Check if password contains easy sequences with php [closed] - php

Question

Closed. This question needs to be more focused. It is not currently accepting answers.
Want to improve this question? Update the question so it focuses on one problem only by editing this post.
Closed 2 years ago.
Improve this question
I want to have an php check for easy passwords patterns like
123456
123456789
abcde
98764321
101010
202020
Is it possible to have a check like this that doesn't rely in maintaining an array of pre-defined strings ?

Answer 1

Just iterate to each letter and check if the next one is same, one less or one more as current. So you can create a score of uniqueness.
For last case you can check if there are duplicate characters and remove from score, too.
$passwords = ['123456', '123456789', 'abcde', '98764321', '101010', '202020', 'xhdgszu'];
foreach ($passwords as $password) {
$score = $length = strlen($password);
$chars = str_split($password);
for ($i = 0; $i < $length - 1; $i++) {
$currentChar = $chars[$i];
$nextChar = $chars[$i + 1];
if ($currentChar === $nextChar
|| ord($currentChar) - 1 === ord($nextChar)
|| ord($currentChar) + 1 === ord($nextChar)
) {
$score--;
continue;
}
}
$unique = array_unique($chars);
$score -= $length - count($unique);
echo "{$password}: {$score} / {$length} ", ($score < $length) ? 'Bad' : 'Good', PHP_EOL;
}
123456: 1 / 6 Bad
123456789: 1 / 9 Bad
abcde: 1 / 5 Bad
98764321: 2 / 8 Bad
101010: -3 / 6 Bad
202020: 2 / 6 Bad
xhdgszu: 7 / 7 Good