Laravel Too few arguments to function - php

Question

I have a simple app for generating some code using Laravel, now I am trying to pass unique id to to my controller with the url.
This is this method that should receive the ID:
public function code($code_id)
{
$settings = Setting::find($code_id);
return view('pages.settings.code', compact('settings'));
}
And this is my view-file where I pass the ID:
<a href="{{ route('settings.code', $settings->code_id) }}">
{{ __('Generate Code') }}
</a>
When I check the URL I get:
http://127.0.0.1:8001/settings/code?K1zMXRZG4
Here is my route:
Route::get('settings/code', [
'as' => 'settings.code',
'uses' => 'SettingController#code'
]);
Route::resource('settings', "SettingController");
But I get the following error:
Symfony \ Component \ Debug \ Exception \ FatalThrowableError (E_RECOVERABLE_ERROR)
Too few arguments to function App\Http\Controllers\SettingController::code(), 0 passed and exactly 1 expected
What is wrong with my code?

Answer 1

You need to define any parameters that should be passed to the method in your route:
Route::get('/settings/code/{code_id}', 'MyController#code')
->name('settings.code');
That will pass $code_id to the code()-method in your controller.
If you don´t define the parameter in your route, it will be passed as a parameter in Request-object instead - like all querystrings - and you need to fetch it like this in your controller:
$code_id = $request->query('code_id');