I create a code to display from a table
$sql = "SELECT * FROM table";
$stmt = $dbcon->prepare($sql);
$stmt->execute();
$result = $stmt->fetchAll();
to display the result, I use the following ode:
<?php foreach($result as $readrow){ ?>
<div class="table-row">
<td><?php echo $readrow['id'];?></td>
<td><?php echo $readrow['area'];?></td>
<td><?php echo $readrow['color'];?></td>
<?php } ?>
Is there any way, the table can be displayed with the header?
There are many duplicated questions but all answers are beyond any reason, offering complicated solutions involving running extra queries etc.
While the solution is right here: when using fetchAll(), you already have all the column headers in the $result variable
$headerNames = $result ? array_keys($result[0]) : [];
now you can foreach over $coulmnNames to get the table header and the foreach over $result to display the results.
<table class='table'>
<tr>
<?php foreach($coulmnNames as $name): ?>
<th><?= $name ?></th>
<?php endforeach ?>
</tr>
<?php foreach($result as $row){ ?>
<tr class="table-row">
<?php foreach($result as $value){ ?>
<td><?= $value ?></td>
</tr>
<?php endforeach ?>
</table>
Related
I am trying to populate html table with data from mysql.But i am stuck on this part where each time i add some data it keeps repeating. On the picture below you can see that Test 1 repeat each time for every P20,P21,P24,P22,P23 and i needed to be one TEST1 for all of them. When i add Test 2 with value 19000 its making new P20 and all data come from Test 1 to Test 2. Can someone help me how to fix this.Any hint or suggestion wil be appreciated. Thank you all very much (Sorry for my bad english)
This is code that runs this
$sql = 'SELECT DISTINCT Pers.naam, Rol.funkcija,pdata.broj
FROM ids
left JOIN Pers ON ids.persid = Pers.id
left JOIN Rol ON ids.rolid = Rol.id
left JOIN pdata ON ids.pdataid = pdata.id
';
$query = $conn->prepare($sql);
$query->execute();
$testing = $query->fetchAll(PDO::FETCH_ASSOC);
?>
<table>
<tr>
<th>P Small <small>(NONE)</small></th>
<?php
foreach ($testing as $test):
?>
<th>
<?php
echo $test['naam'] . '<br />';
?>
</th>
<?php
endforeach;
?>
</tr>
<tr>
<th>TESTING LINES</th>
</tr>
<?php foreach ($testing as $test): ?>
<tr>
<td><?php echo $test['funkcija']; ?></td>
<?php endforeach; ?>
<?php
foreach ($testing as $test):
?>
<td><?php echo $test['broj']; ?></td>
<?php
endforeach;
?>
</tr>
</table>
I would like to have it like this
There is some refactoring required to get to the output you want.
You seem to be enumerating quite a lot of data from your SQL result, so there is some grouping required to make things easier.
To get the appropriate number to each "naam" and "funkcija" you can use array_filter which however could theoretically return several numbers in each case.
You'll also have to nest a couple foreach instead of running them after one another.
If I understand your data structure correctly, this should at least give you a good starting point for the output you want:
<?php
// ...
$testing = $query->fetchAll(PDO::FETCH_ASSOC);
$naams = array_unique(array_column($testing, "naam"));
$funkcijas = array_unique(array_column($testing, "funkcija"));
?>
<table>
<tr>
<th>P Small <small>(NONE)</small></th>
<?php foreach ($naams as $naam): ?>
<th>
<?php echo $naam; ?>
</th>
<?php endforeach; ?>
</tr>
<tr>
<th>TESTING LINES</th>
</tr>
<?php foreach ($funkcijas as $funkcija): ?>
<tr>
<td><?php echo $funkcija; ?></td>
<?php foreach ($naams as $naam): ?>
<?php
$data = array_filter(
$testing,
function ($v) use ($naam, $funkcija)
{
return $v["naam"] === $naam && $v["funkcija"] === $funkcija;
}
);
foreach ($data as $value): ?>
<td><?php echo $value["broj"]; ?></td>
<?php endforeach; ?>
<?php endforeach; ?>
</tr>
<?php endforeach; ?>
</table>
im having trouble getting a result value of a query and the error says.
Notice: Undefined index: prelim in C:\xampp\htdocs\gradingxworking\teacher\student.php on line 85 can someone help me to fix this or some clue to fix this? im just starting to learn php.
<tbody>
<?php $c=1; ?>
<?php foreach($mystudent as $row): ?>
<tr>
<td><?php echo $c; ?></td>
<td class="text-center"><?php echo $row['studid']; ?></td>
<td class="text-center"><?php echo $row['lname'].', '.$row['fname']; ?></td>
<?php $grade = $student->getstudentgrade($row['studid']);?>
//code that cause error line 85--> <td class="text-center"><?php echo $grade['prelim']; ?></td>
</tr>
<?php $c++; ?>
<?php endforeach; ?>
<?php if(!$mystudent): ?>
<tr><td colspan="8" class="text-center text-danger"><strong>*** No Result ***</strong></td></tr>
<?php endif; ?>
</tbody>
the function:
function getstudentgrade($studid){
$q = "select * from studentsubject where studid=$studid";
$r = mysql_query($q);
$data = array();
while($row = mysql_fetch_array($r)){
$data[] = array(
'prelim' => $row['prelim']
);
}
return $data;
}
As #Bara suggested, you need to check the array first before accessing it.
if(isset($grade['prelim']))
I suspect, there is no data for specific studid. Lets see you function.
$data = array();
while($row = mysql_fetch_array($r)){
$data[] = array(
'prelim' => $row['prelim']
);
}
Now, you have created new array $data. But, if there is no record ? your while loop won't be executed and your $data array won't have anything. right ? So, to handle that, you need to check whether there is any data in your array.
Now, second point, which #Mossavari made is also correct. You need to use
$grade[0]['prelim'];
instead of
$grade['prelim'];
after doing
<?php $grade = $student->getstudentgrade($row['studid']);?>
you need to check what $grade holdes. and its better before trying to fetch data from array to make a check like this :
if(isset($grade['prelim']))
Based on your getstudentgrade function you'll have multidimensional array result, you may need to change $grade['prelim'] to $grade[0]['prelim']
Since, every student will have only 1 grade. So, why to use array.
<?php
function getstudentgrade($studid){
$q = "select * from studentsubject where studid=$studid LIMIT 0,1";
$data = "";
$r = mysql_query($q);
while($row = mysql_fetch_array($r)){
$data = $row['prelim'];
}
return $data;
}?>
PHP
<tbody>
<?php $c=1; ?>
<?php foreach($mystudent as $row): ?>
<tr>
<td><?php echo $c; ?></td>
<td class="text-center"><?php echo $row['studid']; ?></td>
<td class="text-center"><?php echo $row['lname'].', '.$row['fname']; ?></td>
<td class="text-center"><?php echo $grade = $student->getstudentgrade($row['studid']);?></td>
</tr>
<?php $c++; ?>
<?php endforeach; ?>
<?php if(!$mystudent): ?>
<tr>
<td colspan="8" class="text-center text-danger">
<strong>*** No Result ***</strong>
</td>
</tr>
<?php endif; ?>
</tbody>
I'm in need of some help. I'm working in dreamweaver and I'm trying to insert values from my MySQL database into a table on my HTML page.
Dreamweaver generated these variables for me from the server behaviours
mysql_select_db($database_connection, $connection);
$query_mwAcc = "SELECT * FROM accounts";
$mwAcc = mysql_query($query_mwAcc, $connection) or die(mysql_error());
$row_mwAcc = mysql_fetch_assoc($mwAcc);
$totalRows_mwAcc = mysql_num_rows($mwAcc);
Now what I need help with is what to put into the while loop for my PHP script, this is what I have so far
<table class="table table-bordered">
<?php while (): ?>
<tr>
<td><?php echo $row['id'] ?></td>
</tr>
<?php endwhile; ?>
</table>
You need to write your fetch command within the while loop itself.
$query_mwAcc = "SELECT * FROM accounts";
$mwAcc = mysql_query($query_mwAcc, $connection) or die(mysql_error());
while($row_mwAcc = mysql_fetch_assoc($mwAcc)) {
?>
<tr>
<td><?php echo $row_mwAcc['id'] ?></td>
</tr>
<?php } ?>
</table>
With an update to use PDO you can change the while loop into a foreach on the query result. PDO should be used over mysql_ interface methods, due to deprecation: Why shouldn't I use mysql_* functions in PHP?
<?php
$dbh = new PDO('mysql:host=...;dbname=...', $user, $pass);
$results = $dbh->query('SELECT * FROM accounts');
?>
<table class="table table-bordered">
<?php foreach ($results as $row): ?>
<tr>
<td><?php echo $row['id'] ?></td>
</tr>
<?php endforeach; ?>
</table>
I have several MySQL tables that are dynamically generated into a html table one table at a time through the code below. However, the tables don't have the same columns. i.e. One table has a description column, whereas the other does not.
Is the following code the best way to have all the possible MySQL columns among the various tables in the script but only show the MySQL columns that exist for the selected table? I feel like I'm redundant by writing "isset" for every column. Thanks!
<?php
$query = " SELECT * FROM $tablename ";
$query_select = mysqli_query($con,$query);
while($row = mysqli_fetch_array($query_select)) {
?>
<table>
<tr>
<?php if(isset($row['name'])){ ?>
<td><?php echo $row['name'];?></td>
<?php } ?>
<?php if(isset($row['description'])){ ?>
<td><?php echo $row['description']?></td>
<?php } ?>
</tr>
</table>
You might want to make your code adapt to the fields in the result set:
<?php
$result = mysqli_query($con,$query);
$fields = mysqli_fetch_fields($result);
$myaliases = array(
'column_id' => 'id'
);
?>
<table>
<tr>
<?php foreach ($fields as $field): ?>
<th><?php echo $myaliases[$field->name] ?: $field->name; ?></th>
<?php endforeach; ?>
</tr>
<?php while($row = mysqli_fetch_array($result)): ?>
<tr>
<?php foreach ($fields as $field): ?>
<td><?php echo $row[$field->name]; ?></td>
<?php endforeach; ?>
</tr>
<?php endwhile; ?>
</table>
Re comments:
I've added code above to print a table row for column headings.
I've also included an example of mapping a field name column_id to a table heading id in the output. If I define no alias for a given column, it defaults to the original field name by using the PHP 5.3 operator ?:
You could alternatively define column aliases in your SQL query like SELECT column_id AS id ...
See http://www.php.net/manual/en/mysqli-result.fetch-fields.php
You can foreach the array instead.
<?php
$query = " SELECT * FROM $tablename ";
$query_select = mysqli_query($con,$query);
?>
<table>
<?php while($row = mysqli_fetch_array($query_select, MYSQLI_ASSOC)) { ?>
<tr>
<?php foreach($row as $key => $value) { ?>
<td><?=$value?></td>
<?php } //Endforeach ?>
</tr>
<?php } //Endwhile ?>
</table>
If you need to print labels you can also use an associative array and an additional iteration to do that as well.
<?php
$query = " SELECT * FROM $tablename ";
$keys = array('name' => 'Name Label', 'description' => 'Description Label');
$query_select = mysqli_query($con,$query);
$i = 0;
?>
<table>
<?php while($row = mysqli_fetch_array($query_select, MYSQLI_ASSOC)) { ?>
<?php if($i == 0) { ?>
<tr>
<?php foreach($row as $key => $value) { ?>
<td><b><?=$keys[$key]?></b></td>
<?php } //Endforeach ?>
</tr>
<?php } $i++; //Endif ?>
<tr>
<?php foreach($row as $key => $value) { ?>
<td><?=$value?></td>
<?php } //Endforeach ?>
</tr>
<?php } //Endwhile ?>
</table>
You could just loop through the results. However, that would not perform any checks. Most likely, you'll have to do something like this, depending on what you're actually getting from the database.
<?php foreach ($row as $field): ?>
<?php if ($field): ?>
<td><?php echo $field; ?></td>
<?php endif; ?>
<?php endforeach; ?>
Edit: In keeping in line with the comment you added above, you could simply remove the if clause.
not sure if this is what you need,
but you can use indexes instead for the column instead of names:
<?php
$query = " SELECT * FROM $tablename ";
$query_select = mysqli_query($con,$query);
while($row = mysqli_fetch_array($query_select)) {
echo $row[0] ." ".$row[1]." ".$row[2]
}
?>
mysql_fetch_array
possible formating:
<table>
<?php
$query = " SELECT * FROM $tablename ";
$query_select = mysqli_query($con,$query);
while($row = mysqli_fetch_array($query_select)) { ?>
<tr>
<?php for(var $i=0; $i < count($row); $i++){
echo "<td>". $row[i] ."</td>";
} ?>
</tr>
<?php } ?>
</table>
I want to populate all the data from my database to a table using <?php foreach; ?> but I can't get it to work. Please check my code:
controller
$data['query'] = $this->db->query('SELECT * FROM users');
$this->load->view('users_view',$data);
View
<?php foreach ($query->result_array() as $row)
{ ;?>
<tr>
<td><?php echo $row['usrID'];?></td>
<td><?php echo $row['usrName'];?></td>
<td><?php echo $row['usrPassword'];?></td>
</tr>
<?php } ?>
<?php endforeach; ?>
I would reccommend the alternative syntax for your foreach in the view...
It looks like you should be having some syntax errors the way you have it.
<?php foreach ($query->result_array() as $row): ?>
<tr>
<td><?php echo $row['usrID'];?></td>
<td><?php echo $row['usrName'];?></td>
<td><?php echo $row['usrPassword'];?></td>
</tr>
<?php endforeach; ?>
EDIT - to point out your syntax issues.
<?php foreach ($query->result_array() as $row)
{ ;?> //<---- semicolon?
<tr>
<td><?php echo $row['usrID'];?></td>
<td><?php echo $row['usrName'];?></td>
<td><?php echo $row['usrPassword'];?></td>
</tr>
<?php } ?>
<?php endforeach; ?> //<--- no need for this when using regular foreach
This first semicolon would be like writing a foreach like this...
foreach ($array as $ele) { ; //<--this would throw an error just like it should above.
//do stuff
}
Opinion aside from the point of the question
You should be processing your data in the controller and simply sending an array of data to be displayed in the view, not the whole query object.
so...
Controller
$query = $this->db->query('SELECT * FROM users');
$data['users'] = $query->result_array();
$this->load->view('users_view',$data);