Invalid input syntax for integer: "" - php

Question

I have a problem, to build INSERT PHP file with HTML form code. When I drop from HTML form, then this error pops out ""invalid input syntax for integer: "" LINE 2:""
in all code, I comment every single line and nothing.
There is my PHP script
`
$order_nr = pg_escape_string($_POST['order_nr']);
$date = pg_escape_string($_POST['date']);
$place = pg_escape_string($_POST['place']);
$service = pg_escape_string($_POST['service']);
$Vards = pg_escape_string($_POST['vards']);
$Uzvards = pg_escape_string($_POST['uzvards']);
$phone = pg_escape_string($_POST['phone']);
$email = pg_escape_string($_POST['email']);
$veids = pg_escape_string($_POST['veids']);
$passw = pg_escape_string($_POST['passw']);
$papildaprikojums = pg_escape_string($_POST['papildaprikojums']);
$save_info = pg_escape_string($_POST['save_info']);
$defekts = pg_escape_string($_POST['defekts']);
$query = " INSERT INTO serviss (order_nr, place, service, vards, uzvards, email, veids, passw, save_info, papildaprikojums, defekts)
VALUES ('$order_id', '$place', '$service', '$vards', '$uzvards', '$email', '$veids', '$passw', '$papildaprikojums', '$save_info', '$defekts') " ;
$result = pg_query($query);
if (!$result) {
$errormessage = pg_last_error();
echo "Error with query: " . $errormessage;
exit();
}
printf ("These values were inserted into the database - %s %s %s", $order_id);
pg_close();
There is my HTML form code
<form action="serviss.php" method="post" >
<div class="ievade">
Pasūtijuma numurs : <input type="text" size="5" name="order_id"> <br><br>
Pieņemšanas datums : <input type="date" data-date="" data-date-format="DD MMMM YYYY" value="2015-08-09" name="date"> <br><br>
Pieņemšanas vieta : <select name="place">
<option value="Ausekļa_iela_9"> Ausekļa iela 9 </option>
</select> <br><br>
Pieņēma : <select >
<option value="service" name="Maris"> Māris </option>
<option value="service name="Toms"> Toms </option>
</select> <br> <br>
Klienta vārds : <input type="text" name="vards" size="5"> <br><br>
Klienta uzvārds : <input type="text" name="uzvards" size="5"> <br><br>
Klienta tel.nr.: <input type="tel" id="phone" size="6"> <br><br>
Klienta e-pasts: <input type="text" value="example#test.net" name="email">
<br><br>
Iekārtas veids: <input type="text" value="iekārta" name="veids" size="5"> <br><br>
Parole: <input type="text" name="passw" size="5"> <br><br>
</div>
<div class="checkbox">
Garantija: <br>
Ir
<input type="radio" name="garantija" value="Ir"> <br>
Nav <input type="radio" name="garantija" value="Nav">
<br> <br>
</div>
<div class="ievade">
Papildaprīkojums: <input type="text" name="papildaprikojums" > <br><br>
Papildus informācija: <input type="text" name="informacija">
<br> <br>
Saglabājamā informācija: <input type="text" name="save_info">
<br> <br>
Defekta apraksts: <input type="text" name="defekts">
</div>
</div>
<input type="submit" value="Submit">
</form>
I hope you can help me.
I use PostgreSQL 10.10

Answer 1

It's like you have mixed up the 'order_id' with 'order_nr'.
The name value attribute is 'order_id' so when you try to get it it is
$_POST['order_id'] not `$_POST['order_nr']`
It means that either you should say
$order_nr = pg_escape_string($_POST['order_id']);
In order to use the variable into the insert statement and then
$query = " INSERT INTO serviss (order_nr, place, service, vards, uzvards, email, veids, passw, save_info, papildaprikojums, defekts)
VALUES ('$order_nr', '$place', '$service', '$vards', '$uzvards', '$email', '$veids', '$passw', '$papildaprikojums', '$save_info', '$defekts') " ;
or you shoud say
$order_id = pg_escape_string($_POST['order_id']);
And then
$query = " INSERT INTO serviss (order_nr, place, service, vards, uzvards, email, veids, passw, save_info, papildaprikojums, defekts)
VALUES ('$order_id', '$place', '$service', '$vards', '$uzvards', '$email', '$veids', '$passw', '$papildaprikojums', '$save_info', '$defekts') " ;