Add value from a form into a function - php

I have the following form:
<form action="myform.php" method="post" enctype="multipart/form-data">
<input type="hidden" name="my-add-calc" value="add to cart" class="button" />
<input id="my-item-calc" name="my-item-calc" value="29.00">
<input type="hidden" name="my-item-id" value="1"></td>
<td><input type="submit"></form>
I want to use the submitted value of my-item-calc in a function:
I have tried
public function add_calc($calcdel){
$validCaldel = false;
if (is_numeric($calcdel)){
$validCaldel= true;}
//add calculated delivery
if ($validCaldel !==false){
$this->calcdels = $calcdel;}
}
Where
$calcdel = $config['calc']['calcdel'];
in the config file:
$config['checkoutPath'] = 'myform.php';
$config['calc']['calcdel'] = 'my-item-calc';
When I try to return $this->caldels its says this is an array, Im not sure why as I am only adding one value.
I would want the $this->calcdels to echo out the submitted 29.00
Any help very welcome

In your myform.php you shoud first get the value you're looking for:
$my_item_calc = $_POST[ 'my-item-calc' ];
and then give it to the function:
add_calc( $my_item_calc );

Related

Updating a specific key within a multidimensional array (PHP)

I'm having some difficulty updating a quantity value in a multi-dimensional array I've created and really hoping you can help me correct where I've gone wrong;
.
The background
I've got two "items" which both have a simple form tag followed by a hidden input field with a unique value (1 for the first item, 2 for the second).
The button will just point back to this same page using the POST method.
The div on the right of the page will then load a "basket" which will use these post values and add them to an array.
When the "add" button is used again the value should update to +1 rather than create another sub_array.
.
What is currently happening
Currently when I click "add" the first time it adds the array as expected;
However when clicking "add" for the second time it adds a second array rather than +1'in the quantity.
On the third time clicking "add" it does actually now find the original value and update it as I expected, if I click again and again it will continue to update the quantity
It just seems to be that second time I click "add".
.
The Script
<?php session_start();
function in_array_r($needle, $haystack, $strict = false) {
foreach ($haystack as $item) {
if (($strict ? $item === $needle : $item == $needle) || (is_array($item) && in_array_r($needle, $item, $strict))) {
return true;
}
}
return false;
}
if (ISSET($_POST["prod"]))
{
if(in_array($_POST["prod"],$_SESSION["cart"])==TRUE)
{
$_SESSION["cart"][0] =
array($_POST["prod"],$_POST["name"],$_SESSION["cart"][0][2]+1);
}
else{
echo 'running else';
$_SESSION["cart"]=array($_POST["prod"],$_POST["name"],1);}}
if ($_POST['e']=='1')
{
$_SESSION['cart'] = '';
}
echo '<br /><br />';
print_r($_SESSION["cart"]);
}
Sample form
<form action="test.php" method="post" enctype="application/x-www-form-urlencoded">
MAST-O-MIR<br/>
img<br/>
£2.00<br/>
<input type="hidden" value="1" name="prod" />
<input type="hidden" value="MAST-O-MIR" name="name" />
<button class="plus-btn" type="Submit">Add</button>
</form>
Also, what you might well notice from my script is that when you "add" the second item it will actually overwrite the first one by creating the array from scratch so if you can help me with either or both of these I really would appreciate the expertise!
Many thanks to all in advance!
I tried to debug your code and a possible solution could be the following:
<?php
session_start();
if(!isset($_SESSION["cart"]))
{
$_SESSION["cart"]=[];
}
if (isset($_POST["prod"]))
{
$prod_id=$_POST["prod"];
//let suppose $_POST['prod'] is your item id
$found=false;
for($i=0;$i<count($_SESSION['cart']);$i++)
{
if(isset($_SESSION['cart'][$prod_id]))
{
echo "found! so add +1";
$_SESSION['cart'][$prod_id][2]+=1;
$found=true;
break;
}
}
if($found==false)
{
echo 'not found! so create a new item';
$_SESSION["cart"][$prod_id]=array($_POST["prod"],$_POST["name"],1);
}
}
if (isset($_POST['e']) && $_POST['e']=='1')
{
$_SESSION['cart'] = '';
}
echo '<br /><br />';
print_r($_SESSION["cart"]);
?>
<form action="cart.php" method="post" enctype="application/x-www-form-urlencoded">
MAST-O-MIR<br/>
img<br/>
£2.00<br/>
<input type="hidden" value="1" name="prod" />
<input type="hidden" value="MAST-O-MIR" name="name" />
<button class="plus-btn" type="Submit">Add</button>
</form>
<form action="cart.php" method="post" enctype="application/x-www-form-urlencoded">
MAST-O-MIR<br/>
img<br/>
£2.00<br/>
<input type="hidden" value="2" name="prod" />
<input type="hidden" value="MAST-O-MIR" name="name" />
<button class="plus-btn" type="Submit">Add</button>
</form>
Another way to do it is using associative arrays.
The following code creates a cart array in $_SESSION using the item name as key(so you don't need to loop over the cart array to find the item) and
an array with properties as name=>value for each item.
session_start();
if(!isset($_SESSION["cart"]))
{
$_SESSION["cart"]=[];
}
//let's suppose you have unique names for items
if (isset($_POST["prod"]))
{
$name=$_POST["name"];
if(isset($_SESSION['cart'][$name]))
{
echo "found! so add +1";
$_SESSION['cart'][$name]['quantity']+=1;
}
else
{
echo 'not found! so create a new item';
$_SESSION["cart"][$name]=array("id"=>$_POST["prod"],"name"=>$_POST["name"],"quantity"=>1);
}
}
if (isset($_POST['e']) && $_POST['e']=='1')
{
$_SESSION['cart'] =[];
}
echo '<br /><br />';
print_r($_SESSION["cart"]);
?>
<form action="cart2.php" method="post" enctype="application/x-www-form-urlencoded">
MAST-O-MIR<br/>
img<br/>
£2.00<br/>
<input type="hidden" value="1" name="prod" />
<input type="hidden" value="MAST-O-MIR" name="name" />
<button class="plus-btn" type="Submit">Add</button>
</form>
<form action="cart2.php" method="post" enctype="application/x-www-form-urlencoded">
MAST-O-MIR<br/>
img<br/>
£2.00<br/>
<input type="hidden" value="2" name="prod" />
<input type="hidden" value="MAST-OMIR" name="name" />
<button class="plus-btn" type="Submit">Add</button>
</form>
It's hard to test your code without a sample form but I guess both of your problems may be solved by replacing:
$_SESSION["cart"][0] = array($_POST["prod"], $_POST["name"], $_SESSION["cart"][0][2]+1);
For:
$_SESSION["cart"][0][2]+= 1;
By the way, try to properly indent your code when you are going to post it. It is hard to read.

Can't get form value with PHP

I am trying to get the value of a form (text field) with _POST, and store it to a text file but it doesn't work. Here's my code:
HTML
<form>
<input type="text" name="test" id="test" value="">
<input type="button" onclick="location.href='example.com/index.php?address=true';" value="ODOSLAŤ" />
</form>
PHP
if (isset($_GET['address'])) {
$email = $_POST['test'];
$myfile = fopen("log.txt","a") or die("Error.");
fwrite($myfile, "\n".$email);
// this prints nothing
echo $email;
}
I can't get the value of that text field. Nor GET nor POST doesn't work for me. What am I doing wrong?
You are missing a post method in your form.
<form method="post" action="example.com/index.php?address=true">
<input type="text" name="test" id="test" value="">
<input type="submit" value="ODOSLAŤ" />
</form>
You also have to change the following line.
if (isset($_GET['address'])) {
With
if (isset($_POST['address'])) {
You want to post after triggering an action as FreedomPride mentioned
Conclusion
You want to declare for example a post methodif you know that you would like to post that data in the future.
As FreedomPride also mentioned :
You are using a GET, but if a user does not input anything your script won't work, there by it is recommended to use a POST
You are not submitting your form.
Change your code as follows....
<form method="post" action="example.com/index.php?address=true">
<input type="text" name="test" id="test" value="">
<input type="submit" value="ODOSLAŤ" />
</form>
You'll get what you want....
This is what you're missing as Tomm mentioned.
<form method="post" action="yourphp.php">
<input type="text" name="address" id="test" value="">
<input type="submit" name="submit"/>
</form>
In your PHP, it should be post if it was triggered
if (isset($_POST['address'])) {
$email = $_POST['test'];
$myfile = fopen("log.txt","a") or die("Error.");
fwrite($myfile, "\n".$email);
// this prints nothing
echo $email;
}
Explanation :-
In a form, an action is required to pass the action to the next caller with action. The action could be empty or pass it's value to another script.
In your PHP you're actually using a GET. What if the user didn't input anything. That's why it's recommended to use POST .

Getting a value from text input field, then displaying on POST

I'm trying to get a value from a form, then display it on posting of the form. I can get the value to appear in the second text field, once I have chosen an option using the Ajax Auto-Select, but how do I get that value shown stored into a variable for display on posting? This is what I have been trying -
if ($_POST['action'] == 'getentity') {
$value= $entity;
$content .= '<div>'.$value.' hello</div>';
}
<form method="post" action="?">
<input type="text" name="TownID_display" size="50" onkeyup="javascript:ajax_showOptions(this,\'getEntitiesByLetters\',event)">
<input type="text" name="TownID" id="TownID_display_hidden" value="'.$entity.'" />
<input type="hidden" name="action" value="getentity" />
<input type="submit" name="submit" value="Find"/>
Many thanks for any help.
Try
<input type="text" name="TownID" id="TownID_display_hidden" value="<?php $value = $entity; echo $entity; ?>" />
and its better to use like this
if ($_POST['action'] == 'getentity') {
$value= $_POST['TownID'];
$content .= '<div>'.$value.' hello</div>';
}
it should work.

Simple form submit to PHP function failing

I'm trying to submit two form field values to a PHP function, on the same page.
The function works perfect manually filling the two values.
<?PHP // Works as expected
echo "<br />"."<br />"."Write text file value: ".sav_newval_of(e, 45);
?>
On the form I must be missing something, or I have a syntax error. The web page doesn't fail to display. I found the below example here: A 1 Year old Stackoverflow post
<?php
if( isset($_GET['submit']) ) {
$val1 = htmlentities($_GET['val1']);
$val2 = htmlentities($_GET['val2']);
$result = sav_newval_of($val1, $val2);
}
?>
<?php if( isset($result) ) echo $result; //print the result of the form ?>
<form action="" method="get">
Input position a-s:
<input type="text" name="val1" id="val1"></input>
<br></br>
Input quantity value:
<input type="text" name="val2" id="val2"></input>
<br></br>
<input type="submit" value="send"></input>
</form>
Could it be the placement of my code on the form?
Any suggestions appreciated.
You need to name your submit button, or check for something else on your if(isset($_GET['submit'])) portion:
<form action="" method="get">
Input position a-s:
<input type="text" name="val1" id="val1" />
<br></br>
Input quantity value:
<input type="text" name="val2" id="val2" />
<br></br>
<input type="submit" name="submit" value="send" />
</form>
OR keep same form, but change php to:
<?php
if( isset($_GET['val1']) || isset($_GET['val2'])) {
$val1 = htmlentities($_GET['val1']);
$val2 = htmlentities($_GET['val2']);
$result = sav_newval_of($val1, $val2);
}
?>
You can you hidden field as:
<input type='hidden' name='action' value='add' >
And check on php by using isset function that form has been submitted.

passing value in hidden field from one page to another in php

I have a simple registration form.
I want to pass value entered in one page to other in a text field.
how to pass and access it from next page in php.
this is my first php page.
Thanks in advance.
You can add hidden fields within HTML and access them in PHP:
<input type="hidden" name="myFieldName" value="someValue"/>
Then in PHP:
$val = $_POST['myFieldName'];
If you're going to ouput this again you should use htmlspecialchars or something similar to prevent injection attacks.
<input type="hidden" name="myFieldName" value="<?=htmlspecialchars($_POST['myFieldName']);?>"/>
Suppose this the form input in page A
<form name="" action="" method=post enctype="multipart/form-data">
<input type="text" name="myvalue" value="">
<input type=submit>
</form>
In page B
In the page you want to get values put this code
<?PHP
foreach ($_REQUEST as $key => $value ) {
$$key=(stripslashes($value));
}
?>
<form name="" action="" method=post enctype="multipart/form-data">
<input type="text" name="myvalue" value="<?PHP echo $myvalue" ?>">
<input type=submit>
</form>
So yo can use or attach variable value to another form do what else you want to do
use following code, that should help you.
<form action ="formhandler.php" method ="POST" >
<input name = "inputfield" />
<input type="submit" />
</form>
on formhandler.php file yo need to enter following code to get the value of inputfiled.
$inputfield = isset($_POST['inputfield'])?$_POST['inputfield']:"";
// now you can do what ever you want with $inputfield value
echo($inputfield);

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