PHP - Problems on Change MySQL-enquiry from mysql_query to PDO - php

Question

Last year I have taken over the support of a webpage. This page in parts is still written with mysql_querys, which is the reason the server still runs on PHP 5.6 (which causes unnecessary cost). To finally change the server to PHP 7.x, I'm actually working on change the scripts which still use mysql_query to PDO. In parts this worked without any problem. But now one of the scripts still won't work after a long search of mistakes. So I hope, that someone in this community can take a look at the script and help my finding the error.
The MysQL-query surely is correct and gives a result. So the problem must be at the PDO-syntax.
This was the Script how it is used till now (only the output is simplified by me):
$link = mysql_connect($sHost, $sUser, $sPass);
mysql_select_db($sDBName, $link);
$sql1 = "SELECT * FROM `" . $table . "` WHERE `index` = " . $_REQUEST['id'];
$erg1 = mysql_query($sql1, $link) or die("Fehler: " .mysql_error());
$result1[0] = mysql_fetch_array($erg1);
echo $result1[0]["kreis"];
Result:
Berlin
This is the script change to PDO now:
if(isset($_GET['id'])) {
$id = $_GET['id'];
} else {
die("Bitte eine ?id übergeben");
}
$pdo2 = new PDO(sprintf('mysql:host=%s;dbname=%s', $sHost, $DBName), $sUser, $sPass);
$utf8 = $pdo2->prepare("SET NAMES UTF8");
$result_check = $utf8->execute();
$table = "orte_bb";
$sql1 = "SELECT * FROM `" . $table . "` WHERE `index` = ?";
$statementbb = $pdo2->prepare($sql1);
$erg1 = $statementbb->execute(array($id));
while ($result1 = $statementbb->fetch(PDO::FETCH_ASSOC))
{
echo $result1['kreis'];
}
Result:
empty array
This means, that the PDO $statementbb seams to file no data set. The question, I can't answer to me, ist, why this happens.
I would be happy, when some can take a look and give me a clue.
Thanks
bagira41berl

Answer 1

Now I found the error myself (which stuck in the detail). The error is in the first PDO-line:
$pdo2 = new PDO(sprintf('mysql:host=%s;dbname=%s', $sHost, $DBName), $sUser, $sPass);
It's the variable, which is used for the database-name, where 1 letter is missed, which didn't stand out mutch. I korrected the syntax of this line to:
$pdo2 = new PDO(sprintf('mysql:host=%s;dbname=%s', $sHost, $sDBName), $sUser, $sPass);
And now it works.
Best reagards
baerlinerbaer