How to get Billing Address from Eloquent model with where clause? - php

Question

For example I can use:
$address = $user->address
which will return the addresses for the user.
// User.php (model)
public function address()
{
return $this->hasMany(Address::class, 'refer_id', 'id');
}
public function billingAddress()
{
return $this->address()
->where('type', '=', 1)
->where('refer_id', '=', $this->id)
->first();
}
However, I would like to return the BillingAddress for the user depending on this where clause. How do I do it?
EDIT:
If I use this inside... OrderController#index it returns correctly
$orders = Order::with('order_fulfillment', 'cart.product', 'user.address', 'payment')->get();
return new OrderResource($orders);
However, If I change it to:
$orders = Order::with('order_fulfillment', 'cart.product', 'user.billingAddress', 'payment')->get();
return new OrderResource($orders);
I get this error:
Symfony\Component\Debug\Exception\FatalThrowableError
Call to a member function addEagerConstraints() on null

Answer 1

One option is you can use whereHas in your query. For example,
$orders = Order::with('order_fulfillment', 'cart.product', 'user.address', 'payment')
->whereHas(
'address', function ($query) {
$query->where('type', '=', 1)
->first();
}
)->get();
return new OrderResource($orders);
This is one option. try to dd($orders) an find if its working.
You had an another option like this, in your model
public function address()
{
return $this->hasMany(Address::class, 'refer_id', 'id');
}
Add relations like
public function billingAddress()
{
return $this->hasOne(Address::class, 'refer_id', 'id')->where('type', 1);
}
And
public function shippingAddress()
{
return $this->hasOne(Address::class, 'refer_id', 'id')->where('type', 2);
}
Then in your query,
$orders = Order::with('order_fulfillment', 'cart.product', 'user.address','user.billingAddress', 'user.shippingAddress', 'payment')->get(); return new OrderResource($orders);