Getting the First Sunday in any Given Year in PHP [duplicate] - php

Question

I need to use PHP DateTime to get the first day of the current year. I've tried:
$year = new DateTime('first day of this year');
var_dump($year);
But this seems to be returning the first day of the current month: 2014-09-01 09:28:56
Why? How do I correctly get the first day of the current year?

Answer 1

Your relative date format 'first day of this year' is correct by returning the first day of the month because of the definition of first day of:
Sets the day of the first of the current month. This phrase is best
used together with a month name following it. (See PHP-doc)
To get the first day of the current year with the relative format you can use something like this:
'first day of January ' . date('Y')

Answer 2

Or use only text in the strtotime function:
date('Y-m-d', strtotime('first day of january this year'));

Answer 3

echo date('l',strtotime(date('Y-01-01')));

Answer 4

You can get the current date and then set day and month to 1:
$year = new DateTime();
$year->setDate($year->format('Y'), 1, 1);
Optionally, you can set the time to midnight:
$year->setTime(0, 0, 0);

Answer 5

If you want to get first day of current year just use this code
echo date("l", strtotime('first day of January '.date('Y') ));

Answer 6

Just wanted to record some nuance with the answer by lorem monkey
The suggested method might cause issues with when using time zones.
scenario: consider current system time is 2018-01-01 00:20:00 UTC and system default time zone is set to UTC.
date('Y') will give you 2018
if you are doing something like:
$startDate = new DateTime('first day of january '.date('Y'), new DateTimeZone('America/New_York'));
This will compute to 'first day of january 2018' but you actually needed the first date of your current year in America/New_York, which is still 2017.
Stop dropping the ball man, its not new year yet!
So it is better to just do
$startDate = new DateTime('first day of january', new DateTimeZone('America/New_York'));
And then do the modifications as needed by using the DateTime::modify() function.
Relative date formats are fun.
My scenario: I wanted to get the bounds of this year as in 2018-01-01 00:00:00 to 2018-12-31 23:59:59
This can be achieved in two ways with relative date formats.
one way is to use the DateTime::modify() function on the object.
$startDate = (new DateTime('now', new DateTimeZone("America/New_York")));
$endDate = (new DateTime('now', new DateTimeZone("America/New_York")));
$startDate->modify("january")
->modify("first day of this month")
->modify("midnight");
$endDate->modify("next year")
->modify("january")
->modify("first day of this month")
->modify("midnight")->modify("-1 second");
var_dump([$startDate, $endDate]);
Try out here: https://www.tehplayground.com/Qk3SkcrCDkNJoLK2
Another way to do this is to separate the relative strings with a comma like so:
$startDate = (new DateTime('first day of january', new DateTimeZone("America/New_York")));
$endDate = (new DateTime('next year, first day of january, -1 second', new DateTimeZone("America/New_York")));
var_dump([$startDate, $endDate]);
Try out here: https://www.tehplayground.com/hyCqXLRBlhJbCyks

Answer 7

Basically date('Y') returns the value of current year. and the first day of each year starts like 2000-01-01.
So this will help you to get exact output.
$firstdate = date( 'Y' ) . '-01-01';

Answer 8

Take a look at this link -- http://davidhancock.co/2013/11/get-the-firstlast-day-of-a-week-month-quarter-or-year-in-php/
function firstDayOf($period, DateTime $date = null)
{
$period = strtolower($period);
$validPeriods = array('year', 'quarter', 'month', 'week');
if ( ! in_array($period, $validPeriods))
throw new InvalidArgumentException('Period must be one of: ' . implode(', ', $validPeriods));
$newDate = ($date === null) ? new DateTime() : clone $date;
switch ($period) {
case 'year':
$newDate->modify('first day of january ' . $newDate->format('Y'));
break;
case 'quarter':
$month = $newDate->format('n') ;
if ($month < 4) {
$newDate->modify('first day of january ' . $newDate->format('Y'));
} elseif ($month > 3 && $month < 7) {
$newDate->modify('first day of april ' . $newDate->format('Y'));
} elseif ($month > 6 && $month < 10) {
$newDate->modify('first day of july ' . $newDate->format('Y'));
} elseif ($month > 9) {
$newDate->modify('first day of october ' . $newDate->format('Y'));
}
break;
case 'month':
$newDate->modify('first day of this month');
break;
case 'week':
$newDate->modify(($newDate->format('w') === '0') ? 'monday last week' : 'monday this week');
break;
}
return $newDate;
}

Answer 9

in PHP 5.3.10 this works
$myDate = new \DateTime(date("Y")."-01-01");
echo $myDate->format("Y-m-d");
In PHP 5.4 and upper you can put all together
echo (new \DateTime(date("Y")."-01-01"))->format("Y-m-d")

Answer 10

As a commenter #Glavić said already
$year = new DateTime('first day of January');
is the solution.
To me it did make sense semantically that "this year" should return midnight of the first day of the year, but indeed it does not!

Answer 11

Following is the code snippet for getting first and last day of the year.
$firstDayOfYear = date('Y-01-01');
$lastDayOfYear = date('Y-12-t');

Answer 12

Try this:
$dt = date('m/d/Y',time());
echo 'First day : '. date("01/01/Y", strtotime($dt)).' - Last day : '. date("m/t/Y", strtotime($dt));

Answer 13

Getting first and last day of the current year using DateTime object.
$currentDate = new \DateTime("NOW");
$yearStartString = $currentDate->format("Y")."-01-01 00:00:00";
$yearEndString = $currentDate->format("Y")."-12-31 23:59:59";
$yearStartDate = \DateTime::createFromFormat("Y-m-d H:i:s", $yearStartString);
$yearEndDate = \DateTime::createFromFormat("Y-m-d H:i:s", $yearEndString);