CakePHP ignore Record not found in table exception - php

There is no record with ID 0 on purpos. And I'm doing
$id = 0;
try {
$object = $this->MyModel->get($id);
} catch(Exception $e){
//Nothing
}
And I still get the exception thrown "Record not found in table".
How can I ignore, that there is no record with the given ID with get($id) and avoid the exception?

$this->MyModel->find('all', ['conditions' => ['id' => $id]])->first(); seems to be the shortest code without getting an error on non-existence of an element.
The other problem was, that I used Exception instead of the correct \Exception, that's why the error was thrown despite the try-catch-block.

You can also try making the relationship a LEFT join.
Insde MyModelTable.php
$this->MyModel->belongsTo('ParentTable', [
'foreignKey' => 'parent_id',
'joinType' => 'LEFT',
]);

Why not using if statement?
$id = 0;
$object = [];
if ($id){
$object = $this->MyModel->get($id);
} else{
$object = [];
}

Related

Laravel hasMany error. 'site_id' doesn't have a default value

I have following method in a controller
public function store(Request $request)
{
$site = Site::create([
"path" => $request->path,
"site_link" => $request->link,
]);
if ($request->features) {
$features = explode(',', $request->features);
foreach ($features as $feature) {
$site->features()->save(SiteFeature::create(["feature" => $feature]));
}
}
return response()->json($site, 201);
}
Site model has this method
public function features()
{
return $this->hasMany('App\SiteFeature');
}
And this is my $fillable property of a SiteFeature
protected $fillable = ['feature', 'site_id'];
By some reason I get next error
local.ERROR: SQLSTATE[HY000]: General error: 1364 Field 'site_id'
doesn't have a default value (SQL: insert into site_features
(feature) values (fes)) {"exception":"[object]
(Illuminate\Database\QueryException(code: HY000): SQLSTATE[HY000]:
General error: 1364 Field 'site_id' doesn't have a default value (SQL:
insert into site_features (feature) values (fes))
The Model::create method actually creates a record in your database and since you're not specifying a required site_id, it is failing which is why you're seeing this error.
It looks like you're trying to use Laravel's relationships to save a new SiteFeature for the site but you're passing what would be an already existing object (if the query didn't fail) to the relation's save method.
You need to either pass a new instance of SiteFeature, that has not already been saved to the database to the save method:
$this->features()->save(new SiteFeature(['feature' => $feature]));
or you can use the relation's create method to avoid having to pass in an instance altogether, you just need to provide the attributes:
$this->features()->create(['feature' => $feature]);
try this
in your model features
public function features()
{
return $this->hasMany('App\SiteFeature','site_id','id');
}
you model SiteFeature
public function siteFeatures()
{
return $this->belongsTo('App\features', 'site_id', 'id');
}
$site = Site::create([
"path" => $request->path,
"site_link" => $request->link,
]);
Doesn't return the last insert id... try
$site = new Site;
$site->path = $request->path;
$site->site_link = $request->link;
$site->save();
As for this part:
if ($request->features) {
$features = explode(',', $request->features);
foreach ($features as $feature) {
$site->features()->save(SiteFeature::create(["feature" => $feature]));
}
}
You could do this if the above code doesnt work...
if ($request->features) {
$features = explode(',', $request->features);
foreach ($features as $feature) {
$sf = new SiteFeature;
$sf->feature = $feature;
$sf->site_id = $site->id;
$sf->save();
}
}

Delete item with ajax from session in laravel 5.4, respond with 500 internal server error

I have this code to push products into array session in laravel 5.4
public function agregarACarrito(Request $request)
{
$producto = new Producto();
$producto = Producto::with('marca')
->where('id', '=', $request->parametros)
->get();
$request->session()->push('session_products', $producto);
return "Producto eliminado";
}
So, i want to delete an item using AJAX, this is my code right now:
public function borrarDeCarrito(Request $request){
$productos = $request->session()->pull('session_products');
foreach($productos as $key => $producto) {
if ($request->parametros == $producto->id) {
unset($productos[$key]);
break;
}
}
$request->session()->put('session_products', $productos);
echo"¡Product removed!";
}
I get a 500 internal server error and in the laravel error log i'm getting
'Exception' with message 'Property [id] does not exist on this collection
instance.
This is my ajax code
function borrarDeCarrito(id){
var parametros=id;
$.ajax({
data:{parametros:parametros},
url:'/borrarDeCarrito',
type:'post',
success:function(data){
//console.log(data);
alert(data);
}
});
}
¿what i'm doing wrong ?
The problem is you are pulling an unregistered index from your session.
$request->session()->push('session_products',$producto);
In the code above, you push session_products to your session but you pull $request->parametros from your session on which you didn't register.
You can only pull session_products from $request->session(), and here's a quick fix
public function borrarDeCarrito(Request $request){
$productos = $request->session()->pull('session_products');
foreach($productos as $key => $producto) {
if ($request->parametros == $producto->id) {
unset($productos[$key]);
break;
}
}
$request->session()->put('session_products', $productos);
}
UPDATE:
$producto = Producto::with('marca')
->where('id', '=', $request->parametros)
->get();
'Exception' with message 'Property [id] does not exist on this collection instance.
With the codes above you are trying to get 1 row by referencing its id, but you called ->get() which is expected to return a multiple collection of Productos.
And after you put that on your session, the structure becomes like this:
session_products = [
0 => [0 => [name => 'productname', ...]]
]
Instead of:
session_products = [
0 => [name => 'productname', ..]
]
You should use ->first() when you only want to get a single row.
To fix it, simply:
$producto = Producto::where('id', '=', $request->parametros)
->with('marca')
->first();

Updating table fields on submit button

I am very much new to laravel framework.
I have one form , which i need to update on submit button click.
when submit button clicks control goes to controller.php 's update() function .
But I am unable to edit any field's value.
here is my code.
public function update($id)
{
//echo "<pre>";print_r(Input::all());exit;
$product = $this->product->find($id);
$input = Input::only('designer', 'sku', 'name', 'display_name', 'description', 'price', 'main_category', 'sub_category', 'lead_time', 'sizing', 'woven', 'body_fabric', 'lining_fabric', 'fit', 'primary_color', 'secondary_color', 'care_label', 'neck_type', 'closure', 'trims', 'special_finishings', 'image1', 'image2', 'image3', 'image4', 'image5','top', 'combo_products', 'keywords', 'visibility', 'featured');
//echo "<pre>";print_r($input);exit;
try
{
$this->adminNewProductForm->validate($input);
} catch(\Laracasts\Validation\FormValidationException $e)
{
return Redirect::back()->withInput()->withErrors($e->getErrors());
}
$slug = Str::slug(Input::get('name'));
$slug = $this->product->getSlug($slug);
$input = array_add($input, 'slug', $slug);
DB::transaction(function() use($product, $input)
{
$product->fill($input)->save();
$stock_count = 0;
if(!empty(Input::get('xsmall_size')))
{
$rows = DB::table('products_variants')->where('product_id', $product->id)->where('variant_name', 'XS')->get();
$stock_count += Input::get('xsmall_stock');
if(!empty($rows))
{
DB::table('products_variants')->where('product_id', $product->id)->where('variant_name', 'XS')->update(array('variant_specs' => Input::get('xsmall_size'), 'price_change' => Input::get('xsmall_price'), 'total_stock' => Input::get('xsmall_stock'), 'stock_used' => 0));
} else {
DB::table('products_variants')->insert(array('product_id' => $product->id, 'variant_name' => 'XS', 'variant_specs' => Input::get('xsmall_size'), 'price_change' => Input::get('xsmall_price'), 'total_stock' => Input::get('xsmall_stock'), 'stock_used' => 0));
}
}
$input = array();
$input['flagship_status'] = Input::get('flagship_status');
if(Input::get('flagship_status'))
{
$input['stock_count'] = Input::get('small_stock');
}else {
$input['stock_count'] = $stock_count;
}
$product->fill($input)->save();
});
//echo "<pre>";print_r(Input::all());exit;
return Redirect::back()->withFlashMessage('Product Updated Successfully!');
}
Also I cant understand , what is going on by this line ? because i did not find validate function anywhere in my code.
$this->adminNewProductForm->validate($input);
I need to update table products not products_variants.
validate is inherited from the FormRequst class.
https://laravel.com/api/5.0/Illuminate/Foundation/Http/FormRequest.html#method_validate
You've provided too much code and too little information. You said you need to update a specific table, but yet there are two lines where you are very intentionally manually updating a database entry.
This is one of them:
DB::table('products_variants')->where('product_id', $product->id)->where('variant_name', 'XS')->update(array('variant_specs' => Input::get('xsmall_size'), 'price_change' => Input::get('xsmall_price'), 'total_stock' => Input::get('xsmall_stock'), 'stock_used' => 0));
When you call this:
$product->fill($input)->save();
It also saves 'dirty' (modified) models that also belong to it, which can include products_variants relationships. From the sound of it, you are incorrectly applying changes directly through SQL, and then the model's save method is overwriting it.
You seem unclear about what your code is actually doing, and I would strongly suggest simplifying it down and adding in code as you begin to understand what each line does. I think your question is the byproduct of copying an example and adding your own work without understanding how Laravel handles relationships and models. There is almost never a good reason to use raw SQL or DB statements.

Unable to save select box options in Laravel 5.1

I am working on my first project using Laravel 5.1. Uses a selectbox in a form.
{!!Form::select('animal_parent[]', array('1' => 'opt1', '2' => 'opt2', '3' => 'opt3', '4' => 'opt4',), null, ['id' => 'animal_parent', 'disabled' => 'disabled', 'multiple' => 'multiple', 'class' => 'form-control'])!!}
Selection limited to two options which need to saved in two columns, male_parent and female_ parent of the animal table.
There are no male_parent and female_ parent element names in the form. Similarly no animal_parent field in animal table.
Values are set as expected in the code given below. However, the insert command does not reflect the newly set values and throws an error.
"ErrorException in helpers.php line 671: preg_replace(): Parameter mismatch, pattern is a string while replacement is an array."
Any help would be much appreciated.
First attempt using mutators
public function setMaleParentAttribute()
{
$parent = Input::get('animal_parent');
$this->attributes['male_parent'] = intval($parent[0]);
}
public function setFemaleParentAttribute(AddAnimalRequest $request)
{
$parent = Input::get('animal_parent);
if (isset($parent[1])) {
$this->attributes['female_parent'] = intval($parent[1]);
} else {
$this->attributes['female_parent'] = intval($parent[0]);
}
unset($request->animal_parent);
}
Second attempt using the store() method in the controller.
$animal = new Animal($request->all());
$parent = Input::get('animal_parent');
$animal['male_parent'] = intval($parent[0]);
if (isset($parent[1])) {
$animal['female_parent'] = intval($parent[1]);
} else {
$animal['female_parent'] = intval($parent[0]);
}
unset($request->animal_parent);
Auth::user()->animals()->save($animal);
return redirect('animals');
The problem was then solved with a change in UI. I feel the problem could have been solved using the below method. Hope that helps someone.
$input = $request->all();
$parent = $input['animal_parent'];
$input['male_parent'] = intval($parent[0]);
if (isset($parent[1])) {
$input['female_parent'] = intval($parent[1]);
} else {
$input['female_parent'] = intval($parent[0]);
}
unset($input['animal_parent']);
$animal = new Animal($input);
$animal->save();`

Get the Last Inserted Id Using Laravel Eloquent

I'm currently using the below code to insert data in a table:
<?php
public function saveDetailsCompany()
{
$post = Input::All();
$data = new Company;
$data->nombre = $post['name'];
$data->direccion = $post['address'];
$data->telefono = $post['phone'];
$data->email = $post['email'];
$data->giro = $post['type'];
$data->fecha_registro = date("Y-m-d H:i:s");
$data->fecha_modificacion = date("Y-m-d H:i:s");
if ($data->save()) {
return Response::json(array('success' => true), 200);
}
}
I want to return the last ID inserted but I don't know how to get it.
Kind regards!
After save, $data->id should be the last id inserted.
$data->save();
$data->id;
Can be used like this.
return Response::json(array('success' => true, 'last_insert_id' => $data->id), 200);
For updated laravel version try this
return response()->json(array('success' => true, 'last_insert_id' => $data->id), 200);
xdazz is right in this case, but for the benefit of future visitors who might be using DB::statement or DB::insert, there is another way:
DB::getPdo()->lastInsertId();
If the table has an auto-incrementing id, use the insertGetId method to insert a record and then retrieve the ID:
$id = DB::table('users')->insertGetId([
'email' => 'john#example.com',
'votes' => 0
]);
Refer: https://laravel.com/docs/5.1/queries#inserts
For anyone who also likes how Jeffrey Way uses Model::create() in his Laracasts 5 tutorials, where he just sends the Request straight into the database without explicitly setting each field in the controller, and using the model's $fillable for mass assignment (very important, for anyone new and using this way): I read a lot of people using insertGetId() but unfortunately this does not respect the $fillable whitelist so you'll get errors with it trying to insert _token and anything that isn't a field in the database, end up setting things you want to filter, etc. That bummed me out, because I want to use mass assignment and overall write less code when possible. Fortunately Eloquent's create method just wraps the save method (what #xdazz cited above), so you can still pull the last created ID...
public function store() {
$input = Request::all();
$id = Company::create($input)->id;
return redirect('company/'.$id);
}
**** For Laravel ****
Firstly create an object, Then set attributes value for that object, Then save the object record, and then get the last inserted id. such as
$user = new User();
$user->name = 'John';
$user->save();
// Now Getting The Last inserted id
$insertedId = $user->id;
echo $insertedId ;
There are several ways to get the last inserted id. All are based on what method do you used when inserting. In your case you can get last Id like the following:
$data->save();
$data->id;
For others who need to know how can they get last inserted id if they use other insert methods here is how:
Using create() method
$book = Book::create(['name'=>'Laravel Warrior']);
$lastId = $book->id;
Using insertGetId()
$id = DB::table('books')->insertGetId( ['name' => 'Laravel warrior'] ); $lastId = $id;
Using lastInsertId() method
$lastId = DB::getPdo()->lastInsertId();
Reference https://easycodesolution.com/2020/08/22/last-inserted-id-in-laravel/
In laravel 5: you can do this:
use App\Http\Requests\UserStoreRequest;
class UserController extends Controller {
private $user;
public function __construct( User $user )
{
$this->user = $user;
}
public function store( UserStoreRequest $request )
{
$user= $this->user->create([
'name' => $request['name'],
'email' => $request['email'],
'password' => Hash::make($request['password'])
]);
$lastInsertedId= $user->id;
}
}
This worked for me in laravel 4.2
$id = User::insertGetId([
'username' => Input::get('username'),
'password' => Hash::make('password'),
'active' => 0
]);
Here's an example:
public static function saveTutorial(){
$data = Input::all();
$Tut = new Tutorial;
$Tut->title = $data['title'];
$Tut->tutorial = $data['tutorial'];
$Tut->save();
$LastInsertId = $Tut->id;
return Response::json(array('success' => true,'last_id'=>$LastInsertId), 200);
}
Use insertGetId to insert and get inserted id at the same time
From doc
If the table has an auto-incrementing id, use the insertGetId method
to insert a record and then retrieve the ID:
By Model
$id = Model::insertGetId(["name"=>"Niklesh","email"=>"myemail#gmail.com"]);
By DB
$id = DB::table('users')->insertGetId(["name"=>"Niklesh","email"=>"myemail#gmail.com"]);
For more details : https://laravel.com/docs/5.5/queries#inserts
For insert()
Example:
$data1 = array(
'company_id' => $company_id,
'branch_id' => $branch_id
);
$insert_id = CreditVoucher::insert($data1);
$id = DB::getPdo()->lastInsertId();
dd($id);
Here is how we can get last inserted id in Laravel 4
public function store()
{
$input = Input::all();
$validation = Validator::make($input, user::$rules);
if ($validation->passes())
{
$user= $this->user->create(array(
'name' => Input::get('name'),
'email' => Input::get('email'),
'password' => Hash::make(Input::get('password')),
));
$lastInsertedId= $user->id; //get last inserted record's user id value
$userId= array('user_id'=>$lastInsertedId); //put this value equal to datatable column name where it will be saved
$user->update($userId); //update newly created record by storing the value of last inserted id
return Redirect::route('users.index');
}
return Redirect::route('users.create')->withInput()->withErrors($validation)->with('message', 'There were validation errors.');
}
Although this question is a bit dated. My quick and dirty solution would look like this:
$last_entry = Model::latest()->first();
But I guess it's vulnerable to race conditions on highly frequented databases.
After saving model, the initialized instance has the id:
$report = new Report();
$report->user_id = $request->user_id;
$report->patient_id = $request->patient_id;
$report->diseases_id = $request->modality;
$isReportCreated = $report->save();
return $report->id; // this will return the saved report id
You can easily fetch last inserted record Id
$user = User::create($userData);
$lastId = $user->value('id');
It's an awesome trick to fetch Id from the last inserted record in the DB.
After
$data->save()
$data->id will give you the inserted id,
Note: If your autoincrement column name is sno then you should use
$data->sno and not $data->id
After saving a record in database, you can access id by $data->id
return Response::json(['success' => true, 'last_insert_id' => $data->id], 200)
In Laravel 5.2 i would make it as clean as possible:
public function saveContact(Request $request, Contact $contact)
{
$create = $contact->create($request->all());
return response()->json($create->id, 201);
}
For Laravel, If you insert a new record and call $data->save() this function executes an INSERT query and returns the primary key value (i.e. id by default).
You can use following code:
if($data->save()) {
return Response::json(array('status' => 1, 'primary_id'=>$data->id), 200);
}
You can do this:
$result=app('db')->insert("INSERT INTO table...");
$lastInsertId=app('db')->getPdo()->lastInsertId();
$objPost = new Post;
$objPost->title = 'Title';
$objPost->description = 'Description';
$objPost->save();
$recId = $objPost->id; // If Id in table column name if other then id then user the other column name
return Response::json(['success' => true,'id' => $recId], 200);
For get last inserted id in database
You can use
$data = new YourModelName;
$data->name = 'Some Value';
$data->email = 'abc#mail.com';
$data->save();
$lastInsertedId = $data->id;
here $lastInsertedId will gives you last inserted auto increment id.
The shortest way is probably a call of the refresh() on the model:
public function create(array $data): MyModel
{
$myModel = new MyModel($dataArray);
$myModel->saveOrFail();
return $myModel->refresh();
}
You can also try like this:
public function storeAndLastInrestedId() {
$data = new ModelName();
$data->title = $request->title;
$data->save();
$last_insert_id = $data->id;
return $last_insert_id;
}
Here it is how it worked for me, family_id is the primary key with auto increment I am using Laravel7
public function store(Request $request){
$family = new Family();
$family->family_name = $request->get('FamilyName');
$family->family_no = $request->get('FamilyNo');
$family->save();
//family_id is the primary key and auto increment
return redirect('/family/detail/' . $family->family_id);
}
Also in the Model Family file which extends Model, should have the increment set to true otherwise the above $family-->family_id will return empty
public $incrementing = true;
Using Eloquent Model
$user = new Report();
$user->email= 'johndoe#example.com';
$user->save();
$lastId = $user->id;
Using Query Builder
$lastId = DB::table('reports')->insertGetId(['email' => 'johndoe#example.com']);
After Saving $data->save(). all data is pushed inside $data. As this is an object and the current row is just saved recently inside $data. so last insertId will be found inside $data->id.
Response code will be:
return Response::json(array('success' => true, 'last_insert_id' => $data->id), 200);
You can get last inserted id with same object you call save method;
$data->save();
$inserted_id = $data->id;
So you can simply write:
if ($data->save()) {
return Response::json(array('success' => true,'inserted_id'=>$data->id), 200);
}
public function store( UserStoreRequest $request ) {
$input = $request->all();
$user = User::create($input);
$userId=$user->id
}
Using Eloquent Model
use App\Company;
public function saveDetailsCompany(Request $request)
{
$createcompany=Company::create(['nombre'=>$request->input('name'),'direccion'=>$request->input('address'),'telefono'=>$request->input('phone'),'email'=>$request->input('emaile'),'giro'=>$request->input('type')]);
// Last Inserted Row ID
echo $createcompany->id;
}
Using Query Builder
$createcompany=DB::table('company')->create(['nombre'=>$request->input('name'),'direccion'=>$request->input('address'),'telefono'=>$request->input('phone'),'email'=>$request->input('emaile'),'giro'=>$request->input('type')]);
echo $createcompany->id;
For more methods to get Last Inserted Row id in Laravel : http://phpnotebook.com/95-laravel/127-3-methods-to-get-last-inserted-row-id-in-laravel

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