I have two related tables, posts and hidden_posts, where posts.id corresponds to hidden_posts.post_id.
In my posts model I have this relation to return a record if the post should be hidden:
public function getHiddenPosts()
{
return $this->hasOne(HiddenPost::className(), ['post_id' => 'id']);
}
Now I need to return all posts that are NOT hidden. So I am looking for the equivalent of this pseudo code:
return $this->hasNone(HiddenPost::className(), ['post_id' => 'id'])->all();
Which is saying, "show me all posts that are not in the hidden_posts table".
So does this use an outer join query or is there a statement that I can't find do do this in one line?
You can do it this way. Get all posts that are not listed in Hidden table:
$posts = Post::find()
->andFilterWhere(['not in',
'post.id',
HiddenPost::find()
->select(['hidden_post.post_id'])
->all();
In any case, it is best to proceed from the raw SQL statement. Write a statement that satisfies your results and transfer it to ActiveRecord query.
Post items could be retrieved using an inner join
$res = Post::find()
->select('post.*')
->innerJoin('hdn_post', '`post`.`id` = `hdn_post`.`post_id`')
->all();
It could be good practice using yii2 owned function instead of adding queries inside the model such as using select queries in your model.
Instead you can use ORM functions in yii2 has already done by gii inner functions created for to make u=your work easy.
Add * #property YourModel $hidden_post
and inside this model add you post_id such as ( * #property integer $post_id ) to create relation.
public function getHiddenPosts($hidden_post) {
return $this->find()->joinWith('hidden_post')
->where(['hidden_post' => $hidden_post])
->all();
}
You could retrive the Post items using an inner join
$posts = Post::find()
->select('post.*')
->innerJoin('hidden_post', '`post`.`id` = `hidden_post`.`post_id`')
->all();
for not hidden then use left join and check for null result of related table
$posts = Post::find()
->select('post.*')
->leftJoin('hidden_post', '`post`.`id` = `hidden_post`.`post_id`')
->where('ISNULL(`hidden_post`.console_id)')
->all();
Related
I have the following relationships in models:
Product.php
public function skus()
{
return $this->belongsToMany(Sku::class);
}
Sku.php
public function prices()
{
return $this->hasMany(Price::class);
}
I need to get an attribute indicating whether a product has at least one price or not (in the extreme case, just the number of prices).
Product::withExists('sku.prices') or Product::withCount('sku.prices')
I know about this repository https://github.com/staudenmeir/belongs-to-through, but I prefer to use complex query once
UPDATE: I have already written a sql query for this purpose, but I don't know how to do it in Laravel:
SELECT
*,
EXISTS (SELECT
*
FROM prices
INNER JOIN skus
ON prices.sku_id = skus.id
INNER JOIN product_sku
ON skus.id = product_sku.sku_id
WHERE products.id = product_sku.product_id
) AS prices_exists
FROM products
Here you can get at least one record
$skuPrice = Sku::with('prices')
->has('prices', '>=', 1)
->withCount('prices')
->get();
I encountered a problem when trying to use with() function along with join:
$query = Model::query()->with([
'relationOne',
'relationTwo',
...
]);
$query->join(DB::raw("(
select *
from <models_table>
where <some_condition>
) as new_model"), 'new_model.id', '=', '<models_table>.id');
$query->paginate($rpp);
After paginate($rpp) call I received all items with appropriate relations appended, but without joined table (aka new_model). Is there a way to retrieve new_model along with relations ?
Have you tried to add select statement to emphasize the tables you want to get?
$query->join(DB::raw("(
select *
from <models_table>
where <some_condition>
) as new_model"), 'new_model.id', '=', '<models_table>.id')
->select(['<models_table>.*', 'new_model.*']);
Please try the below code hope it will help you.
$query = Model::query()->with([
'relationOne',
'relationTwo',
...
])
$query = $query->join(DB::raw("(
select *
from <models_table>
where <some_condition>
) as new_model"), 'new_model.id', '=', '<models_table>.id')
$query = $query->paginate($rpp);
I am learning relationships in Laravel php framework and I am trying to build this query
SELECT * FROM users u INNER JOIN link_to_stores lts ON u.id=lts.user_id INNER JOIN stores s ON lts.store_id=s.store_id WHERE lts.privilege = 'Owner'
I built this in Model
Link_to_store.php
public function store()
{
return $this->belongsTo('App\Store');
}
public function user()
{
return $this->belongsTo('App\User');
}
User.php
public function store_links()
{
return $this->hasMany('App\Link_to_store');
}
Store.php
public function user_links()
{
return $this->hasMany('App\Link_to_store');
}
I tried this query but this only joins user and link_to_store table
$personal_stores = Auth::user()->store_links->where('privilege','=','Owner');
Now I am confused how to join store table too. Can anyone help with this?
Schema is like this
Stores Table
store_id store_name
Users Table
id name
Link_to_stores Table
id store_id user_id privilege
I suppose store_links is actually a pivot table. In this case, you can use belongsToMany(), this will automatically take care of the pivot table.
To do this, in your User model you change the store function to this:
function stores() {
return $this->belongsToMany('App\Store', 'store_links', 'user_id', 'store_id')->withPivot('privilege');
}
Because the primary key of stores is not id, you will have to define this in you Store model with the following line:
protected $primaryKey = 'store_id';
Now to get the stores for a user, you simply call
$stores = Auth::user->stores()->wherePivot('privilege', 'Owner')->get();
I am learning relationships in Laravel php framework and I am trying to build this query
SELECT * FROM users u INNER JOIN link_to_stores lts ON u.id=lts.user_id INNER JOIN stores s ON lts.store_id=s.store_id WHERE lts.privilege = 'Owner'
You are trying to do a join here. You can do a join like this:
$stores = User::join('link_to_stores as lts', 'users.id', '=', 'lts.user_id')->join('stores as s', 'lts.store_id', '=', 's.id')->where('lts.privilege', 'Owner')->get();
But like Jerodev pointed out, it seems like Many to Many relationship might make more sense in your case. The difference is that relationship will actually execute 2 queries (1 for original model, 1 for relationship). It will then attach the related models to the original model (which is extremely handy).
I have a Pivot table thats used to join two other tables that have many relations per hotel_id. Is there a way I can eagerload the relationship that pulls the results for both tables in one relationship? The raw SQL query, works correctly but when using belongsToMany the order is off.
Amenities Pivot Table
id
hotel_id
distance_id
type_id
Distance Table
id
name
Type Table
id
name
RAW Query (This works fine)
SELECT * FROM amenities a
LEFT JOIN distance d ON a.distance_id = d.id
LEFT JOIN type t ON a.type_id = t.id WHERE a.hotel_id = ?
My "Hotels" Model is using belongsToMany like so
public function distance() {
return $this->belongsToMany('Distance', 'amenities', 'hotel_id', 'distance_id');
}
public function type() {
return $this->belongsToMany('Type', 'amenities', 'hotel_id', 'type_id');
}
This outputs the collection, but they are not grouped correctly. I need to loop these into select fields side by side as entered in the pivot table, so a user can select a "type" and the "distance", but the order is off when using the collection. The raw query above outputs correctly.
Hotels::where('id','=','200')->with('distance', 'type')->take(5)->get();
Ok Solved it. So apparently you can use orderBy on your pivot table. Incase anyone else has this issue this is what I did on both relationships.
public function distance() {
return $this->belongsToMany('Distance', 'amenities', 'hotel_id', 'distance_id')->withPivot('id')->orderBy('pivot_id','desc');
}
public function type() {
return $this->belongsToMany('Type', 'amenities', 'hotel_id', 'type_id')->withPivot('id')->orderBy('pivot_id','desc');
}
It's not really a great practice to include other query building steps in the relationship methods on your models. The relationship method should just define the relationship, nothing else. A cleaner method is to apply eager load constraints. (scroll down a bit) Consider the following.
Hotels::where('id', 200)->with(array(
'distance' => function ($query)
{
$query->withPivot('id')->orderBy('pivot_id','desc');
},
'type' => function ($query)
{
$query->withPivot('id')->orderBy('pivot_id','desc');
},
))->take(5)->get();
If you find that you are eagerly loading this relationship in this way often, consider using scopes to keep things DRY. The end result will allow you to do something like this.
Hotels::where('id', 200)->withOrderedDistance()->withOrderedType()->take(5)->get();
P.S. Your models should be singular. Hotel, not Hotels. The model represents a single record.
Solved by using ->withPivot('id')->orderBy('pivot_id','desc');
Posted answer in the question.
I am trying to get a single column of an inner joined model.
$items = Item::with('brand')->get();
This gives me the whole brand object as well, but I only want brand.brand_name
$items = Item::with('brand.brand_name')->get();
Didn´t work for me.
How can I achieve this?
This will get related models (another query) with just the column you want (an id, see below):
$items = Item::with(['brand' => function ($q) {
$q->select('id','brand_name'); // id is required always to match relations
// it it was hasMany/hasOne also parent_id would be required
}])->get();
// return collection of Item models and related Brand models.
// You can call $item->brand->brand_name on each model
On the other hand you can simply join what you need:
$items = Item::join('brands', 'brands.id', '=', 'items.brand_id')
->get(['items.*','brands.brand_name']);
// returns collection of Item models, each having $item->brand_name property added.
I'm guessing Item belongsTo Brand, table names are items and brands. If not, edit those values accordingly.
Try this:
$items = Item::with(array('brand'=>function($query){
$query->select('name');
}))->get();