PHP - How to calculate the values ​of the second foreach loop? - php

Question

I have a code that I am trying to make work but I just can't!
I have 2 arrays: 1-> Diares 2-> The value corresponds to each diary entry.
$diarioNum = array( [0] => 1 [1] => 2 [2] => 1 [3] => 3 [4] => 5 [5] => 1 [6] => 1 );
$vintoBookSX = array( [0] => -0.5 [1] => -0.4 [2] => -0.6 [3] => -0.4 [4] => -0.4 [5] => -1 [6] => -1 );
In my case I have multiply diaries and in the database from which I extrapolate the data are not in order, so I had to do this code:
<?php
$con = array_count_values($diarioNum);
foreach ($con as $key => $value) {
$pos = array_keys($diarioNum, $key);
echo "Diario " .$key. "<br>";
foreach ($pos as $ke => $val) {
$vBKsx = $vintoBookSX[$val];
echo $vBKsx . "<br>";
}
}
?>
Output:
Diario 1
-0.5
-0.6
-1
-1
Diario 2
-0.4
Diario 3
-0.4
Diario 5
-0.4
my Database table:
my Database table
Now I have to sum values ​​for each diary.
And then output it must be:
Diario 1
-3.1
Diario 2
-0.4
Diario 3
-0.4
Diario 5
-0.4
Can you help me please?

Answer 1

You seem to use a complicated way to do that, this is how I will do it (on PHP side):
$diarioNum = [ 1, 2, 1, 3, 5, 1, 1 ];
$vintoBookSX = [ -0.5, -0.4, -0.6, -0.4, -0.4, -1, -1 ];
$result = [];
foreach ($diarioNum as $k => $day) {
$result[$day][] = $vintoBookSX[$k];
}
print_r($result);
$sums = array_map('array_sum', $result);
print_r($sums);
demo
There's probably a better way to do it on DBMS side. Something like:
SELECT diarioNumero, SUM(VintoBook_SX)
FROM yourtable
GROUP BY diarioNumero
ORDER BY diarioNumero

Answer 2

Here is one more solution
$diarioNum = array(1, 2, 1, 3, 5, 1, 1 );
$vintoBookSX = array(-0.5, -0.4, -0.6, -0.4, -0.4, -1, -1 );
$result = array_fill_keys( array_unique($diarioNum), 0);
foreach ( $diarioNum as $key => $val ) {
$result[ $val ] += $vintoBookSX[ $key ];
}
foreach ( $result as $key => $val ) {
echo "Diario $key <br>";
echo $val . "<br>";
}