Data not Displayed after Submit Post [duplicate] - php

Question

This question already has answers here:
"Notice: Undefined variable", "Notice: Undefined index", "Warning: Undefined array key", and "Notice: Undefined offset" using PHP
(29 answers)
Closed 2 years ago.
I have a problem with my project and i don't know to where is the bug.
Problem: After i Submit Form data is not fetch in the Page.
I tried var_dump($result) but is not return data.
I will Expose my Code and i hope you can help me or guide me to resolve the problem.
<?php
include "connect.php";
include 'header.php';
ini_set('display_errors', 1);
ini_set('display_startup_errors', 1);
error_reporting(E_ALL);
if (isset($_POST["Search"])) {
$table_name = 'imp_acc';
$query = "
SELECT * FROM '.$table_name.' WHERE available = 'YES'
";
if (isset($_POST["regi"], $_POST["stat"])) {
$query .= "
AND reg " . $_POST["regi"] . " AND stat " . $_POST["stat"] . "
";
}
$statement = $connect->prepare($query);
$statement->execute();
$result = $statement->fetchAll();
$total_row = $statement->rowCount();
$output = '';
if($total_row > 0)
{
$output .= '
<table class="table">
<thead>
<tr>
<th scope="col">RRG</th>
<th scope="col">LV</th>
<th scope="col">CR</th>
<th scope="col">PR</th>
<th scope="col">FR</th>
<th scope="col">ES</th>
<th scope="col">RO</th>
<th scope="col">BO</th>
<th scope="col">CP</th>
<th scope="col">SK</th>
<th scope="col">LP</th>
<th scope="col">PRI</th>
<th scope="col">Action</th>
<th scope="col"><th>
<th scope="col"></th>
</tr>
</thead>
';
foreach($result as $row)
{
$timestamp = strtotime($row['lap']);
$newformat = date('Y-m-d',$timestamp);
//$product_id = $row["id"];
$output .= '
<tr>
<td>' . $row["regi"] . '</td>
<td>' . $row["lv"] . '</td>
<td>' . $row["crr_rr"] . '</td>
<td>' . $row["prr_rr"] . '</td>
<td>' . $row["frr_rr"] . '</td>
<td>' . $row["stat"] . '</td>
<td>' . $row["b_o"] . '</td>
<td>' . $row["r_o"] . '</td>
<td>' . $row["cc_count"] . '</td>
<td>' . $row["sk_count"] . '</td>
<td>' . $newformat . '</td>
<td>' . $row["pri_cc"] . '</td>
</tr>
';
}
$output .= ' </table>';
}
else
{
$output = '<h3>No Data Found</h3>';
}
echo $output;
}
?>
Also i need your Opinion for finish my Projects.
I have a Search Page with alot of filters options.
Couple of them are not mandatory , are just optional.
Every filter have a different value in form.
I want to continue in this way to makes more POST like this:
if (isset($_POST["regi"], $_POST["stat"] , ....)
Or i can give a chance to Switch statement, to see how it works.
I wait your opinions and ideea.
Thank you for help

Answer 1

I find the error on code.
It was my fault because i using value and not the form name.
In form data i have something like this:
submit: "Search"
and the code need to be like this:
if (isset($_POST["submit"]))
Now i see another problem is my $result because it comes array.
Thank you for your tips and help.