SQL request or php solution to manage employers - php

Question

My entity :
class User{
id : int
name : string
boss : User()
}
I want to create a function that return an array() of users that work under a giving user.
example :
public function MyEmployers( User $user , array $usersList )
{
$myEmployers = array();
...
return $myEmployers;
}
$results = $this->myEmployers ( $employer1 , $allEmployers)
dump ( $results );
$results = [ 4 , 5 , 6 ];
I found a solution if someone can improve it feel free :
public $tree = array();
public function MyEmployers(User $user)
{
$superior_key_id = array();
$all_users = $this->getallusers();
$id = $user->getId();
foreach ($all_users as $user) {
if ($user->getSuperior())
$superior_key_id[$user->getSuperior()->getId()][] = $user;
}
$this->getSubEmployee($this->getUser(), $superior_key_id);
return ($this->tree);
}
public function getSubEmployee($user, $superior_key_id)
{
if (isset($superior_key_id[$user->getId()])) {
foreach ($superior_key_id[$user->getId()] as $user) {
$this->tree[] = $user;
$this->getSubEmployee($user, $superior_key_id);
}
}
return $user;
}
this one will get all bosses if you're interested :
public function MyBosses(User $user)
{
$bosses = array();
while ($user->getSuperior()) {
array_push($bosses, $user->getSuperior());
$user = $user->getSuperior();
}
return $bosses;
}

Answer 1

You could set up a one-to-many relationship between boss and employee
So you're user class could look like:
class User{
/**
* #ORM\Id()
* #ORM\GeneratedValue()
* #ORM\Column(type="integer")
*/
private $id;
/**
* #ORM\Column(type="string")
*/
private $name;
/**
* #ORM\ManyToOne(targetEntity="App\Entity\User", inversedBy="employee")
*/
private $boss;
/**
* #ORM\OneToMany(targetEntity="App\Entity\User", mappedBy="boss")
*/
private $employees;
public function __construct()
{
$this->employees = new ArrayCollection();
}
public function getId(): ?int
{
return $this->id;
}
public function getName(): ?string
{
return $this->name;
}
public function setName(string $name): self
{
$this->name = $name;
return $this;
}
/**
* #return Collection|employees[]
*/
public function getEmployees(): Collection
{
return $this->employees;
}
public function addEmployee(employee $employee): self
{
if (!$this->employees->contains($employee)) {
$this->employees[] = $employee;
}
return $this;
}
public function removeEmployee(employee $employee): self
{
if ($this->employees->contains($employee)) {
$this->employees->removeElement($employee);
}
return $this;
}
public function getBoss(): ?Usesr
{
return $this->boss;
}
public function setBoss(?User $boss): self
{
$this->boss = $boss;
return $this;
}
}
You would need to set up the database relationship with the symfony make:entity command.
To get all employeers under a user, you could do something like:
function getAllEmployeesUnder(User $user)
{
$allEmployees = [];
foreach ($user->getEmployees as $employee) {
$allEmployees[] = $employee;
$allEmployees = array_merge($allEmployees, $this->getAllEmployeesUnder($employee));
}
return $allEmployees;
}