MySQL SUBSTR() function - php

Question

I want to compare $images, $uploads but the outputs have different names:
$images = '/fiscalapplications/uploads/Image_00314_20200122.pdf';
$uploads = 'Image_00314_20200122.pdf';
How do I do SUBSTR for the $images to = Image_00314_20200122.pdf
<?php
//pulling images from mysql colum1
require_once 'database_connection.php';
$result = mysqli_query($conn,"SELECT check_pic_path FROM checklog");
$images = []; // store a list of images from the database
while ($row = mysqli_fetch_array($result)) {
$images[] = $row['check_pic_path'] . "<br>";
}
//pulling pictures from specific path
$dir = "fiscalapplications/uploads";
$uploads = []; // store a list of files on disk
if(is_dir($dir)) {
while (($file = readdir($dh)) !== false) {
$uploads[] = $file . "<br>";
}
}
}
//attempting to compare $image to $upload
$compare = array_diff($images, $uploads);
print_r($compare);

Answer 1

Use basename() to remove the directory from a pathname:
$images[] = basename($row['check_pic_path']) . "<br>";

Answer 2

In MySQL it may be
SUBSTRINT_INDEX(tablename.imagefield, '/', -1)

Answer 3

$uploadsnew = substr($images , strrpos($images , '/') + 1);
strrpos gets the position of the last occurrence of the slash; substr returns everything after that position.
if there is no slash this doesn't work correctly since strrpos returns false. Here's a more robust version:
$pos = strrpos($url, '/');
$uploadsnew = $pos === false ? $url : substr($images , $pos + 1);

Answer 4

In PHP:
$images = $images ?: '';
$uploads = substr($images, ($pos = strrpos($images, '/')) ? $pos : 0);
In MySQL:
if( ifnull( locate( '/', check_pic_path ), 0 ) > 0, substring_index( check_pic_path, '/', -1 ), check_pic_path )