Echo gives different output from only html - php

I have this code:
echo " <div class=\"col-md-4 col-lg-3\"> "
. get_sidebar() ."
</div> ";
when I use it, sidebar doesnt show like col-md-4, it is full width.I want to use it as a sidebar.
but when I use the below html code instead of php function, page seems like how I want:
<div class="col-md-4 col-lg-3">
<?php get_sidebar(); ?>
</div>
what is the problem?

Problem is, that the function get_sidebar() is making echo by itself. It is not returning HTML code, which you could join with your HTML code.
This should work:
echo '<div class="col-md-4 col-lg-3">';
get_sidebar();
echo '</div>';

Related

how to get automatic converted 'echo' of php from html code?

I would like to easy to get converted code that 'echo' of php code from html code.
For example, Just like this.
http://www.accessify.com/tools-and-wizards/developer-tools/html-javascript-convertor/
This is a convert tool for JS printing code from html.
Conclude, I would like to see below
from
<div id="foo">
<div id="bar">
</div>
</div>
to
echo '<div id="foo">';
echo '<div id="bar">';
echo '</div>';
echo '</div>';
Thank you for read.
Not sure if this is what you are looking for but you can echo multiple lines of text like this:
echo <<< EOT
<div id="foo">
<div id="bar">
</div>
</div>
EOT;

Echo an image tag with site_url() inside PHP tags

I have a loop in my view that outputs all the content gathered from the database:
<?php foreach($content as $contentRow): ?>
<?php
echo $contentRow->value;
?>
<?php endforeach; ?>
This works fine for HTML strings like:
<h2><strong>Example Text</strong></h2>
however I have some image content that I would like to display and I have tried the following database entries to no avail:
<img src="<?php echo site_url('pathToImage/Image.png'); ?>" alt="Cover">"
<img src="site_url('pathToImage/Image.png')" alt="Cover\">"
I feel like I am missing a step on how to use PHP values in this way.
How do I access the URL of the image and use that to show the image?
Full Code Edit
<?php
$CI =& get_instance();
?>
<div class="container">
<div class="row">
<div class="col-md-9">
<div class="col-md-2"></div>
<div class="col-md-20">
<!--<form class="form-center" method="post" action="<?php echo site_url(''); ?>" role="form">-->
<!-- <h2 class="">Title</h2>
<h2 class=""SubTitle/h2>-->
<?php echo $this->session->userdata('someValue'); ?>
<!--//<table class="" id="">-->
<?php foreach($content as $contentRow): ?>
<tr>
<td><?php
echo $contentRow->value;
?></td>
</tr>
<?php endforeach; ?>
<!--</table>-->
<!--</form>-->
</div>
<div class="col-md-2"></div>
</div>
</div>
</div><!-- /.container -->
and the values are being read out in $contentRow->value;
I have to verify this, but to me it looks like you are echo'ing a string with a PHP function. The function site_url() is not executed, but simply displayed. You can execute it by running the eval() function. But I have to add this function can be very dangerous and its use is not recommended.
Update:
To sum up some comments: The use of eval() is discouraged! You should reconsider / rethink your design. Maybe the use of tags which are replaced by HTML are a solution (Thanks to Manfred Radlwimmer). Always keep in mind to never trust the data you display, always filter and check!
I'm not going to accept this answer as #Philipp Palmtag's answer helped me out alot more and this is more supplementary information.
Because I'm reading data from the database it seems a sensible place to leave some information about what content is stored. In the same table that the content is stored I have added a "content type" field.
In my view I can then read this content type and render appropriately for the content that is stored. If it is just text I can leave it as HTML markup, images all I need to do is specify the file path and then I can scale this as I see fit.
I have updated my view to something akin to this and the if/else statement can be added to in the future if required:
<?php foreach($content as $contentRow): ?>
<?php if ($contentRow->type != "image"): ?>
<?php echo $contentRow->value; ?>
<?php else: ?>
<?php echo "<img src=\"".site_url($contentRow->value)."\">"; ?>
<?php endif; ?>
<?php endforeach; ?>

Hide Div title if there's no content

I'm very newbie regarding PHP, I'm trying to configure my wordpress Loop.
I figured out how to display my customfield in my template, I manually added a title before my taxonomy and custom fields, but I'd like it doesn't show if the taxonomy is empty.
Here is the code:
<div class="customfields">
<h2 class="widgettitle">My Title</h2>
<?php echo do_shortcode('[tax id="agences" before="Agences : " separator=", " after=""]'); ?>
<?php echo do_shortcode('[custom_fields_block]'); ?>
</div>
I would very much appreciate your help!
Thanks a ton,
T.
So code should be
<?php $taxonomy = do_shortcode('[tax id="agences" before="Agences : " separator=", " after=""]'); ?>
<div class="customfields">
<?php if(!empty($taxonomy)) : ?>
<h2 class="widgettitle">My Title</h2>
<?php echo $taxonomy; ?>
<?php endif; ?>
<?php echo do_shortcode('[custom_fields_block]'); ?>
</div>
If you want to show content in HTML only if certain variables contain a value then you can create a simple if statement that uses PHP's isset function to determine whether or not the variables are set, and if true place some HTML on the page. You can read more about isset here.

Get PHP script result from a page with HTML content by AJAX

I have a PHP page with HTML content in it. Now I run some PHP codes between HTMLs and I get some results. The fact is, when I try to get a respond from this page by AJAX it'll show me the whole page content and plus the result I was looking for. What can I do to prevent the page from writing extra content. I know whenever something get printed on page it'll go as respond to the AJAX call but I want a way to somehow fix this.
My page file (name: page.php):
<?php echo $Content->GetData('HEADER'); ?>
<div id="Content">
<div id="Page">
<?php if($Content->GetData('PAGE','IS_TRUE')) : ?>
<?php if(NULL !== $Content->GetData('PAGE','TITLE')) : ?>
<?php echo $Content->GetPlugins("Page:" . $Content->GetData('PAGE','ID') . ",BeforeTitle"); ?>
<div id="Title" dir="rtl">
<?php echo $Content->GetData('PAGE','TITLE'); ?>
</div>
<?php echo $Content->GetPlugins("Page:" . $Content->GetData('PAGE','ID') . ",AfterTitle"); ?>
<?php endif; ?>
<div id="Content" dir="rtl">
<div style="float: right; width: 966px; padding: 6px">
<?php echo $Content->GetPlugins("Page:" . $Content->GetData('PAGE','ID') . ",BeforeContent"); ?>
<?php echo $Content->GetData('PAGE','CONTENT'); ?>
<?php echo $Content->GetPlugins("Page:" . $Content->GetData('PAGE','ID') . ",AfterContent"); ?>
</div>
</div>
<?php else : ?>
<div id="Content" dir="rtl">
<div style="float: right; width: 966px; padding: 6px">
There is no page like this in our archives.
</div>
</div>
<?php endif; ?>
</div>
</div>
<?php echo $Content->GetData('FOOTER'); ?>
If I write an address in my browser like this localhost/cload/blog?action=rate it'll go through my redirection list and show the page.php with blog plugin loaded. The problem is I want to call my blog plugin by AJAX through this address but it will first render the page data.
Sorry if this is messy.
I'd suggest modifying page.php to be some functions, primarily a data processing function, and then an output function. Then, when you load the page, put a check in for whether it's an AJAX request, and if so, echo the data you want as JSON, otherwise render the page using the output function.
Alternatively, you could create a second, separate page, but that could be more difficult to maintain than a single file.
Yes, you should check whether your request is a ajax request, if it is so you should change your response to return only the result whatever want.
This php code will give an rough idea on this.
if($request->isXmlHttpRequest()){
return new Response(json_encode($data_array));
}
Hope this will help.

Add HTML elements to the current page using PHP

So I have the need to dynamically add html content using php which isnt the tricky part but I'm trying to put the HTML into a different location in the document than where the PHP is being run. So for example:
<div id="firstDiv">
<?php
echo "<div id=\"firstDivA\"></div>";
echo "<div id=\"secondDivA\"></div>";
?>
</div>
<div id="secondDiv">
</div>
But I want to be able to place the some HTML inside "secondDiv" using the PHP that is executed in the "firstDiv". The end result should be:
<div id="firstDiv">
<div id="firstDivA"></div>
</div>
<div id="secondDiv">
<div id="secondDivA"></div>
</div>
But I have no idea how to go about doing that. I read about some of the DOM stuff in PHP 5 but I couldn't find anything about modifying the current document.
You can open/close "blocks" of PHP wherever you like in your HTML
<div id="firstDiv">
<?php echo '<div id="firstDivA"></div>'; ?>
</div>
<div id="secondDiv">
<?php echo '<div id="secondDivA"></div>'; ?>
</div>
You can also capture the output if necessary with ob_start() and ob_get_clean():
<?php
$separator = "\n";
ob_start();
echo '<div id="firstDivA"></div>' . $separator;
echo '<div id="secondDivA"></div>' . $separator;
$content = ob_get_clean();
$sections = explode($separator, $content);
?>
<div id="firstDiv">
<?php echo $sections[0]; ?>
</div>
<div id="secondDiv">
<?php echo $sections[1]; ?>
</div>
Why not just move the relevant code to the right place?
<div id="firstDiv">
<?php
echo "<div id=\"firstDivA\"></div>";
?>
</div>
<div id="secondDiv">
<?php
echo "<div id=\"secondDivA\"></div>";
?>
</div>
The .php file is continuous thus if you have two separate <?php ?> tags they will be able to share the same variables.
<div id="firstDiv">
<?php
echo "<div id=\"firstDivA\"></div>";
$div2 = "<div id=\"secondDivA\"></div>";
?>
</div>
<div id="secondDiv">
<?php echo $div2 ?>
</div>
This will give the desired effect. (Demonstrates the use of variables)
I'm not sure what you're asking. Perhaps just add an echo statement to the second div.
<div id="firstDiv">
<?php echo "<div id=\"firstDivA\"></div>"; ?>
</div>
<div id="secondDiv">
<?php echo "<div id=\"secondDivA\"></div>"; ?>
</div>
Or do you mean you want to make DIV changes after PHP? Try jQuery!
Or do you mean you want to make DIV changes before PHP is finished? Perhaps phpQuery is good for you then.
If you want to work with XML-data (read XHTML), you'd rather use an appropriate XML processor.
DomCrawler is an excellent to work with DOM. It works with the native DOM Extension and therefore is fast and widely used.
Here an example from the doc on how to add content:
$crawler = new Crawler();
$crawler->addHtmlContent('<html><div class="foo"></div></html>');
$crawler->filter('div')->attr('class') // returns foo

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