How would i not update a image from my files and database? - php

Question

I run into this problem sometimes with the update form which contains files to upload to a database.
now to explain :I have a submit form with two input Fields. The first input is the name of the image , and the second one is the image itself. The form is submitted to upload.php as you can see the code
upload.php
if(isset($_POST['submit'])){
include 'connection.php';
$imageName=$_POST['imageName'];
$image=$_FILES['image'];
$imageTmpName=$image['tmp_name'];
$imageName=$image['name'];
$imageExt=explode('.',$imageName);
$imageExt=strtolower(end($imageExt));
$newImageName=uniqid('',true).'.'.$imageExt;
$path='C:/xampp/htdocs/test/img/'.$newImageName;
if(move_uploaded_file($imageTmpName,$path)){
echo 'file moved';
}
$query="INSERT INTO imagedata(imageName,image) VALUES ('$imageName','$newImageName')";
if(mysqli_query($conn,$query)){
echo 'data posted to database';
}
}
You can see from the code that I am moving the image temporary name to my path and in the same time I'm and storing the new image name into the database.
I am using the same principle update the image name and the image itself in a new form that is submit to update.php as show below:
if(isset($_POST['update'])){
include 'connection.php';
$uImageName=$_POST['uimageName'];
$uImage=$_FILES['uImage'];
$uImageTmpName=$Image['tmp_name'];
$uImageName=$uImage['name'];
$uImageExt=explode('.',$uImageName);
$uImageExt=strtolower(end($uImageExt));
$uNewImageName=uniqid('',true).'.'.$uImageExt;
$uPath='C:/xampp/htdocs/test/img/'.$uNewImageName;
if(move_uploaded_file($uImageTmpName,$uPath)){
echo 'file updatet';
}
$query="UPDATE imagedata SET imageName='$uImageName',image='$uNewImageName'";
if(mysqli_query($conn,$query)){
echo 'data updatet to database';
}
}
Remember that I am querying database and echo the values inside the input field values itself.Now the problem occurs in the update.php file, whenever i update the image name without uploading any new image, it will update the database with a blank image and return that to my update form.
So what i want to do is whenever i want to update the database without an image from my update form, i want the previous uploaded image to remain the same. Or if i want a new image to be uploaded to the database then i want the database to be updated with the new image and also to delete the old image that i have previous uploaded.
I want to thank you for your help with this

Answer 1

Simple way to keep old image if new image not selected!
Here is the easy way, create a hidden input and echo your old image name in value, and keep new image value empty as follows:
<input type="hidden" name="YourOldFile" value="YourOldFileName">
<input type="file" name="YourNewFile" value="">
Then do if statement in PHP part:
if(!empty($POST['YourNewFile'])) {
$newFile = $_POST['YourNewFile'];
// Then do your update query with uploading new image here and delete old image from the server.
} else {
$YourOldFileName = $_POST['YourOldFile'];
//Then do your query here with oldname and do not delete image from server.
}
Note: you can do same for insert and update, and you need to set where clause for update query.
UPDATE :
Displaying with or without image extention is a different question because its a part of your upload code, and how you save and display.
So, your codes in page looks like this :
include 'connection.php';
if(!empty($_FILES['uImageName'])) {
// Then do your update query with uploading new image here and delete old image from the server.
if(isset($_POST['update'])){
$uImageName=$_FILES['uimageName'];
//Your upload code doesnt look right coded to me, I would use an upload class, You can search for how to upload image
// I use verot upload class its very simple.
$uImageTmpName=$Image['tmp_name'];
$uImageName=$uImage['name'];
$uImageExt=explode('.',$uImageName);
$uImageExt=strtolower(end($uImageExt));
$uNewImageName=uniqid('',true).'.'.$uImageExt;
$uPath='C:/xampp/htdocs/test/img/'.$uNewImageName;
if(move_uploaded_file($uImageTmpName,$uPath)){
echo 'file updated';
}
$query="UPDATE imagedata SET imageName='$uImageName'";
if(mysqli_query($conn,$query)){
echo 'data updatet to database';
}
}
} else {
$YourOldFileName = $_POST['YourOldFile'];
//Then do your query here with oldname and do not delete image from server.
//Solution 1. You can update image column with your old image name.
$query="UPDATE imagedata SET image='$YourOldFileName'";
//Solution 2. You can update all other columns without image column dont update image column and dont include image column in your query.
$query="UPDATE imagedata SET yourColumnName='$DataYouWantToInsert'";
if(mysqli_query($conn,$query)){
echo 'data updatet to database';
}
}
<form>
/*Your inputs here*/
<input type="hidden" name="YourOldFile" value="YourOldFileName">
<input type="file" name="YourNewFile" value="">
/*Your buttons*/
</form>
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