PHP file permissions, chmod & mkdir not working - php

Question

I created a php function that allows me to add images to a folder within my web application project. Right now it only works when I manually set the permissions of the folder to write enabled. Unfortunately that is not exactly what I need, because when I push my code to my group members with git, they would still have to manually set the permissions of the folder to enable writing as well, in order for my pushed code to work. all my group members and I are each running this project locally via an apache server, and I believe the problem is that apache does not have access to write within any of the folders within the project unless the folders are somehow set to write enable for everyone. I feel like it's not feasible to tell all my group members to change their folder permissions just so my one function can write to a folder.
I am looking for a way to set file permissions within my php code, I have already tried php functions such as chmod and mkdir to set permissions, however it gives me errors saying that I don't have permission to use those functions, which I guess makes sense, but is there a possible work around?

Answer 1

$structure = 'path';
mkdir($structure, 0777, true)
or
$structure = 'path';
mkdir($structure)
chmod($structure, 0777);

Answer 2

<?php $result = mkdir ("/path/to/directory", "0777");
?>
Try this it will working

Answer 3

Try using this (if shell_exec() is allowed):
(list of issues: only works on linux, has a security issue with potential solutions at bottom of post)
<?php
function readFile($file) { return shell_exec("cat $file"); }
function writeFile($file,$cont) { return shell_exec("echo $cont > $file"); }
function makeFile($filename) { return shell_exec("touch $filename"); }
function makeFolder($filename) { return shell_exec("mkdir -pv $filename"); }
// the -pv was used so you could do makeFolder("1/2/3/4")
function appendFile($file,$cont) { fileWrite($file,readFile($file).$cont); }
function appendToTopOfFile($file,$cont) { fileWrite($file,$cont.readFile($file);); }
?>
Use escapeshellcmd or escapeshellargs to escape user input.
ex.
$file=escapeshellcmd($_GET['file']);
echo readFile($file);