SQL UPDATE and SET on phpmyadmin depending on the values - php

Question

Would like to know how come my SQL update case is not functioning correctly.
I already have values:
$usrcustomerid = 110;
$search = 'face';
Looking for a fix on my CASE in SET because there is no update when this SQL triggers
SQL Update code
public function UpdateUserSearch($db, $usrcustomerid, $search) {
$stmt = $db->prepare(
" UPDATE usr_customer
SET search_counter = (CASE WHEN search_counter = 1 THEN 2
WHEN search_counter = 2 THEN 3
WHEN search_counter = 3 THEN 1 END),
search1 = (CASE WHEN search_counter = 1 THEN $search END),
search2 = (CASE WHEN search_counter = 2 THEN $search END),
search3 = (CASE WHEN search_counter = 3 THEN $search END)
WHERE usrcustomerid = $usrcustomerid "
);
$stmt->bindValue(':usrcustomerid', $usrcustomerid, PDO::PARAM_INT);
$stmt->bindValue(':search', $search, PDO::PARAM_STR);
$stmt->execute();
$rowAffected = $stmt->rowCount();
return $rowAffected;
}
table usr_customer
In the picture below, the user's search_counter is set to one and the three search columns have no value inside, so the code, based on my logic in my CASE, should have my "$search" value insert in "search1" and update search_counter from 1 to 2.
PS I am aware of SQL Injection, please do not answer with a reminder because I am trying to get my code working first.

Answer 1

This is not a SQL issue, it is a PHP issue. The values you are replacing in your SQL Query should be prefixed with : instead of $.
" UPDATE usr_customer
SET search_counter = (CASE WHEN search_counter = 1 THEN 2
WHEN search_counter = 2 THEN 3
WHEN search_counter = 3 THEN 1 END),
search1 = (CASE WHEN search_counter = 1 THEN :search END),
search2 = (CASE WHEN search_counter = 2 THEN :search END),
search3 = (CASE WHEN search_counter = 3 THEN :search END)
WHERE usrcustomerid = :usrcustomerid "
See: PHP Documentation