How to use break or contnue - php

Question

I have an array of admission and each student has multiple entry of payment.
Like Admission=[1,2,3,4,5,6] this is admission ids,
and Payment=[[1->1,5,6,2],[2->2,3],[3->4,7,8] this is admission id->payment_ids
foreach($admission as $a)
{
$payment=DB::table('payement')->where('admission_id',$a->admission_id)->get();
foreach($payment as $p)
{
// Here i wan if payment_date <= today_date
// 1. Add all payment
// 2. Else Go to the next admission id
}
}

Answer 1

It sounds like you're looking for something like this:
foreach($admission as $a)
{
$payment = DB::table('payment')->where('admission_id', $a->admission_id)->get();
$totalPayment = 0;
foreach($payment as $p)
{
if (\Carbon\Carbon::parse($p->payment_date)->lessThanOrEqualTo(\Carbon\Carbon::now())) {
$totalPayment += $p->amount;
}
}
}
Inside of the foreach loop on $payment the code above uses Carbon to compare the dates. It looks like you're using Laravel's Eloquent so you should have Carbon available in your application since it's a Laravel dependency. I use Carbon to compare the dates because it knows more about dates than I do.
Next, if it's true that payment_date is less than or equal to the current date then it will add it to the $totalPayment for that admission. Otherwise, it will move onto the next payment. This presumably makes using continue or break unnecessary unless I am misunderstanding something.
I'm not sure what you want to do with $totalPayment. Right now it will be calculated for each admission and then lost.
If you want to find the total payment across all admissions you should move $totalPayment = 0 to the line above foreach($admission as $a).
If you want to find the total payment for each admission you could set a totalPayment on each admission $a->total_payment = $totalPayment. I would then change $totalPayment = 0 to $a->total_payment = 0 and change $totalPayment += $p->amount to $a->totalPayment += $p->amount.