How do i display php numbers like so?
1
21
321
4321
54321
654321
right now my code is like this and displays the following.
for ($i = 0; $i <= 5; $i++) {
for ($j = 5; $j > $i; $j--)
{ echo " ";
}
for ($l = 0; $l < $j; $l++){
}
for ($k = 1; $k <= $l; $k++) {
echo "$k";
}
echo "</br>";
}
Basically this shows the correct way of the pattern but does not the correct numbers in order.
1
12
123
1234
12345
The code seems to have too many loops, and can use str_repeat to simplify the logic and loop structure. The counter was dependent on another loop, and thus couldn't be easily changed. I have refactored it into the following:
$printOut = "";
$count = 5;
for ($i = 1; $i <= $count; $i++) {
$printOut = $i . $printOut;
echo str_repeat(" ", $count - $i) . $printOut;
echo "</br>";
}
Output:
1
21
321
4321
54321
Related
How to print this Pattern?
$number = 5;
for ($i=1; $i <= $number ; $i++) {
for ($j=$i; $j >= 1;$j--){
echo "0";
}
echo "\n";
}
Prints
0
00
000
0000
00000
I've tries like this, but i'm confused to print star and Zero char
for ($i=1; $i <= $number ; $i++) {
$sum = 0;
for ($j=$i; $j >= 1;$j--){
$sum +=$j;
}
echo $i ." => " .$sum ."\n";
}
Prints
1 => 1
2 => 3
3 => 6
4 => 10
5 => 15
You can use str_repeat to generate the strings of required length. Note that for triangular numbers (1, 3, 6, 10, 15, ...) you can generate the i'th number as i(i+1)/2:
$number = 5;
for ($i = 1; $i <= $number; $i++) {
echo str_repeat('*', $i * ($i + 1) /2) . str_repeat('0', $i) . PHP_EOL;
}
Output:
*0
***00
******000
**********0000
***************00000
Demo on 3v4l.org
For a more literal generation of the triangular part of the output (i.e. sum of the numbers from 1 to i), you could use this code which adds $i *'s and 1 0 to the output on each iteration:
$line = '';
$number = 5;
for ($i = 1; $i <= $number; $i++) {
$line = str_repeat('*', $i) . $line . '0';
echo $line . PHP_EOL;
}
Output:
*0
***00
******000
**********0000
***************00000
Demo on 3v4l.org
Here is another way, which uses a more literal reading of the replacement logic. Here, I form each subsequent line by taking the previous line, and adding the line number amount of * to the * section, and then just tag on a new trailing zero.
$line = "*0";
$max = 5;
$counter = 1;
do {
echo $line . "\n";
$line = preg_replace("/(\*+)/", "\\1" . str_repeat("*", ++$counter), $line) . "0";
} while ($counter <= $max);
This prints:
*0
***00
******000
**********0000
***************00000
The number of zeros are equal to $i in the for loop. So we just need to calculate the number of stars and then simply do a str_repeat
$count = 5;
for ($i=1; $i <= $count; $i++) {
$stars = 0;
for($j=1; $j <= $i; $j++) {
$stars = $stars + $j;
}
echo str_repeat('*', $stars).str_repeat('0', $i)."\n";
}
Output:
*0
***00
******000
**********0000
***************00000
$line = '';
for ($i = 1; $i <= 5; $i++) {
$line = str_repeat('*', $i) . $line . '0'; // **str_repeat()** --> getting string length
echo $line . PHP_EOL; // **PHP_EOL** ---> represents the endline character.
}
I want to create this:
12345
12341
12312
12123
11234
Above should be the output. My code is:
<?php
for ($i=5; $i >=1 ; $i--) {
for ($j=1; $j <=$i ; $j++) {
echo $j." ";
}
echo "<br>";
}
for ($y=1; $y <=4 ; $y++) {
for ($z=1; $z <=$y ; $z++) {
echo $z." ";
}
echo "<br>";
}
?>
It displays output like:
12345
1234
123
12
1
1
12
123
1234
What did I do wrong?
You're pretty close. The pattern says: for each row, iterate up to n - i with numbers 1.. and then iterate to i starting again from 1... Your code prints the first bit correctly, but it's adding a line break before writing the second part.
<?php
$n = 5;
for ($i = 0; $i < $n; $i++) {
for ($j = 1; $j <= $n - $i; $j++) {
echo $j;
}
for ($j = 1; $j <= $i; $j++) {
echo $j;
}
echo "\n";
}
Output:
12345
12341
12312
12123
11234
I have this for loop:
for($i = 1; $i <= 7; $i++) {
echo $i . "<br>";
}
Which outputs:
1
2
3
4
5
6
7
Now what I want is to add all the previous numbers on each loop. So the output should be:
1
2 // add all above to get this number
3 // add all above to get this number
6 // add all above to get this number
12 // add all above to get this number
24 // add all above to get this number
48 // add all above to get this number
96 // add all above to get this number
...etc
The first and second number doesn't necessarily have to be in the loop, that can be defined manually outside.
What I don't want is to add the value of $i on each loop, but to add all the previous numbers on each loop.
I have tried summing up using this code:
$sum = 0;
for($i = 1; $i <= 5; $i++) {
$sum = $sum + $i;
echo $sum . "<br>";
}
But I get this output:
1
3
6
10
15
21
28
How can I achieve my desired output?
Try this
<?php
$results = [];
for ($i = 0; $i <= 7; $i++){
$currentResult = 0;
if ($i < 2){
$currentResult = $i+1;
}
else{
foreach($results as $currenNumber){
$currentResult += $currenNumber;
}
}
echo $currentResult . '<br>';
$results[] = $currentResult;
}
?>
<?php
$value = 0;
for($i = 1; $i <= 8; $i++) {
if($value < 3){
$value = $value + 1;
} else{
$value = $value * 2;
}
echo $value . '<br>';
}
?>
My niece is trying to create one for-loop (php), that results in this:
* 12345678910987654321
example for loop she tried:
for ($i = 1; $i <= 10; $i++ , $i = 10; $i <= 1; $i--) {
echo $i . ' ';
}
She can only use if's and elseif's. I'm not a programmer and can't really help her. Any ideas how this could be achieved in php?
Any information would be greatly appreciated.
The key is to add a variable instead of a number, then reverse that number when $i hits 10.
for($i = 1, $j = 1; $i> 0; $i+=$j) // Start i at 1, and j at 1
{
echo $i;
if($i == 10)
$j = -1; // i has hit 10, so use -1 to start subtracting
}
Another possibility is to loop up to 20, printing $i for the ascending part and 20 - $i for the descending.
for ($i = 1; $i < 20; $i++) {
if ($i <= 10) {
echo $i;
} else {
echo 20 - $i;
}
}
I have a for loop, where $i is 0, and it will run until $i reaches 4. I am trying to make a code that would output numbers in an order like this: 01, 11, 02, 12, 03, 13... etc... Now, the thing is next: when $i is 1, the script should make an order of those number in the boundaries of 1 and 20. When $i is 2, it would be 21 to 40, etc.
I've tried many things (mostly deleted), could not come up with anything that would work the right way.
The inner loop:
for ($j = 0; $j != 10; ++$j)
{
echo $j + 1 + 10 * ($i - 1);
echo $j + 1 + 10 * $i;
}
Try this piece of code;
<?php
$num = 4;
for($i=1;$i<($num + 1);$i++){
$string = "0" . $i . ", 1" . $i;
if($i<$num){
$string .= ", ";
}
echo $string;
}
?>
printf will format your numbers with a leading zero, as specified:
<?php
$format = "%02d ";
for ($i = 1; $i <= 4; $i++) {
$k = 2 * $i - 1;
for ($j = 1; $j <= 10; $j++) {
printf($format, ($k - 1) * 10 + $j);
printf($format, $k * 10 + $j);
}
echo "<br />";
}
?>
You can try:
<?php
$ten = 10;
for ($i = 0; $i<=4; ++$i)
{
echo "0".$i." , ";
echo $ten + $i."<br/>";
}
?>
Only change the range of $i
Thanks