I've never really used json_encode, but it's easy enough to do:
$result = $dblink->query("SELECT * FROM Contracts LIMIT 3");
$dbdata = array();
while ( $row = $result->fetch_assoc()) {
$dbdata[]=$row;
}
echo json_encode($dbdata);
/tada!
However, if I want to give the output data custom "column names", is there a simple way of doing this?
So, rather than outputting something like:
[{"TableColumn1":"147","TableColumn2":"9","TableColumn3":"39","TableColumn4":"32","TableColumn5":"41"...
I can have something like:
[{"My Own Title":"147","My Own Title 2":"9","My own title 3":"39",...
Try this
$result = $dblink->query("SELECT * FROM Contracts LIMIT 3");
$dbdata = array();
while ( $row = $result->fetch_assoc()) {
$rowarray = [];
$rowarray['My Own Title 1'] = $row['TableColumn1'];
$rowarray['My Own Title 2'] = $row['TableColumn2'];
$rowarray['My Own Title 3'] = $row['TableColumn3'];
$dbdata[]=$rowarray;
}
echo json_encode($dbdata);
Related
Can someone please help? I'm new to PHP and struggling to make this bit of code to work. For example I have a sql database table with the following schema and data:
Type....rent_price
a..........100
b..........200
c..........300
I want to be able to echo say, "a", in one section and "200" in another. The following code will display "a" but then I can't seem to get it to display anything from the rent_price column using a second array.
$result = $mysqli->query("SELECT * FROM dbc_posts ORDER BY ID ASC limit 3");
for ($set = array (); $row = $result->fetch_assoc(); $set[] = $row['type']);
for ($set1 = array (); $row = $result->fetch_assoc(); $set1[] =$row['rent_price']);
?>
<?php echo $set[0];?>
<?php echo $set1[1];?>
You loop through the results twice, without resetting. Try to loop only once:
$result = $mysqli->query("SELECT * FROM dbc_posts ORDER BY ID ASC limit 3");
$set = array ();
$set1 = array ();
while ($row = $result->fetch_assoc())
{
$set[] = $row['type'];
$set1[] =$row['rent_price'];
}
?>
<?php echo $set[0];?>
<?php echo $set1[1];?>
Depending on what you mean by '"a" in one section and "200" in another', you may be able to forgo creating the intermediate arrays and just print the values from your query as you fetch them. Two cells in a table row, for example:
while ($row = $result->fetch_assoc()) {
echo "<tr><td>$row[type]</td><td>$row[rent_price]</td></tr>";
}
your data is in the first element of array
$set1[0]
but youre probably better off maintaining the naming throughout
$results = array();
while ($row = $result->fetch_assoc()){
$results[] = $row;
}
foreach ($results as $result){
echo $result['type'];
echo $result['rent_price'];
}
OR
$results = array();
while ($row = $result->fetch_assoc()){
$results['types'][] = $row['type'];
$results['rent_prices'][] = $row['rent_price'];
}
foreach ($results['types'] as $type){
echo $type;
}
foreach ($results['rent_prices'] as $rent_price){
echo $rent_price;
}
I have 10 rows, however when I do the following, it's only giving me the last row. Any kind of help I can get on this is great appreciated!
$query = "select * FROM `$table`.`channels` WHERE `country`='vietnam' ORDER BY `chanid`";
$result = mysql_query($query,$db) or die(mysql_error());
$data = array();
while($row = mysql_fetch_array($result)) {
$chanid = $row['chanid'];
$data[navtitle] = "$chanid - $row[title]";
$data[navurl] = "http://www.localhost.com/vietnam.php?chanid=$row[chanid]&country=$row[country]";
$data[vid_art] = "$chanart";
}
$array2=array_merge(array($array,array($data));
$JSON=json_encode($array2);
echo $JSON;
My $data array is only outputs the last row of my mysql fetch. How can I get it to pull out all 10 rows that I have?
Each time you go through the
while($row = mysql_fetch_array($result)) {
loop, you're setting $data to a new value.
This means it'll only ever contain the last row's worth of data.
Your code should look something like this.
$array2 = array();
while ($row = mysql_fetch_array($result)) {
$data = array();
$chanid = $row['chanid'];
$data['navtitle'] = "$chanid - $row[title]";
$data['navurl'] = "http://www.localhost.com/vietnam.php?chanid=$row[chanid]&country=$row[country]";
$data['vid_art'] = $chanart;
$array2[] = $data;
}
$JSON = json_encode($array2);
I'm trying to put data from my database into seperate arrays within another array. This works but when I'm trying to fetch the 'user_id' information, it only shows one number so it works like a string. How can I get it to work like an array and get the entire user_id?
$fetch = mysqli_query($con, "SELECT * FROM spotify_userdata");
$return_arr = [];
while ($row = mysqli_fetch_array($fetch, MYSQL_ASSOC)) {
$return_arr[] = array(
$row_array['user_id'] = $row['user_id'],
$row_array['name'] = $row['name'],
$row_array['artists'] = $row['artists'],
);
}
$user = json_encode($return_arr[0]);
echo $user[2];
This code returns 1 so it show the third number of the user_id. How can I get it to show the entire user_id like this: 111434343
You have many things in your code that's wrong:
Remove the last array item's comma
Change
$return_arr = [];
To
$return_arr = array();
3.Add:
$row_array = array()
at the begginning of all that code
At the end your code must be like this:
$fetch = mysqli_query($con, "SELECT * FROM spotify_userdata");
$row_array = array();
while ($row = mysqli_fetch_array($fetch, MYSQL_ASSOC)) {
$return_arr = array(
$row_array['user_id'] = $row['user_id'],
$row_array['name'] = $row['name'],
$row_array['artists'] = $row['artists'],
);
}
$user = json_encode($return_arr[0]);
According to your code you should use:
echo $user['user_id'];
But the real problem is - where is $row_array initialized?!?
And even bigger problem - why use "=" inside array creation in the while ... it seems to me that "=>" would fit better, don't you think?
I have an existing database which has a table called PERSON with a field called NAME. What I’m trying to do is select all of the rows in the table where the NAME is "bill". And then I want the result to be stored in an array that I can step through at a later point.
Now, the problem is my code will only select the FIRST row with the name "bill" and ignore the rest of the rows where the NAME is "bill". At least that’s how it appears when I print out the array contents with print_r(). My code below:
<?php
$getAllPreview = "SELECT * from PERSON where NAME = 'bill'";
$getAllResult = #mysql_query( $getAllPreview );
$getAllRows = #mysql_fetch_assoc( $getAllResult );
print "<pre>";
print_r($getAllRows);
print "</pre>";
?>
<?php
$getAllPreview = "SELECT * from PERSON where NAME = 'bill'";
$getAllResult = #mysql_query( $getAllPreview );
while ($row = #mysql_fetch_assoc( $getAllResult ) ) {
$getAllRows[] = $row;
}
print "<pre>";
print_r($getAllRows);
print "</pre>";
?>
while($row = mysql_fetch_array($getAllResult, MYSQL_ASSOC)) {
$data[] = $row;
}
You just keep looping over mysql_fetch_assoc until no further rows are returned. If you want to output or process them, just do so in each iteration of the loop, as it's more efficient than placing it in an array first. But here you go anyway:
$allRows = array ();
while ($row = mysql_fetch_assoc( $getAllResult)) $allRows [] = $row;
<?php
$getAllPreview = "SELECT * from PERSON where NAME = 'bill'";
$getAllResult = #mysql_query( $getAllPreview );
$num_rows = mysql_num_rows($getAllResult);
while ($row = #mysql_fetch_assoc($getAllResult))
{
for($i=0;$i<$num_rows;$i++)
{
$array[] = $row;
}
}
?>
I am querying a database to get 6 values in my params table suing this;
$result = mysql_query("SELECT * FROM params");
while($row = mysql_fetch_array($result))
{
$param = $row['value'] ;
}
is this right, if so is their away i can add one to the variable name each time round so i get $param1, $param2....
I dont want to have to send a query to the database for each param, is it possible to get them all like this?
The simpliest way is to use an array:
$result = mysql_query("SELECT * FROM params");
$param = array();
$i = 0;
while($row = mysql_fetch_array($result)) {
$param[$i] = $row['value'] ;
$i++;
}
Than you get $param[0], $param[1], ...
You can create variable names like this:
${'var'.1}
${'var'.'1.cat'}
${'var'.$x}
${$y.$x}
and so on.
This seems like a design flaw. But what you can do is:
$count = 1;
$result = mysql_query("SELECT * FROM params");
while($row = mysql_fetch_array($result))
{
$paramname = 'param' . $count++;
$$paramname = $row['value'] ;
}
You may find the list function useful - http://php.net/manual/en/function.list.php
list($param1,$param2,$param3,$param4,$param5,$param6) = mysql_fetch_row($result);
Probably more use when using descriptive variables, just a thought.