Set default value for select dropdown in Php - php

I'm a absolute newby for php and i'm struggling with just a basic thing.
I want to set a default value for a select box i have. Default value should be 2
My code
<div class="selector-wrapper">
<select id="adults" class="form-control" onchange="toggleSetGuests()">
<?php
for($i = 0; $i <= 20; $i++):
?>
<option value="<?php echo $i ?>" <?php if($i == 0){ echo('selected="true"'); } ?>>
<?php echo $i ?> Adults
</option>
<?php
endfor;
?>
</select>
</div>
So in this select box i get options from 0 - 20. I want to set the default value as 2 instead of 0
My approach was like below
<option value="<?php echo $i ?>" <?php if($i == 2){ echo('selected="true"'); } ?>>
But did not work.
How do i set the default value to be selected as the value 2


<option value="<?php echo $i ?>" <?php if($i == 2){ echo ' selected'; } ?>>
should work.You don't need selected=true

Related

PHP Assign Value from dropdown selection

I have this loop coded to create a dropdown with the numbers 0-30.
<td style="text-align:left;">
<select id="iPhone12Case" name="iPhone12Case">
<?php
for ($i=0; $i<=30; $i++) {
?>
<option value="<?php echo $i;?>"><?php echo $i;?></option>
<?php
}
?>
</select>
</td>
I cannot seem to figure out how to get the value of I to work in my calculations on an order processing form.
I assign the variable using
$iPhone12 = htmlspecialchars($_POST['iPhone12Case']);
but if I try to output $iPhone12 * 15 for example the answer is always zero.

Make sure you select is wrapped in a form element with method="POST". You should also use isset to make sure it exists.
<form action="" method="post">
<td style="text-align:left;"><select id="iPhone12Case" name="iPhone12Case">
<?php
for ($i = 0; $i <= 30; $i++) {
?>
<option value="<?php echo $i; ?>"><?php echo $i; ?></option>
<?php
}
?>
</select></td>
<button>submit</button>
</form>
<?php
if (isset($_POST['iPhone12Case'])) {
$iPhone12 = htmlspecialchars($_POST['iPhone12Case']);
printf($iPhone12 * 15);
}

Gateway is down because of PHP code in one situation

Here is the code (HTML / PHP) :
<div class="col-sm-6">
<div class="form-group">
<select id="horseSize" name="horseSize" class="form-control" >
<option value="<?php echo htmlspecialchars($horseSize); ?>" selected><?php echo htmlspecialchars($horseSize); ?> m</option>
<?php
$i = 0.50;
while($i <= 2.00){
if ($i != $horseSize){
?>
<option value="<?php echo htmlspecialchars(number_format($i, 2)) ; ?>"><?php echo htmlspecialchars(number_format($i, 2)) ; ?> m</option>
<?php
$i = $i + 0.01;
}
}
?>
</select>
</div>
</div>
$horseSize comes from a SQL query and is working fine. Th problem is in displaying webpage.
When i am trying to display this webpage, my website goes down because of gateway giving no answer. This triggers only in one situation : if the variable value of $horseSize is inferior to 1. As if it was not possible to display something like 0,....
Maybe I did something wrong in this code, but I tried many times to fix, I couldn't reach it.

you are incrementing $i only under if condition, so value like 0.50 it will always never increase. Also floating point comparison will not work. please read: Floating point numbers
<div class="col-sm-6">
<div class="form-group">
<select id="horseSize" name="horseSize" class="form-control" >
<option value="<?php echo htmlspecialchars($horseSize); ?>" selected><?php echo htmlspecialchars($horseSize); ?> m</option>
<?php
$i = 0.50;
$precision = 0.00001;
while($i <= 2.00){
if(abs($i-$horseSize) > $precision) {
?>
<option value="<?php echo htmlspecialchars(number_format($i, 2)) ; ?>"><?php echo htmlspecialchars(number_format($i, 2)) ; ?> m</option>
<?php
$i = $i + 0.01;
} else {
$i = $i + 0.01;
}
}
?>
</select>
</div>
</div>

set variable 2 digits in a for loop

I'm having an stupid issue here; I'm trying to make in a form, a select with the time the user starts, and the time they finish, so logically, I want to display the time as:
00
01
02.. I mean, 2 digit
But although I put 00 for the initial value of $i, it displays only 1 digit anyway!
Is it any way I can set it to two digits?
Thanks!!
<div class="interval">
<input type="checkbox" id="interval_check"/>
<div id="desde">
De: <select class="hores" name="hores" disabled>
<?php for ($i = 00; $i <= 23; $i++) : ?>
<option value="<?php echo $i; ?>"><?php echo $i; ?></option>
<?php endfor; ?>
</select>:<select class="minuts" name="minuts" disabled>
<?php for ($i = 00; $i <= 45; $i+=15) : ?>
<option value="<?php echo $i; ?>"><?php echo $i; ?></option>
<?php endfor; ?>
</select>
</div> <div id="fins">
fins: <select class="hores" name="hores" disabled>
<?php for ($i = 00; $i <= 23; $i++) : ?>
<option value="<?php echo $i; ?>"><?php echo $i; ?></option>
<?php endfor; ?>
</select>:<select class="minuts" name="minuts" disabled>
<?php for ($i = 00; $i <= 45; $i+=15) : ?>
<option value="<?php echo $i; ?>"><?php echo $i; ?></option>
<?php endfor; ?>
</select>
</div>
</div>

just use sprintf to create the string for you.
<?php for ($i = 0; $i <= 23; $i++) : ?>
<option value="<?php echo $i; ?>">
<?php echo sprintf("%02d", $i); ?>
</option>
<?php endfor; ?>
this will add a 0 if the string is less than 2 characters. I'm presuming that you don't care about the value.

PHP Displaying current month in option select

How to make the current month selected by default in option select using php
Here is what i have tried so far.
$curmonth = date("F");
And to display the entire month
<select>
<?php
for($i = 1 ; $i <= 12; $i++)
{
$allmonth = date("F",mktime(0,0,0,$i,1,date("Y")))
?>
<option value="<?php
echo $i;
if($curmonth==$allmonth)
{
echo 'selected';
}
?>"
>
<?php
echo date("F",mktime(0,0,0,$i,1,date("Y")));
}
?>
</option>
And according to the above code, I am assigning the current month as $curmonth, and inside loop assigning the $allmonth for entire, month.
And inside the Value
<option value="<?php
echo $i;
if($curmonth==$allmonth)
{
echo 'selected';
}
?>"
>
<?php
echo date("F",mktime(0,0,0,$i,1,date("Y")));
}
?>
</option>
for checking if the current month equals all month and displaying the selected to make it select. But i am not getting result.. What i am getting is all the items are being displayed in the option select.
What i am missing ?

What you have missed is,
You are trying to display the selected inside the value
What you need to do is
<option value="<?php
echo $i;
?>"
<?php
if($allmonth==$curmonth)
{
echo ' selected';
}
?>
>
<?php
echo $allmonth;
}
?>
</option>
So, the result will be
<select >
<option value="1">
January<option value="2">
February<option value="3">
March<option value="4">
April<option value="5">
May<option value="6">
June<option value="7">
July<option value="8">
August<option value="9" selected>
September<option value="10">
October<option value="11">
November<option value="12">
December</option>

You're not correctly closing the <option> tags you are creating. Indenting you're code makes these issues more apparent:
<select>
<?php
for($i = 1 ; $i <= 12; $i++)
{
$allmonth = date("F",mktime(0,0,0,$i,1,date("Y")))
?>
<option value="<?php
echo $i;
if($curmonth==$allmonth)
{
echo 'selected';
}
?>"
>
<?php
echo date("F",mktime(0,0,0,$i,1,date("Y")));
//Close tag inside loop
?>
</option>
<?php
}

Hope you are wrong here
<option value="<?php
echo $i; ?>"
<?php
if($curmonth==$allmonth)
{
echo 'selected';
}
?>"
>
<?php
echo date("F",mktime(0,0,0,$i,1,date("Y")));
}
?>
</option>
You have missed closing quotes for the value

Take a look on this example:
$current = date('F');
for($i = 1 ; $i <= 12; $i++) {
$month = date("F",mktime(0,0,0,$i,1,date("Y")));
if( $current == $month )
echo $month . " - Selected \r\n";
else
echo $month . "\r\n";
}
IN HTML FORMAT:
echo "<select>";
$current = date('F');
for($i = 1 ; $i <= 12; $i++) {
$month = date("F",mktime(0,0,0,$i,1,date("Y")));
if( $current == $month )
echo "<option value='$month' selected='selected'>" $month . "</option>";
else
echo "<option value='$month'>" $month . "</option>";
}
echo "</select>";
DEMO

You have error with closing quotes in the value of options in the line
<option value="<?php
echo $i; if($curmonth==$allmonth)
{
echo 'selected';
}
?>"
^ // This is the quotes opened for value and is not properly closed
>
Here you have to close the quotes. As per your code it will display as:
<option value="9 selected" >
Also you are not closing <option> properly. Change your code to :
<select>
<?php
for($i = 1 ; $i <= 12; $i++)
{
$allmonth = date("F",mktime(0,0,0,$i,1,date("Y")))
?>
<option value="<?php echo $i;?>" <?php if($curmonth==$allmonth){echo 'selected';}?> >
^ // close quotes here
<?php
echo $allmonth;?>
</option>
}
</select>

Select box values in PHP MYSQL

I have a select box like this. This is nothing but looping from 1 to 10.
<select name="author_box[]" id="author_box[]">
<?php for($j=1;$j<=10;$j++){ ?>
<option id="<?php echo $j; ?>" name="<?php echo $j; ?>" value="<?php echo $$j; ?>"><?php echo $j; ?></option>
<?php } ?>
</select>
For example: I have a variable $tmp_rating="5". So what I want to display is showing the value 5 in the select box along with the other values (i.e. from 1 to 10).
How can I achieve that. In short, the value which I fetch from the database should be displayed first in the select box.
Thank you gentleman, for all the time and instant reply. This portal helps me a lot in fixing my issues in less time.

You have to use the selected attribute for the option:
<select name="author_box[]" id="author_box[]">
<?php for($j=1;$j<=10;$j++){ ?>
<option value="<?php echo $j; ?>" <?=($tmp_rating==$j)?'selected="selected"':null;?>><?php echo $j; ?></option>
<?php } ?>
</select>
This way, if $tmp_rating is the same as $j in your loop, the attribute selected is added and the correct value displays in your selectbox.

By adding this condition
<?php if($j == $tmp_rating) echo 'selected="selected"'; ?>
Full code
<option <?php if($j == $tmp_rating) echo 'selected="selected"'; ?> id="<?php echo $j; ?>" name="<?php echo $j; ?>" value="<?php echo $$j; ?>"><?php echo $j; ?></option>

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