PHP 7.2 Cannot use string offset as an array in eval - php

Question

The code was working in php 7.0 . I am getting error after moved to 7.2 version .
I need help in understand this .
I have an $map and $tempArray
print_r value of $locMap is given below
Array
(
[1] => Array
(
[ID] => 1
[LEVEL] => 1
[NAME] => Operations1
[CLASS] => ["e2"]["00"]
)
[2] => Array
(
[ID] => 2
[LEVEL] => 1
[NAME] => POperations2
[CLASS] => ["e2"]["01"]
)
[26] => Array
(
[ID] => 26
[LEVEL] => 2
[NAME] => Operations3
[CLASS] => ["e2"]["01"]["e2"]["00"]
)
)
print_r value of $tempArray is as below
Array
(
[account] => Array
(
[0] => Array
(
[id] => 1000
[name] => Homes
[level] =>
[rno] => 9
)
)
)
Looping this $map as below
foreach ($map $rec=>$det) {
$dummyArray = array();
$dummyArray['id'] = $det['ID'];
$dummyArray['CLASS'] = $det['CLASS'];
eval("\$tempArray['account'][0]".$det["CLASS"]." = \$dummyArray;");
}
Error: Cannot use string offset as an array in *************: eval()'d code:1
Inside eval function, "\$tempArray['account'][0]" is a string and is concatenating with the string again.
Why do I get the error in this case?
Help me understand this and how do I fix this issue ?

Answer 1

I believe the problem comes your concatenation of "\$tempArray['account'][0]".$det["CLASS"]." = \$dummyArray;". If you output the string, you can see what is evaluated. Most probably, you forgot [] around $det["CLASS"]. In your case, the first part might be a string, not an array.
By the way, I am not sure to understand what you want to do but I am not sure you use the easiest way.
I do not understand why it worked with php7.0.