How to get element from array? - php

Question

How to get single element from this?
array(1) { [0]=> object(stdClass)#3 (2) { ["id"]=> int(29595) ["image_id"]=> string(20) "eohsidatfx8wyw5ltzt6" } }
I need to separate "image_id". How to do it? I tried
echo $result["image_id"]
but it doesn't work:
Notice: Undefined index: image_id in C:\xampp\htdocs\IGDB\moje\index.php on line 53

Answer 1

It seems your array only directly contains object(stdClass)#3. This object is itself an array containing id and image_id. You can access image_id by doing
echo $result[0]["image_id"];

Answer 2

Ok, got it.
$result3=array_column($result2, 'image_id');
echo $result3[0];

Answer 3

$myArray = array(
'#3' => array (
"id"=> 29595,
"image_id"=> "eohsidatfx8wyw5ltzt6"
)
);
what you are looking for is in the second level of your array.
Use a foreach loop to iterate of the arrays key/value pairs.
foreach($myArray as $value){
foreach($value as $key => $id){
if($key === 'image_id'){
$output = $id;// output now holds the vlaue of the key set with 'image_id'
}
}
}
If you know the value of the key, you can also access this by using the keys like so: $arrayname['firstlevelkey']['secondlevelkey'];
Notice: Undefined index: image_id in C:\xampp\htdocs\IGDB\moje\index.php on line 53
--> This is because you are defining an array with a key that does not exist in the array
echo $result["image_id"] --> here you are telling php that "image_id" is on the first level of the array, however, it looks to be nested in the second layer of the array you are trying to parse. $result['#3']['image_id'].
If you are not sure, write a conditional that looks in the first array using is_array(), if the first is a key value holding a child array. Then run the foreach loop again to look for the key/pair value.
foreach($arr as $values){
// do something if value is string
if(is_array($values){
foreach($values as $key => $value){
// check your second level $key/$value
}
}
}