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<?php
session_start();
?>
<html>
<head>
<link href="style.css" rel="stylesheet" type="text/css">
</head>
<body>
<div class="pageContainer">
<form action="second.php" class="formLayout" method="post">
<div class="formGroup">
<label>Name:</label>
<input type="text" name="first_name"><br>
<input type="hidden" name="postback" value="true"><br>
</div>
<div class="formGroup">
<label> Car model:</label>
<div class="formElements">
<input type="radio" name="model" value="Mustang">Ford Mustang<br>
<input type="radio" name="model" value="Subaru">Subaru WRX STI<br>
<input type="radio" name="model" value="Corvette">Corvette<br>
</div>
<input type="submit" name="submit">
</form>
<?php
if (isset($_POST['submit'])) {
$_SESSION["first_name"] = $_POST["first_name"];
$_SESSION["model"] = $_POST["model"];
}
?>
</div>
</body>
</html>
I set up my code to set the value of the "first_name" and "model" names into my session variables.
When I try to access the values of the stored variables in the submission page of the form:
<?php
session_start();
?>
<html>
<body>
<?php
echo $_SESSION["first_name"];
echo $_SESSION["model"];
?>
</body>
</html>
I only receive the out of the model value, not the first_name value. I don't understand what I'm doing wrong here.
Let's assume your first file is called first.php. As shown in your <form>, the second one is second.php.
It seems that you are writing the data into the session in the first.php file, but this code will never run because you are submitting your form to second.php and not first.php!
So, move the code that writes the session variables into second.php instead. To test that it really worked, you can create a third.php to display them.
(I'm not sure why see the model set, but I guess it's still there from a previous test you did.)
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i download 2 php file, one is index. php for input form, and other is insert.php. i have put them on the same folder.
when i click submit it execute insert.php file it work fine and it insert form data into my database. but the question is: how it is called? no code line on the index.php calling the insert.php file.
here is a code of index.php
<!DOCTYPE html>
<html lang="en">
<head>
<title>GFG- Store Data</title>
</head>
<body>
<center>
<h1>Storing Form data in Database</h1>
<form action="insert.php" method="post">
<p>
<label for="firstName">Name:</label>
<input type="text" name="name" id="name">
</p>
<p>
<label for="lastName">Branch:</label>
<input type="text" name="branch" id="branch">
</p>
<p>
<label for="Gender">Roll Number:</label>
<input type="text" name="roll_no" id="roll_no">
</p>
<input type="submit" value="Submit">
</form>
</center>
</body>
</html>
here is the code of insert.php
<!DOCTYPE html>
<html>
<head>
<title>TEST</title>
</head>
<body>
<center>
<?php
$conn = mysqli_connect("localhost", "root", "", "test");
// Check connection
if($conn === false){
die("ERROR: Could not connect. "
. mysqli_connect_error());
}
// Taking all 3 values from the form data(input)
$name = $_REQUEST['name'];
$branch = $_REQUEST['branch'];
$roll_no = $_REQUEST['roll_no'];
// Performing insert query execution
// here our table name is college
$sql = "INSERT INTO student VALUES ('$name','$branch','$roll_no')";
if(mysqli_query($conn, $sql)){
echo "<h3>data stored in a database successfully."
. " Please browse your localhost php my admin"
. " to view the updated data</h3>";
}
else{
echo "ERROR: Hush! Sorry $sql. "
. mysqli_error($conn);
}
// Close connection
mysqli_close($conn);
?>
</center>
</body>
</html>
insert.php is calling after clicking on submit button by "action" attribute which you have used in tag.
<form action="insert.php" method="post">
You can set another path as well as if you want to keep insert.php on any other folder location.
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I'm a beginner in PHP and MySQL and I want to add values that come from an input in HTML, to a MySQL database.
I have to find some things on the Internet but this doesn't work and so I tried to learn a little bit more PHP but I still don't understand why the condition in the code below is not valid:
<!DOCTYPE html>
<html>
<head>
<link rel="stylesheet" type="text/css" href="style.css">
<meta charset="utf-8">
<title>SHAR-APP</title>
</head>
<body>
<div class='div1'>
<div class='div2'>
<label for="name">Name of the user:</label>
<input class ='in'type="text" id="name" name="name" size="20">
</div>
<div class='div2'>
<label class = 'label' for="name">Code:</label>
<input class='in' id ='code' type="text" name="code" size="20">
</div>
<div class="div2" id='b'>
<input type="submit" value="send" class='button'>
</div>
</div>
<?php
echo "test1";
if (isset($_POST['name'])) {
echo "test2";
$mtsqli = mysqli_connect('localhost','the_name_of_my_project','my_password');
mysqli_select_db('project_database', $msqli);
$requete = 'INSERT INTO the_name_of_the_database's_table VALUES(NULL,"' . $_POST['name'] . '","' . $_POST['code'] . '")';
$query = "SELECT * FROM the_name_of_the_database's_table";
echo $_POST['name'];
echo "test3";
}
?>
</body>
</html>
I'm on this for 3 days and I'm really blocked. Maybe I have others mistake in the PHP code. If I can do that with another language i prefer to stay on PHP because I don't want to learn too much languages. If I can do a bridge between HTML and MySQL with Python or JavaScript I'm OK to know that.
THIS PART IS GOOD but another problem is come ...
when i want to connect on my database this error message is display
C:\Users\titou>set PATH=$PATH$;C:\Program Files\MySQL\MySQL Server 8.0\bin
C:\Users\titou>mysql -h localhost -u root -p
Enter password: **********
ERROR 1045 (28000): AccŠs refus‚ pour l'utilisateur: 'root'#'#localhost' (mot de passe: OUI)
its in french but you can see that there is two # instand of one ('root'#'localhost')
First you need to add a Form Method
<form action="" method="POST">
<div class='div2'>
<label for="name">Name of the user:</label>
<input class ='in'type="text" id="name" name="name" size="20">
</div>
<div class='div2'>
<label class = 'label' for="name">Code:</label>
<input class='in' id ='code' type="text" name="code" size="20">
</div>
<div class="div2" id='b'>
<input type="submit" value="send" class='button'>
</div>
</form>
The is some kind of class that tells the browser to expect inputs and then on the button click- to treat them.
The Action="" is for initializing where to treat the given inputs.
In your case, since your php code is in the same class as the form, you can leave it blank, either way you should initialize the path you want to send those data.
The Method="POST" is just a Method for treating your data on the web. It is also more secure than GET method which it works too but it's more sensitive since all the data from the inputs it's going to be exposed also in the URL.
Furthermore, I hope you have already installed XAMPP and already created a database in MySQL.
Add the form attribute to your form and in it add a method and an action. Method is needed to tell the form to post, and action is needed to tell the form what to do when you submit.
<!DOCTYPE html>
<html>
<head>
<link rel="stylesheet" type="text/css" href="style.css">
<meta charset="utf-8">
<title>SHAR-APP</title>
</head>
<body>
<form method="post" action="">
<div class='div1'>
<div class='div2'>
<label for="name">Name of the user:</label>
<input class ='in'type="text" id="name" name="name" size="20">
</div>
<div class='div2'>
<label class = 'label' for="name">Code:</label>
<input class='in' id ='code' type="text" name="code" size="20">
</div>
<div class="div2" id='b'>
<input type="submit" value="send" class='button'>
</div>
</div>
</form>
<?php
if (isset($_POST['name'])) {
$db = mysqli_connect($dbhost, $dbuser, $dbpass, $dbname);
$requete = 'INSERT INTO the_name_of_the_database's_table VALUES(NULL,"' . $_POST['name'] . '","' . $_POST['code'] . '")';
mysqli_query($db, $requete);
$query = "SELECT * FROM the_name_of_the_database's_table";
$Data = mysqli_query($db, $query);
var_dump[$Data];
}
?>
</body>
</html>
Now an important thing to note, never use this in a live website as it would open up your website to SQL injection. You should use prepared statements instead, but for learning purposes, this is fine.
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Closed 4 years ago.
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this is my html code
<?php include('process.php') ?>
<!doctype html>
<html lang="en">
<head>
<title>Title</title>
</head>
<body>
<from action="index.php.php" method="post">
<?php include('errors.php'); ?>
<lable> name </lable>
<input type="text" name="name" placeholder="enter your name">
<lable>location</lable>
<input type="text" name="location" placeholder="enter your location">
<button type="submit" name="save_btn" >update</button>
</from>
</body>
</html>
this is my php code
<?php
session_start();
// initializing variables
$name="";
$location="";
// connect to the database
$db = mysqli_connect('localhost', 'newuser', 'password', 'curd');
// REGISTER USER
if (isset($_POST['save_btn'])) {
// receive all input values from the form
$name = mysqli_real_escape_string($db, $_POST['name']);
$location = mysqli_real_escape_string($db, $_POST['location']);
$query = "INSERT INTO data (name, location) VALUES('$name', '$location')";
mysqli_query($db, $query);
}
why its not store in data base? data base name correct and i have 3 tables
id (ai)
name (var 200)
location (var 200)
in my browser i can locate index.php but when i click button nothing happen any one can explain why its not working?
Fine, it seems that the problem is caused by 2 important typos:
<from action="index.php.php" method="post"> should be <form action="index.php" method="post">.
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Closed 8 years ago.
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I have an HTML Form and I am trying to get the values from the form in my php file.
<div id="qForm">
<form action="postComment.php" method="post" name="comment">
Name: <input type="text" name="askerName"><br>
Title: <input type="text" name="qTitle"><br>
<textarea maxlength="255" name="theQ"></textarea>
<input type="submit">
</form>
</div>
My PHP file looks like this but It echos as Welcome
<?php
$name = $_POST["askerName"];
echo $name; //this works
$textArea = $_POST["theQ"];
echo $textArea; //this does not work
?>
<html>
<head>
</head>
<body>
welcome <?php $_POST["askerName"]; ?>
</body>
</html>
Use
<body>
welcome <?php echo $_POST["askerName"]; ?>
</body>
instead.
you have to use print/echo to display your php output these two basic ways to get output: echo and print
<body>
welcome <?php print $_POST["askerName"]; ?>
</body>
else
<body>
welcome <?php echo $_POST["askerName"]; ?>
</body>
echo is marginally faster compared to print as echo does not return any value
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Closed 9 years ago.
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I have a log in page that I want to pass a value to from another page... but it wont pass can anyone help me? please.
login page code:
<!DOCTYPE html>
<?php
ob_start();
session_start();
include('include/connect.php');
?>
<html>
<head>
<title>test</title>
</head>
<body>
<form action="" method="post">
<input type="text" name="username">
<input type="text" name="password">
<input type="submit" name="login" id="send" />
</form>
</body>
</html>
<?php
// Inialize session
if(isset($_POST['login'])){
$username=$_POST['username'];
$password=$_POST['password'];
$repcode=$_POST['repcode'];
// Include database connection settings
include('connection.php');
// Retrieve username and password from database according to user's input
$login = mysql_query("SELECT * FROM users WHERE username = '$username' and password = '$password'");
// Check username and password match
if (mysql_num_rows($login) == 1) {
// Set username session variable
$_SESSION['username'] = $_POST['username'];
$_SESSION['repcode'] = $_POST['repcode'];
// Jump to secured page
$stat = "UPDATE users SET status='login'";
mysql_query($stat);
header('Location: home2.php');
}else {
}
}
?>
page to be passed:
<!DOCTYPE html>
<?php
ob_start();
session_start();
include('include/connect.php');
?>
<html>
<head>
<title>test</title>
</head>
<body>
<form method="get">
<input type="text" name="username" value="<?php echo $_POST['username']; ?> "/>
<input type="text" name="repcode" value="<?php echo $_POST['repcode']; ?> "/>
</form>
</body>
</html>
I want to pass the username and repcode to another page and put it in textboxes. Can anyone help me with this...I'm new in php and still learning.
I don't understand the goal of your code, but you need to use $_SESSION instead of $_POST in the 2nd page if you want to use the values stored in SESSION:
<form method="get" >
<input type="text" name="username" value="<?php echo $_SESSION['username']; ?> "/>
<input type="text" name="repcode" value="<?php echo $_SESSION['repcode']; ?> "/>
</form>