This question already has answers here:
"Notice: Undefined variable", "Notice: Undefined index", "Warning: Undefined array key", and "Notice: Undefined offset" using PHP
(29 answers)
Closed 3 years ago.
I am trying to run my PHP code, but I am getting an undefined error for the $name variable. The error will show only when it runs for the first time only, but after the second run, it didn't show any error.
<?php
if($_SERVER['REQUEST_METHOD'] == 'POST'){
$name = $nameerr = "";
if(empty($_POST["name"])){
$nameerr = "This Field is Required";
}
else{
$name = test_run($_POST['name']);
}
}
function test_run($data){
$data = trim($data);
$data = stripslashes($data);
$data = htmlspecialchars($data);
return $data;
}
?>
<form action="<?php htmlspecialchars($_SERVER['PHP_SELF']) ?>" method="POST">
<label for="name">Name: </label>
<input type="text" name="name" value="<?php echo $name;?>"><span>* <?php echo $nameerr ?></span><br><br>
<input type="submit" value="Submit">
</form>
<h1>Output</h1>
<?php
echo $name."<br><br>";
?>
This is because you are not setting the $name variable initially. You are only setting it when a post request is made. So the first time you fetch your script with a GET request, PHP shows you the notice. The second time ( I presume is after you submit your form which initiates a POST request ) the $name variable is set, thus, you do not receive the notice. To resolve this, you can set your $name variable to an empty string above your first if statement.
Related
This question already has answers here:
"Notice: Undefined variable", "Notice: Undefined index", "Warning: Undefined array key", and "Notice: Undefined offset" using PHP
(29 answers)
Closed 8 months ago.
I have a html/php code as shown below in the file abc.php in which at Line#A, I am getting the following error:
Notice: Undefined variable: world in abc.php on line#A
html/php code (abc.php) :
if ('POST' == $_SERVER['REQUEST_METHOD']) {
$world = $_POST['world'];
}
<form method="post" action="abc.php?id=<?= $id; ?>">
<input type="hidden" name="world" value="<?= $world; ?>"/> //line#A
</form>
This is what I have tried but it doesn't seem to work:
if ('POST' == $_SERVER['REQUEST_METHOD']) {
$world = isset($_POST['world']);
}
The $world variable will only be defined if page served via POST method.
So, what you need is define it before the condition:
$world = "";
if ('POST' == $_SERVER['REQUEST_METHOD']) {
$world = $_POST['world'];
}
<form method="post" action="abc.php?id=<?= $id; ?>">
<input type="hidden" name="world" value="<?= $world; ?>"/> //line#A
</form>
This question already has answers here:
"Notice: Undefined variable", "Notice: Undefined index", "Warning: Undefined array key", and "Notice: Undefined offset" using PHP
(29 answers)
Closed 2 years ago.
<?php include 'connection.php'; ?>
<?php
if (isset($_GET['consultation']))
{
echo "Consultation Details";
$no=$_GET['consultation'];
?>
<form class="" method="get">
<textarea name="details" rows="8" cols="80" placeholder="enter consultation details"></textarea><br>
<button type="submit" name="c">submit</button>
</form>
<?php
if (isset($_GET['details'])) {
$details=$_GET['details'];
}
//$details= $_GET['details'];
$insertQuery="INSERT INTO redo (consultation) VALUES ($details) WHERE no=$no;";
$insert = mysqli_query($conn,$insertQuery);
if ($insert) {
echo "recorded";
?>
Back to Total Patients
Back to Registration
<?php
}
else {
echo "record couldnt be inserted";
}
}
?>
No $_GET['details'], you sure you're using a GET method in the form? Change $_GET['details'] to $_REQUEST['details'].
To be exact, this one fails:
if (isset($_GET['details'])) {
$details=$_GET['details'];
}
I mean, the if condition is not met, so $details is not defined, as you don't define it anywhere in the code outside that if.
Other solution would be adding:
$details = '';
in front of that if.
This question already has answers here:
"Notice: Undefined variable", "Notice: Undefined index", "Warning: Undefined array key", and "Notice: Undefined offset" using PHP
(29 answers)
Closed 4 years ago.
i am building a multi step login page like that of gmail,
i want the email address the the user typed in to be stored in a global variable so i can echo it in the next step of the form i have been trying but can't figure it out, have seen many error, when i change the code i get a different one the new one i have now is (Notice: Undefined index: email in C:\xampp\htdocs\xxxxx\index.php on line 3)
this is the form
<form action="" method="post" class="form-login">
<div class="step-login step-one">
<input type="text" class="email"/>
<input type="button" class="btn next-step" value="next">
</div>
</form>
this is the php code that i am trying to use and store the input, i think this is where the problem is
<?php
$emails = $_POST['email'];
if(isset($_POST['next'])){
$GLOBALS['email'] = $_GET['email'];
}
?>
this is the code where i am trying to echo the varible
<div class="data-user-find">
<p class="user-email"><?php echo $GLOBALS['email']; ?></p>
</div>
Please guys help me
The "value" of your button is "next", but your button isn't called "next", it should be <button name="next" value="next" type="submit">
Then your error would go away. Also, you define an $email variable outside of your if-clause, please put it inside your if clause, so your code would be this:
<?php if(isset($_POST["next"]) {
$email = $_POST["email"]; (DONT FORGET TO GIVE YOUR MAIL INPUT THE 'name="mail"' TAG)
$GLOBALS["email"] = $email;
} ?>
This question already has answers here:
"Notice: Undefined variable", "Notice: Undefined index", "Warning: Undefined array key", and "Notice: Undefined offset" using PHP
(29 answers)
Closed 6 years ago.
I have this issue that my form obviously doesn't send data with POST method but it sends it with GET method.
Here is my HTML code of the form
<form action="action.php" method="POST">
<input type="text" name="text">
<input type="submit" value="send">
</form>
and here is the php code in the action page
if($_SERVER['REQUEST_METHOD'] == 'POST'){
echo $_POST['text'];
var_dump($_POST);
}
if(isset($_POST['text'])){
echo "ok";
}else{
echo "no";
}
when I submit the form I get this error for output
Notice: Undefined index: text in F:\test\action.php on line 9
array(0) { } no
but when I send data with GET method it works correctly without any problem.
I think the problem is for phpstorm because it runs correctly in the xampp server. and the considerable thing is when I run it in mozila or IE it says page not found but xampp is okay.
Try using isset with your input like so:
You have to add name="something" for the isset to pick up that you have clicked it.
<?php
if (isset($_POST['sub']))
{
echo $_POST['text'];
}
?>
<form action="" method="post">
<input type="text" name="text">
<input type="submit" name="sub" value="Submit">
</form
I can only assume that the output you are seeing is before you submit the form. When you submit it, you should check for POST and not for post:
if ($_SERVER['REQUEST_METHOD'] === 'POST') {
^^^^ here
echo $_POST['text'];
}
This question already has answers here:
"Notice: Undefined variable", "Notice: Undefined index", "Warning: Undefined array key", and "Notice: Undefined offset" using PHP
(29 answers)
Closed 7 years ago.
Every time I hit submit button after selecting an image will face the problem "Notice: Undefined index: profile_picture in C:\wamp\www\Test\testImage.php on line 5", and the page print the text not selected which must be display if image is not selected.
The index is defined, but why it is behave like this, please help with your suggestions
<?php
$photo = "";
if($_SERVER['REQUEST_METHOD'] == "POST")
{
$photo = trim(stripslashes($_POST["profile_picture"]));
if($photo != '')
{
//$photo = trim(stripslashes($_POST["profile_picture"]));
header("Location: success.php");
}
else{
echo 'not selected';
}
}
?>
<!DOCTYPE html>
<html>
<body>
<form name="signup_form" method="post" action="<?php $_SERVER['PHP_SELF']; ?>" enctype="multipart/form-data">
<input type="file" class="profile_picture" id="profile_picture" name="profile_picture"> </br>
<input type="submit" name="submit_btn" id="submit_btn" class="submit_btn" value="sign up">
</form>
</body>
</html>
Files are not posted over $_POST.
They are posted with $_FILES array.
Reference