I'm looking to retrieve a user's avatar using their user name, retrieve it in an input field. However what I did does not work and I am not familiar with Ajax. Could someone help me and explain the procedure to me?
<input type="text" name="username" class="input" placeholder="Your username">
<img id="#result" src=""></img>
Here is my ajax
$(document).keyup(function (event) {
$.ajax({
url: "App/Actions/PlayerGetFigure.php",
type: "post",
data: {
login: function () {
return $(':input[name="username"]').val();
},
},
success: function (data) {
$('#result').html(data);
}
});
});
And here is my PHP
require '../../vendor/autoload.php';
use App\Models\UsersManager as Users;
$Users = new Users();
$username = $_POST['username'];
if (isset($username)) {
$user = $Users->getByUsername($username);
if ($user) {
echo $user['avatar'];
} else {
return false;
}
}
I would personally take this approach, it looks a bit cleaner for me (assuming that $user['avatar'] returns the path to the image)
HTML
<input type="text" id="username" class="input" placeholder="Your username" />
<div id="result"></div>
AJAX
$(document).keyup(function (event) {
let username = $('#username').val();
$.ajax({
url: "App/Actions/PlayerGetFigure.php",
type: "post",
data: { login:username },
success: function (data) {
$('#result').html(data);
}
});
});
PHP
require '../../vendor/autoload.php';
use App\Models\UsersManager as Users;
$Users = new Users();
$username = $_POST['username'];
if (isset($username)) {
$user = $Users->getByUsername($username);
if ($user) {
$avatar = $user['avatar'];
echo "<img src='$avatar'></img>";
} else {
return false;
}
}
If this is your HTML:
<input type="text" name="username" class="input" placeholder="Your username">
<img id="result" src=""></img>
I would advise the following jQuery.
$(function(){
function getAvatar(username){
var url = "";
$.post("App/Actions/PlayerGetFigure.php", { login: username }, function(data){
url = data;
});
return url;
}
$("input[type='username']").change(function(){
$("#result").attr("src", getAvatar($(this).val()));
});
});
This assumes that the PHP Script will return a (Relative or Absolute) URL Path to the Image.
Related
I have created an AJAX function in Wordpress. The function is called on form submission. The function is run, but it is not receiving any of the form data that I have submitted. What am I missing?
PHP Function
I have added the PHP function here, which is called successfully via AJAX. This form creates a new user successfully, but only when I create the variables manually (eg. see $new_user_data['user_login'] = 'This Text Works';). For some reason, the $_POST data isn't coming through to the function.
add_action("wp_ajax_register_user", __NAMESPACE__ . "\\register_user");
add_action("wp_ajax_nopriv_register_user", __NAMESPACE__ . "\\register_user");
function register_user() {
// NONCE VERIFICATION
if ( !wp_verify_nonce( $_REQUEST['nonce'], "rtr_register_nonce")) {
exit("Oops! This is embarassing!");
}
// Get all post data for the user.
$new_user_data = array();
$new_user_data['first_name'] = sanitize_text_field($_POST['first-name']);
$new_user_data['last_name'] = sanitize_text_field($_POST['last-name']);
$new_user_data['user_email'] = $_POST['email'];
$new_user_data['user_pass'] = sanitize_text_field($_POST['password']);
$new_user_data['user_login'] = 'This Text Works';
$new_user_data['role'] = 'subscriber';
// Create the User
$registered_user = wp_insert_user( $new_user_data );
$result['user'] = $registered_user;
// AJAX CHECK
if(!empty($_SERVER['HTTP_X_REQUESTED_WITH']) && strtolower($_SERVER['HTTP_X_REQUESTED_WITH']) == 'xmlhttprequest') {
$result = json_encode($result);
echo $result;
} else {
header("Location: ".$_SERVER["HTTP_REFERER"]);
}
die();
}
JQuery
function registerUser(){
var nonce = $('#regForm').attr("data-nonce");
var formData = $('#regForm').serialize();
$.ajax({
url: rtr_register_user.ajaxUrl,
type: 'post',
dataType: 'json',
data : {action: 'register_user', nonce: nonce, formData: formData},
success: function (response) {
console.log(response);
$('#regForm').html('Your form has been submitted successfully');
},
});
}
function nextPrev(n) {
// This function will figure out which tab to display
var x = document.getElementsByClassName("form-tab");
// Exit the function if any field in the current tab is invalid:
if (n === 1 && !validateForm()) {
return false;
}
// Hide the current tab:
x[currentTab].style.display = "none";
// Increase or decrease the current tab by 1:
currentTab = currentTab + n;
// if you have reached the end of the form... :
if (currentTab >= x.length) {
//...the form gets submitted:
//document.getElementById("regForm").submit();
registerUser();
return false;
}
// Otherwise, display the correct tab:
showTab(currentTab);
}
$('#nextBtn').click(function () {
nextPrev(1);
});
$('#prevBtn').click(function () {
nextPrev(-1);
});
Form
<?php
$nonce = wp_create_nonce("rtr_register_nonce");
$link = admin_url('admin-ajax.php?action=register_user&nonce='.$nonce);
?>
<form id="regForm" <?php echo 'data-nonce="' . $nonce . '"'; ?> action="<?php echo $link; ?>" method="post" enctype="multipart/form-data">>
<div class="my-3 text-center">
<span class="form-step">1</span>
<span class="form-step">2</span>
</div>
<div class="form-tab">
<p><input name="first-name" placeholder="First Name" oninput="this.className = ''"></p>
<p><input name="last-name" placeholder="Last Name" oninput="this.className = ''"></p>
<p><input name="dob" type="date" oninput="this.className = ''"></p>
</div>
<div class="form-tab">
<p><input name="email" type="email" placeholder="Email" oninput="this.className = ''"></p>
<p><input name="password" type="password" placeholder="Password" oninput="this.className = ''"></p>
</div>
<div style="overflow:auto;">
<div style="float:right;">
<button type="button" class="btn btn-brand" id="prevBtn">Previous</button>
<button type="button" class="btn btn-brand" id="nextBtn">Next</button>
</div>
</div>
</form>
Seems you are not triggering registerUser() check following script works fine for me
jQuery(document).ready(function($) {
jQuery('body').on('click', '#nextBtn', function() {
registerUser();
});
});
function registerUser(){
var nonce = jQuery('#regForm').attr("data-nonce");
var formData = jQuery('#regForm').serialize();
jQuery.ajax({
url: ajaxurl,
type: 'post',
dataType: 'json',
data : {action: 'register_user', nonce: nonce, formData: formData},
success: function (response) {
console.log(response);
$('#regForm').html('Your form has been submitted successfully');
},
});
}
add method="post" to your 'form' - 'get' is the default https://stackoverflow.com%2Fquestions%2F2314401%2Fwhat-is-the-default-form-http-method&usg=AOvVaw1dKc3hW4K6r5SwQurLztBw
The "user_login" is a username of the user so probably it doesn't accepts space too.
See also WP Insert Post
Please try passing some username such as "custom_user" and see the result.
Hope this might work.
Ok it was a bit of help from everyone here. But yes, I was calling the AJAX correctly, but not actually submitting the form. I added a .on(submit) to the form and then added a listener to the form to perform the AJAX call on submit. Here's the amendments below.
function nextPrev(n) {
var x = document.getElementsByClassName("form-tab");
if (n === 1 && !validateForm()) {
return false;
}
x[currentTab].style.display = "none";
currentTab = currentTab + n;
if (currentTab >= x.length) {
// ADDED THIS SUBMIT() HERE
document.getElementById("regForm").submit();
return false;
}
// Otherwise, display the correct tab:
showTab(currentTab);
}
// ADDED AN EVENT LISTENER TO TRIGGER THE AJAX CALL HERE
$('#regForm').on('submit', function () {
var nonce = $('#regForm').attr("data-nonce");
var formData = $('#regForm').serialize();
$.ajax({
url: rtr_register_user.ajaxUrl,
type: 'post',
dataType: 'json',
data: {
action: 'register_user',
nonce: nonce,
formData: formData
},
success: function (response) {
console.log(response);
$('#regForm').html('Your form has been submitted successfully');
},
});
});
This is my first post here. Sorry if my English appears to be bad.
I attempted to use the following codes to submit form data to my signup/submit/index.php.
Here is my sample HTML
<form name="signup_form" id="signup_form" action="submit">
<input type="text" class="form-control" placeholder="CreateUsername" name="username" id="username" autocomplete="off">
<input type="password" class="form-control" placeholder="CreatePassword" name="password" id="password"></form>
Here is my Ajax
.on('success.form.fv', function(e) {
e.preventDefault();
loadshow();
var $form = $(e.target),
fv = $form.data('formValidation');
// Use Ajax
$.ajax({
url: $form.attr('action'),
type: 'POST',
data: $('#signup_form').serialize(), //or $form.serialize()
success: function(result) {
// ... Process the result ...
//alert(result);
if (result=="2")
{
swal({
type: "success",
title: "HiHi!",
text: "GoodLuck",
animation: "slide-from-top",
showConfirmButton: true
}, function(){
var username = $("#username").val();
var password = $("#password").val();
functionA(username,password).done(functionB);
});
}
else (result=="agent_na")
{
swal({
type: "error",
title: "ERROR",
text: "N/A",
animation: "slide-from-top",
showConfirmButton: true
});
Here goes my PhP
<?php
$params = array();
$gett = $_POST["username"];
parse_str($gett,$params);
print_r ($gett); // it prints an empty array
print_r ($gett); // it prints an empty array
echo $params["username"] // it shows undefined username index
?>
I have attempted to serialize $gett before parse_str it. It returns me (){}[].
Could please assist me on this?? I spent almost 20 hours on this, google and tried a lot. Am new to JS.
I try to keep it simple
HTML
<!-- Include Jquery Plugin -->
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<form id="signup_form">
<input type="text" name="username" placeholder="Enter the user name" />
<input type="password" name="password" placeholder="Enter password here" />
<input type="submit" value="Login" />
</form>
<script>
/* Page loaded */
$(function(){
/* Trigger when the form submitted */
$("#signup_form").submit(function(e) {
var form = $(this);
$.ajax({
type: "POST",
url: "backend.php",
data: form.serialize(), // Checkout the document - https://api.jquery.com/serialize/
success: function(data) {
// handle the return data from server
console.log(data);
}
});
e.preventDefault();
return false;
})
})
</script>
PHP (backend.php)
<?php
// Always check param exists before accessing it
if(isset($_POST['username']) && isset($_POST['password'])){
// Print all the post params
print_r($_POST);
// or by param
// echo "User Name: " . $_POST['username']. " <br />";
// echo "Password: " . $_POST['username']. " <br />";
}
?>
Hope this helps!
This is a sample of how you can debug an ajax call:
Javascript:
$(function(){
$("#signup_form").submit(function(e) {
var formData = new FormData($(this));
$.ajax({
type: "POST",
url: "backend.php",
data: formData,
success: function(data) {
console.log(data);
// if (data.length > 0) ....
}
});
e.preventDefault();
return false;
});
});
PHP:
<?php
if (isset($_POST['signup_form'])){
$params = array();
$gett = $_POST['username'];
parse_str($gett,$params);
print_r ($gett);
echo $_POST['username'];
}else{
die('No $_POST data.');
}
?>
Your php code had some problems in it, you missed a semi-colon and you tried to print from an empty array, calls through ajax won't show any run time errors, and thus you need to be very careful when you're trying to debug an ajax to php call.
Hope this helps.
im trying to send a AJAX request to my database and get the information in JSON format back, then i want to replace my div with those json information. But my div wont get changed and i dont know why..
Here is my code and thank you very much for helping:
index.php
<form class="login-form" method="post" action="">
<input type="text" name="lusername" placeholder="username"/>
<input type="password" name="lpassword" placeholder="password"/>
<input type="image" name="login" src="src/login.png" onClick="getLoginInfo()">
<p class="message">Not registered? <span id="tab">Create an account</span></p>
<div id="test">change me pls</div>
</form>
login.php
<?php
require_once("connection.php");
if(isset($_POST['login_x']) or isset($_POST['login_y'])) {
$lusername = $_POST['lusername'];
$lpassword = $_POST['lpassword'];
$select = mysqli_query($connection, "SELECT Username, Password FROM Account WHERE Username='".$lusername."' AND Password='".$lpassword."'");
if(mysqli_num_rows($select) == 0) {
echo '<script>cantFindAccount()</script>';
} else {
$array = mysqli_fetch_row($select);
echo json_encode($array);
}
}
?>
getLoginInfo.js
function getLoginInfo() {
$.ajax({
url: 'http://localhost/login.php',
data: "",
dataType: 'json',
success: function(data) {
var user = data[0];
var pass = data[1];
$('#test').html("<b>id: </b>"+user+"<b> name: </b>"+pass);
}
});
return false;
}
Try this, you have to post some data to your script so that it would process. Moreover you have to use method: 'POST' because you have used $_POST[]
$.ajax({
url: 'http://localhost/login.php',
data: $(this).serialize(),
method: 'POST',
dataType: 'json',
success: function(data) {
var user = data[0];
var pass = data[1];
$('#test').html("<b>id: </b>"+user+"<b> name: </b>"+pass);
}
});
I'm new to using jQuery with AJAX. I want to build a simple form that prompts the user when one of the field inputs are incorrect.
My only requirement (for now) is that the name must be "John".
html (ajaxtutorial.html)
<!DOCTYPE html>
<html>
<head>
<title>AJAX Form</title>
</head>
<body>
<form action="ajax/contact.php" method="post" class="ajax">
<div>
<input type="text" name="name" placeholder="Your name">
</div>
<div>
<input type="text" name="email" placeholder="Your email">
</div>
<div>
<textarea name="message" placeholder="Your message"></textarea>
</div>
<input type="submit" value="Send">
<div>
</form>
<script src="js/jquery-1.11.0.js"></script>
<script src="js/main.js"></script>
</body>
</html>
jQuery (main.js):
$('form.ajax').on('submit', function() {
var that = $(this),
url = that.attr('action'),
type = that.attr('method'),
data = {};
that.find('[name]').each(function(index, value) {
var that = $(this), //references the inputs within the find function
name = that.attr('name'),
value = that.val();
data[name] = value;
});
$.ajax({
url: url,
type: type,
data: data,
dataType: 'json',
cache: false,
success: function(result) {
if(result.error == true) {
console.log('Did not type John');
}
else {
console.log('Typed John');
}
}
});
return false;
});
php (contact.php):
<?php
$errors = array();
$form_data = array();
$name = htmlspecialchars($_POST['name']);
$email = htmlspecialchars($_POST['email']);
$message = htmlspecialchars($_POST['message']);
if ($name != 'John') {
$errors['name'] = true;
}
if (array_key_exists('name',$errors)) {
$form_data['success'] = true;
$form_data['error'] = true;
} elseif (empty($errors)) {
$form_data['success'] = true;
}
echo json_encode($form_data);
?>
I feel it's simple, but can't solve it. I want to identify the error by it's class (i.e. result.['class']) in order to provide unique feedback for each error.
Thanks for the help
Try to use serialize() instead of looping like,
$('form.ajax').on('submit', function() {
var that = $(this),
url = that.attr('action'),
type = that.attr('method');
$.ajax({
url: url,
type: type,
data: that.serialize(),// use form.serialize() here
dataType: 'json',
cache: false,
success: function(result) {
if(result.error == true) {
console.log('Did not type John');
}
else {
console.log('Typed John');
}
}
});
return false;
});
Also in PHP in case of error, your are assigning success and error both try it like,
if (array_key_exists('name',$errors)) {
// remove success key from here
$form_data['error'] = true;// only error
} elseif (empty($errors)) {
$form_data['success'] = true; // only success
}
echo json_encode($form_data);
I have a form in a modal window. When I submit the form through ajax I don't get the success message. My aim is to see the message created in the php file in the modal after submitting the form. Here is the code:
<p><a class='activate_modal' name='modal_window' href='#'>Sign Up</a></p>
<div id='mask' class='close_modal'></div>
<div id='modal_window' class='modal_window'>
<form name="field" method="post" id="form">
<label for="username">Username:</label><br>
<input name="username" id="username" type="text"/><span id="gif"><span>
<span id="user_error"></span><br><br>
<label for="email">Email:</label><br>
<input name="email" id="email" type="text"/><span id="gif3"></span>
<span id="email_error"></span><br><br>
<input name="submit" type="submit" value="Register" id="submit"/>
</form>
</div>
The modal.js
$('.activate_modal').click(function(){
var modal_id = $(this).attr('name');
show_modal(modal_id);
});
$('.close_modal').click(function(){
close_modal();
});
$(document).keydown(function(e){
if (e.keyCode == 27){
close_modal();
}
});
function close_modal(){
$('#mask').fadeOut(500);
$('.modal_window').fadeOut(500);
}
function show_modal(modal_id){
$('#mask').css({ 'display' : 'block', opacity : 0});
$('#mask').fadeTo(500,0.7);
$('#'+modal_id).fadeIn(500);
}
The test.js for the registration of the user
$(function() {
$('#form').submit(function() {
$.ajax({
type: "POST",
url: "test.php",
data: $("#form").serialize(),
success: function(data) {
$('#form').replaceWith(data);
}
});
});
});
And the PHP FILE
<?php
$mysqli = new mysqli('127.0.0.1', 'root', '', 'project');
$username = $_POST['username'];
$email = $_POST['email'];
$mysqli->query("INSERT INTO `project`.`registration` (`username`,`email`) VALUES ('$username','$email')");
$result = $mysqli->affected_rows;
if($result > 0) {
echo 'Welcome';
} else {
echo 'ERROR!';
}
?>
Try putting the returncode from your AJAX call into
$('#modal_window')
instead of in the form
$('#form')
BTW: Why not use the POST or GET method of jQuery? They're incredibly easy to use...
Try something like this.
First write ajax code using jquery.
<script type="text/javascript">
function submitForm()
{
var str = jQuery( "form" ).serialize();
jQuery.ajax({
type: "POST",
url: '<?php echo BaseUrl()."myurl/"; ?>',
data: str,
format: "json",
success: function(data) {
var obj = JSON.parse(data);
if( obj[0] === 'error')
{
jQuery("#error").html(obj[1]);
}else{
jQuery("#success").html(obj[1]);
setTimeout(function () {
jQuery.fancybox.close();
}, 2500);
}
}
});
}
</script>
while in php write code for error and success messages like this :
if(//condition true){
echo json_encode(array("success"," successfully Done.."));
}else{
echo json_encode(array("error","Some error.."));
}
Hopes this help you.