Display information from SQL database to google chart - php

Question

I'm trying to display information from my SQL database to google charts.
The project is a health dashboard where I need to display steps, kcal, etc.
I got the information from the database but I'm having trouble looping over it (the same information displays multiple times). I assume the problem is somewhere at the "data.addrows"-code.
php
include('template.php');
$query = /** #lang text */ <<
SELECT * FROM project_healthinfo WHERE id = {$_SESSION['userId']} ORDER BY date DESC
END;
$res = $mysqli->query($query);
$result = $res->fetch_object();
$content = <<<END
<!-- Google Chart script starts here -->
<!--Load the AJAX API-->
// Load the Visualization API and the corechart package.
google.charts.load('current', {'packages':['corechart']});
// Set a callback to run when the Google Visualization API is loaded.
google.charts.setOnLoadCallback(drawChart);
// Callback that creates and populates a data table,
// instantiates the pie chart, passes in the data and
// draws it.
function drawChart() {
// Create the data table.
google.charts.load('current', {'packages':['line']});
google.charts.setOnLoadCallback(drawChart);
google.charts.load('current', {'packages':['line']});
google.charts.setOnLoadCallback(drawChart);
function drawChart() {
var data = new google.visualization.DataTable();
data.addColumn('string', 'Date');
data.addColumn('number', 'Steps taken');
data.addRows([
['$result->date', $result->steps],
['$result->date', $result->steps],
['$result->date', $result->steps]
]);
var options = {
chart: {
title: ''
},
width: 550,
height: 300
};
var chart = new google.charts.Line(document.getElementById('steps_chart'));
chart.draw(data, google.charts.Line.convertOptions(options));
}
</script>
<!-- Google Chart script ends here -->

Answer 1

You'll need to break the $content into two parts.
$before_result_date = <<<EOS
...
EOS;
$after_result_data = <<<EOQ
...
EOS;
Then the section between there should be a loop similar to this.
while($result = $mysqli->fetch_object()){
printf("['%s', %s],\n",$result->date, $result->steps);
}
and all together it would be something like this:
include('template.php');
$query = /** #lang text */ <<
SELECT * FROM project_healthinfo WHERE id =
{$_SESSION['userId']} ORDER BY date DESC
END;
$res = $mysqli->query($query);
print $before_result_date;
while($result = $mysqli->fetch_object()){
printf("['%s', %s],\n",$result->date, $result->steps);
}
print $after_result_date;
That should do it.