Updating multiple MYSQL rows with one submit button [duplicate] - php

Question

This question already has an answer here:
How do I insert Data Into database with many Input which has same name?
(1 answer)
Closed 3 years ago.
i was trying to updating multiple MYSQL rows with one submit button,
before i used to create submit for each row, but since i have a lot of rows now i need to update them all together
index.php
<?php
if (mysqli_num_rows($row){
while($row1= mysqli_fetch_assoc($row){
id<input type="text" value="<?php echo $row["id"];?>" name='id' id="id" >
id<input type="text" value="<?php echo $row["name"];?>" name='name' id="name" >
}
<button type="submit" formaction="update.php">
submit
</button>
}
update.php
$id= $_POST['id'];
$name= $_POST['name'];
$sql = "UPDATE `$tabelname` SET
name='$name'
WHERE id='$id'";
its updating the first row only

Answer 1

Assuming that id is the primary key,
In your html, you need to use an array in the name. This allows the form to send it as an array instead of just taking the last value:
<?php while($row1= mysqli_fetch_assoc($row): ?>
<div>
<label>Name: </label>
<input type="text" value="<?=$row["name"]?>" name="name[<?= $row["id"] ?>]" id="name-"<?= $row["id"] ?> " />
</div>
<?php endwhile; ?>
The key here is name=“name[]”. The square brackets make it an array. I’m using the id as the index. (Note that <?= is just a much more concise way of writing <?php echo)
Then, in your php script, the easiest way to show you is to iterate through the array and do an update each time:
$row = $_POST[‘name’];
foreach($row as $id => $name) {
// This is a big No-No!
// $sql = "UPDATE `$tabelname` SET name='$name' WHERE id='$id'";
// use prepared statements. Always.
$sql = "UPDATE `$tabelname` SET name=? WHERE id=?"; // assuming “tabelname” is not user-provided
// database connection up to you
$stmt = $db->prepare($sql);
$stmt->execute( [$name, $id] );
}