display series of characters in a string using loops in php - php

Question

I want to make a series, e.g, 1/2 + 3/4 + 5/6 + 7/8 + 9/10 + 11/12 as a string using loops in php. write now i have written this code:
$output='';
for ($i=0; $i < 6; $i++)
{
$output=$output.($i+1+$i).'/'.($i+2+$i);
if ($i==5)
{
break;
}
else
{
$output=$output.'+';
}
}
echo nl2br("\n4: $output");
output:
1/2 + 3/4 + 5/6 + 7/8 + 9/10 + 11/12
is there any other better approach to do that?

Answer 1

preg_replace('/(\d+) \+ (\d+)/', '$1/$2', implode(" + ", range(1, 12)));
https://www.ideone.com/dKUIwc

Answer 2

With minimum of code it is:
$output = [];
for ($i = 0; $i < 6; $i++) {
$output[] = (2 * $i + 1) . '/' . (2 * $i + 2);
}
echo implode(' + ', $output);

Answer 3

Start loop from 1 and make step of 2 instead of one. Then put every sequence to array and finally implode it with +
$output = [];
for ($i = 1; $i <= 12; $i += 2) {
$output[] = $i . '/' . ($i + 1);
}
echo implode(' + ', $output);

Answer 4

as a string using loops in php. --> display as a string...
Use for loop and modulus operator %. Display first key, a forward slash, then continue the iteration outside that conditional and display the next key, then display a plus sign.
Continue iteration until you evaluate if the value is at the end of the array. Two conditionals inside the loop.
I used a iterator defined as $i as using a foreach loop would start at zero and you would have to do some extra code to get the last value.
$myArray = array(1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16);
$stmt = NULL;
for($i = 0; $i < count($myArray); $i++){
if($myArray[$i] % 2 ){
$stmt .= $myArray[$i]."/";
}else{
if($myArray[$i] !== end($myArray)){
$stmt .= $myArray[$i].' + ';
}else{
$stmt .= $myArray[$i];
}
}
}
OUTPUT: