
// all logic is complete; now give the output
?>
<!— html stuff —>
<ul>
<?php while($row=$url->nextRecord() ): ?>
<li><img src="<?= $row->image ?>" alt="Sponsor"/></li>
<?php endwhile; ?>
</ul>
Admittedly, I haven’t explained my object; space does not permit. But this should give you an overview of what’s possible and how to display 150 urls without repeating yourself.

Answer 2

Just to add to excellent answer by Tim Morton: Let's suppose, that the three links are almost always the same, then you can do something like this:
class bannClass {
private $class_varA = 'https://example.com';
private $class_varB = 'https://example.com';
private $class_varC = 'https://example.com';
public $username = '';
public function __construct($nameA = null, $nameB = null, $nameC = null) {
if (!empty($nameA)) $this->class_varA = $nameA;
if (!empty($nameB)) $this->class_varB = $nameB;
if (!empty($nameC)) $this->class_varC = $nameC;
}
public function getVarA(){
return $this->class_varA;
}
public function getVarB(){
return $this->class_varB;
}
public function getVarC(){
return $this->class_varC;
}
}
What above does, that if the class is not called with any parameters = $foo = new bannClass(); it will default all three URLs to what was set as default. Obviously, you should arrange the variables in such manner, that first is possibly changed the most time:
$bar = new bannClass('https://stackoverflow.com');
echo $bar->getVarA(); // returns stackoverflow.com
echo $bar->getVarC(); // returns example.com
Because changing only third parameter looks kinda stupid:
$baz = new bannClass(null,null,'https://stackoverflow.com');
cho $baz->getVarA(); // returns example.com
echo $baz->getVarC(); // returns stackoverflow.com