we have two table for example persons1 and persons2 and out put should be rows of those tables
for exemple:
`persons1`
+----+-------------+
| id | name |
+----+-------------+
| 1 | john |
| 2 | Sophia |
+----+-------------+
and
`persons2`
+----+-------------+
| id | the_name |
+----+-------------+
| 1 | Olivia |
| 2 | Jackson |
+----+-------------+
Output is :
array(
[1,'john'],
[2,'Sophia'],
[1,'Olivia'],
[2,'Jackson'],
)
thank you
You can use union like this:
SELECT id, name as `the_name` FROM `persons1`
UNION
SELECT id, the_name FROM `persons2`;
which outputs:
| id | the_name |
|----| ---------|
| 1 | John |
| 2 | Sophia |
| 1 | Olivia |
| 2 | Jackson |
SqlFiddle
SELECT p1.id, p1.name AS `the_name` FROM persons1 p1
UNION
SELECT p2.id, p2.the_name FROM persons2 p2;
Related
I have 3 tables:
table_1:
| id | test |total_employee|
+----+------+--------------+
| 1 | xxxx | 3 |
| 2 | yyyy | 2 |
| 3 | zzzz | 3 |
----------------------------
table_2:
| id | id_table1 |id_employee|
+----+-----------+-----------+
| 1 | 1 | 1 |
| 2 | 1 | 2 |
| 3 | 1 | 3 |
| 4 | 1 | 1 |
| 5 | 1 | 2 |
| 6 | 1 | 1 |
| 7 | 1 | 2 |
| 8 | 1 | 3 |
-----------------------------
table employee:
| id | name |
+----+------+
| 1 | emp1 |
| 2 | emp2 |
| 3 | emp3 |
-------------
and now I want to display all employees from table employee and from table_2 if the employee record in table employee exists but in table_2 it does not. If record does not exist mark as "unchecked" but if exists mark as "checked".
The point is how to find data from table_employee no matter data is exist or not exist on table_2.
The IF() operation lets you do this:
SELECT e.*, IF(ISNULL(t2.id), 'unchecked', 'checked') AS `checked`
FROM table_employee e
LEFT JOIN table_2 t2 ON t2.id_employee = e.id
+------+---------+----------+
| id | uid | assessors|
+------+---------+----------+
| 1 | 1 | Volvo |
| 2 | 2 | kenitra |
| 3 | 3 | rabat |
| 4 | 3 | Fahad |
| 5 | 3 | John |
+------+---------+----------+
I want to fetch the data on the base of uid because i use a Inner join to fetch data from other table now i want to fetch and show all assesors on uid but i get this output
+---------+----------+
| uid | assessors|
| 1 | Volvo |
| 2 | kenitra |
| 3 | rabat |
Desired Output is:
+---------+----------+
| uid | assessors|
| 1 | Volvo |
| 2 | kenitra |
| 3 | rabat |
| 3 | Fahad |
| 3 | John |
my query is =
SELECT * FROM lego_activity_answers WHERE uid = $studentid;
$studentid comes from another table
If you want to get all data in the lego_activity table except for id, simply select the individual fields you want, instead of querying *
SELECT uid, assessors FROM lego_activity_answers WHERE uid = $studentid;
SELECT DISTINCT uid ,assessors FROM lego_activity_answers where uid=$studentid;
( this may not perform well at all in large tables )
I have 2 tables:
tbl1:
+-------+-------+
| p_id | f_id |
+-------+-------+
| 1 | 2 |
| 1 | 4 |
| 2 | 1 |
| 3 | 4 |
| 4 | 1 |
| 4 | 3 |
+-------+-------+
tbl2:
+-------+-------+-------+
| u_id | fname | lname |
+-------+-------+-------+
| 1 | adam | smith |
| 2 | jon | jones |
| 3 | sean | dent |
| 4 | jack | scott |
+-------+-------+-------+
my logged in id (php) is:
$user->id // this returns '3'
I need to return each u_id in tbl2 for each p_id in tbl1 that does NOT have my $user->id (3 in this example) in it's corresponding f_id. For example, 4 should not be returned because it has a 3 in one of it's f_id's. I hope this makes sense!!! Many thanks..
I think this query should work for you.
SELECT u_id FROM tbl2
WHERE u_id NOT IN
(SELECT p_id FROM tbl1
where f_id = $user);
You will need to build the query in PHP so that it boils down to the above query in SQL.
I have 2 tables.
Table 1: tA
+----+--------------------+
| id | url |
+----+--------------------+
| 1 | hxxp://www.aaa.com |
| 2 | hxxp://www.bbb.com |
+----+--------------------+
Table 2: tB
+----+-------+--------+----------+
|id | tA_id | cat_id | cat_name |
+----+-------+--------+----------+
| 1 | 1 | 1 | Mobile |
| 2 | 1 | 2 | Other |
| 3 | 2 | 2 | Other |
+----+-------+--------+----------+
Expected Output
+----+-------+--------+----------+
| id | tA_id | cat_id | cat_name |
+----+-------+--------+----------+
| 1 | 1 | 1 | Mobile |
| 3 | 2 | 2 | Other |
+----+-------+--------+----------+
mysql code:
select *
from tA
inner tB
on tA.id = tB.tA_id
where tB.cat_id = 1
or tB.cat_id = 2
Group By tA_id
result from my mysql code:
+----+-------+--------+----------+
| id | tA_id | cat_id | cat_name |
+----+-------+--------+----------+
| 1 | 1 | 2 | Other |
| 3 | 2 | 2 | Other |
+----+-------+--------+----------+
How do I do?
Remove your group by tA_id because it is grouping cat_name Mobile and Other together.
If you need to keep it use ORDER BY tB.cat_id ASC which i believe will show the cat_id 1 and 2 like you need it
There is an error in query... JOIN is missing...
QUERY
SELECT *
FROM tA
INNER JOIN tB
ON tA.id = tB.tA_id
WHERE tB.cat_id = 1
OR tB.cat_id = 2
GROUP BY tA_id
This is fetching expected results
+----+---------------------+-----+--------+--------+----------+
| id | url | id | tA_id | cat_id | cat_name |
+----+---------------------+-----+--------+--------+----------+
| 1 | hxxp://www.aaa.com | 1 | 1 | 1 | mobile |
| 2 | hxxp://www.bbb.com | 3 | 2 | 2 | other |
+----+---------------------+-----+--------+--------+----------+
Try this :-
select *
from tA
inner join tB
on tA.id = tB.tA_id
where tB.cat_id = 1
or tB.cat_id = 2
group by tb.cat_name;
Hope it will help you.
I have 2 tables - users and users_audit, need to display results from 2 separate queries into 2 columns with relation to each other. I already figured out both queries.
query for users: SELECT rowid,data FROM users WHERE columnid = 1 GROUP BY rowid;
+-------+------------+
| rowid | data |
+-------+------------+
| 1 | John |
| 2 | Abi |
| 3 | Tony |
| 4 | Gregg |
| 5 | Jon |
| 6 | Victor |
| 7 | Daniel |
query for users_audit: SELECT date_created FROM users_audit WHERE rowid = 6 ORDER BY date_created DESC, date_created DESC LIMIT 1;
Purpose of the query is to display latest date_created for particular rowid.
+---------------------+
| date_created |
+---------------------+
| 2012-07-04 09:20:12 |
+---------------------+
Table users_audit looks like this:
SELECT * FROM users_audit;
+-------+---------+--------------+-------------+---------------------+
| id | rowid | before_value | after_value | date_created |
+-------+---------+--------------+-------------+---------------------+
| 1 | 6 | 3 | 5 | 2012-06-29 15:48:11 |
| 2 | 5 | Out (0) | 2 | 2012-07-04 09:20:10 |
| 3 | 6 | 5 | 4 | 2012-07-04 09:20:12 |
| 4 | 7 | 3 | 6 | 2012-07-04 09:20:14 |
| 5 | 3 | 2 | 3 | 2012-07-04 09:20:16 |
| 6 | 15 | 6 | 5 | 2012-07-04 09:20:22 |
I need to display 2 columns - data from users and date_created from users_audit for each rowid. It means query for users_audit must be run for each rowid (in the loop?).
Expected result displayed in php is:
+------------+----------------------+
| data | date_created |
+------------+----------------------+
| John | (latest date) |
| Abi | (latest date) |
| Tony | (latest date) |
| Gregg | (latest date) |
| Jon | (latest date) |
| Victor | 2012-07-04 09:20:12 |
| Daniel | (latest date) |
How can this be achieved this in php?
Why cant you just create a view and use a join to create the table you want?
SELECT users.data, users_audit.date_created FROM users
INNER JOIN users_audit ON users.rowid = users_audit.rowid
Or am I missing something here?
EDIT
SELECT users.data, users_audit.date_created FROM users
INNER JOIN users_audit ON users.rowid = users_audit.rowid
WHERE users_audit.date_created = (SELECT MAX(date_created) from users_audit
GROUP BY rowid)
I believe this should work..? Let me know.