Print information from database table in shopping site - php

Question

I tried my best but I stuck on this problem. Sorry for my bad english.
So here is the situation:
I am trying to make a little shopping site. My database table looks like this:
id pic titel desc price
1 gta5.png Grand Theft Auto 5 A open world game... 49.99
2 cod.png Call Of Duty: MW A Ego-Shooter game... 59.99
3 play4.png Playstation 4 Next-Gen Console... 249.99
4 contr.png Ps4 Controller Next-Gen Equipment... 69.99
On the Database Class file I have some function where I get the column information from the table:
public function getImg(){
while($row = mysqli_fetch_row($this->query)){
return $row[1];
}
}
public function getTitel(){
while($row = mysqli_fetch_row($this->query)){
return $row[2];
}
}
...
With getImg() I will get every information on the pic column like: gta5.png, cod.png etc.
My problem is starting here. I want to print out every column with a for loop on the index.php file. But I can't see any information. Here is the index.php file:
<ul>
<li>
<div class="container">
<div class="content">
<?php
for($i = 0; $i < $database->getTableLength(); $i++){
?>
<img src="image/<?php echo $database->getImg(); ?>"></img>
<h4><?php echo $database->getTitel(); ?></h4>
<h5><?php echo $database->getDesc(); ?></h5>
<h2><?php echo $database->getPrice(); ?>€</h2>
<input type="button" name="submit" value="Buy">
<?php
}
?>
</div>
</div>
</li>
</ul>
But as I said there is nothing. The getTableLength() function is the length of the table (In this case 4). I also tried to print it out one by one like this:
<ul>
<li>
<div class="container">
<div class="content">
<?php
for($i = 0; $i < $database->getTableLength(); $i++){
echo $database->getImg() . "<br>";
}
?>
</div>
</div>
</li>
</ul>
But again failed.. I can see even the br tag but not the information that I want to print out. When I put the echo line before the for loop, then I can see the first index of the column (gta5.png), but I want to have all columns.
Hope to see some solutions. Thanks for any kind of help!
EDIT:
It is working when I write 5 instead of the length function:
for($i = 0; $i < 5; $i++){
echo $database->getImg();
}
But I still want to use that function. The getTableLength() function isn't working as I expected. There is nothing to see when I insert the function. The getTable function looks like this:
public function getTableLength(){
$sql = "SELECT COUNT(*) AS num FROM `$this->table`";
$this->query = mysqli_query($this->connect, $sql);
if($this->query){
$row = mysqli_fetch_assoc($this->query);
return $row['num'];
}
}
When I call it on the index.php file like:
$database->getTableLength();
I can see nothing and everything is gone. It's like buggy.

Answer 1

Fixed. It was to complicated. Think simple and do it better..
Here is the solution:
<?php
$table = $database->getTableName();
$sql = "SELECT * FROM `$table`";
$connect = $database->getConn();
$result = mysqli_query($connect, $sql);
if(mysqli_num_rows($result) > 0){
while($row = mysqli_fetch_array($result)){
?>
<form method="post" action="index.php?action=add&id=<?php echo $row["id"] ?>">
<ul>
<li>
<div class="container">
<div class="content">
<img src="image/<?php echo $row["bild"]; ?>"></img>
<h4><?php echo $row["titel"]; ?></h4>
<h5><?php echo $row["beschreibung"]; ?></h5>
<h2><?php echo $row["preis"]; ?>€</h2>
<input type="hidden" name="hidden_name" value="<?php echo $row["titel"]; ?>">
<input type="hidden" name="hidden_price" value="<?php echo $row["preis"]; ?>">
<input type="submit" name="add_to_cart" value="Kaufen">
</div>
</div>
</li>
</ul>
<?php