Make a new array form multidimensional array based on search conditions - php

Question

I have a multidimensional array. I want to search values(username IE jon) and count total "YES" for a specific username.
IE As per below array Andew is repeated three times Index 1,3,4 and its value is "YES" So Andrew's total "YES" count value = 3
Jon is repeated two times but its value is "NO" so it's value = 0
Array
(
[0] => Array
(
[0] => Jon
[1] => NO
)
[1] => Array
(
[0] => Andew
[1] => NO
)
[2] => Array
(
[0] => Walid
[1] => YES
)
[3] => Array
(
[0] => Andew
[1] => YES
)
[4] => Array
(
[0] => Andew
[1] => YES
)
[5] => Array
(
[0] => Jon
[1] => NO
)
[6] => Array
(
[0] => Andew
[1] => YES
)
)
I want to make the user as key and value = count the total number of "Yes".
OUTPUT
Array
(
john => 0,
Andew => 3
Walid => 1
)
Anyone, please suggest a possible solution?
Thanks

Answer 1

You may use array_reduce:
$stats = array_reduce($array, static function ($stats, $entry) {
$stats[$entry[0]] = ($stats[$entry[0]] ?? 0) + ($entry[1] === 'YES' ? 1 : 0);
return $stats;
});
This builds up a $stats array, sets its initial value to 0 for each person and increments it by 1 whenever a YES is found.
Demo: https://3v4l.org/NmZ7G

Answer 2

If you just need the count of 'YES', then the below will output a count.
$count_array = [];
foreach($array as $values){
if(!isset($count_array[$values[0]])){
$count_array[$values[0]] = 0;
}
if($values[1] === 'YES'){
$count_array[$values[0]] ++;
}
}
print_r($count_array);

Answer 3

(Not that different from #Jeto's array_reduce.)
A simple foreach:
<?php
$data =
[
['Brian', 'YES'],
['Brian', 'YES'],
['Charles', 'NO'],
['Charles', 'YES'],
['Nicola', 'NO']
];
foreach($data as list($name, $yes_no))
$yes_counts[$name] = ($yes_counts[$name] ?? 0) + (int) ($yes_no === 'YES');
var_export($yes_counts);
Output:
array (
'Brian' => 2,
'Charles' => 1,
'Nicola' => 0,
)