PDO - Shows only 1 result in Table, not all with same ID - php

Question

I have at the moment 2 results in my MySQL Database with same user_id and I want echo all in my HTML table with PDO, but it shows everytime only 1 result, not all.
<?php
$querytest = "SELECT o.output_valu,
p.amount,
p.amount_all,
p.order_id,
p.datetime
FROM allusers a
INNER JOIN order_history o
ON a.account_number = o.account_number
INNER JOIN paymentall p
ON o.output_vl_id = p.output_vl_id
WHERE a.account_number = :account_num
ORDER BY p.datetime";
$statementtest = $conn->prepare($queryoutgo);
$statementtest->bindParam(':account_num', $account_num);
$statementtest->execute();
$test_result = $statementtest->fetchAll();
foreach ($test_result as $row) {
$outputtest = $row['output_valu'];
}
?>
<table>
<tr>
<th>Test</th>
</tr>
<tr>
<td><?php echo $outputtest; ?></td>
</tr>
</table>
With print_r($test_result); it shows my 2 results in array, but why not with my code?
I worked always with mysqli not PDO in the past, maybe someone here can help me :)

Answer 1

In your foreach block you overwrite $outputtest every iteration. This means only the last result will be displayed. Depending on if you want to show each result on a separate row or if you want all the results together in one cell, you should either create the cells in the foreach or concatenate all the results together.
EDIT:
What I think you want is this:
$querytest = "SELECT o.output_valu, p.amount, p.amount_all, " .
"p.order_id, p.datetime " .
"FROM allusers a inner join order_history o " .
"ON a.account_number = o.account_number " .
"INNER JOIN paymentall p " .
"ON o.output_vl_id = p.output_vl_id " .
"WHERE a.account_number =:account_num " .
"ORDER BY p.datetime ";
$statementtest = $conn->prepare($queryoutgo);
$statementtest->bindParam(':account_num', $account_num);
$statementtest->execute();
$test_result = $statementtest->fetchAll();
?>
<table>
<tr>
<th>Test</th>
</tr>
<?php foreach($test_result as $row) { ?>
<tr><td><?= $row['output_valu']; ?></td></tr>
<?php } ?>
</table>