Message: Undefined variable: beauty_detail in CODEIGNITER [duplicate] - php

Question

This question already has answers here:
"Notice: Undefined variable", "Notice: Undefined index", "Warning: Undefined array key", and "Notice: Undefined offset" using PHP
(29 answers)
Closed 2 years ago.
I have a form where user can select either book or beauty radio button. Code is working fine on book but showing an error on beauty. Code is the same except data fetch from database is different. I have tried but still stuck.
ERROR
A PHP Error was encountered Severity: Notice
Message: Undefined variable: beauty_detail
Filename: controllers/Welcome.php
Line Number: 87
if($result == 0){
echo "no recommendation";
} else{
foreach($result as $key=>$value){
$q = $this->mymodel->fetchBeautydetail($key);
foreach($q as $val){
$beauty_detail[$val->user_id]['product_id'] = $val->product_id;
$beauty_detail[$val->user_id]['product_rating'] = $val->rating;
}
}
(line number: 87) $this->load->view('beauty_dashboard', ['beauty_detail'=>$beauty_detail]);
}

Answer 1

Problem is scope.
Try following. (Declaring beauty_detail out of foreach)
$beauty_detail;
foreach($result as $key=>$value){
$q = $this->mymodel->fetchBeautydetail($key);
foreach($q as $val){
$beauty_detail[$val->user_id]['product_id'] = $val->product_id;
$beauty_detail[$val->user_id]['product_rating'] = $val->rating;
}
}
$this->load->view('beauty_dashboard', ['beauty_detail'=>$beauty_detail]);
}