Define value of class when assigned to variable in PHP - php

Question

In PHP I can use \ArrayAccess to create an object such that it can be assigned as variable (an array) but also execute some other stuff while doing it, is it possible to do the same with a single value variable?, for example:
$a = new MyClass(5, "some other stuff")->print(); //Prints 'some other stuff'
$b = $a * 2;
echo $b; //Prints 10
The idea would be that the first parameter is returned when the variable is assigned but at the same time I can do something else with the second parameter, so far I have only manage to do it ussing the __invoke magic method, but the end result is something like this:
$a = new MyClass(5, "some other stuff")->print(); //Prints 'some other stuff'
$b = $a() * 2;
echo $b; //Prints 10
Is it possible to do it without the __invoke method?

Answer 1

This is the way I managed to do it with \ArrayAccess (just in case it helps)
class MySQLK_customArray implements \ArrayAccess{
private $storage = array();
private $queryk;
public function __construct($fetch_array, $query){
$this->queryk = $query;
$this->storage = $fetch_array;
}
public function offsetSet($key, $value)
{
if (is_null($key)) {
$this->storage[] = $value;
} else {
$this->storage[$key] = $value;
}
}
public function offsetExists($key)
{
return isset($this->storage[$key]);
}
public function offsetUnset($key)
{
unset($this->storage[$key]);
}
public function offsetGet($key)
{
if (! isset($this->storage[$key])) {
return null;
}
$val = $this->storage[$key];
if (is_callable($val)) {
return $val($this);
}
return $val;
}
public function print(){
echo $this->queryk.";";
return $this;
}
public function get(){
return $this->storage;
}
}
It can be used this way:
$arr = new MySQLK_customArray(array("id" => 1),"SELECT * FROM Table LIMIT 1")->print(); //Prints 'SELECT * FROM Table LIMIT 1'
echo $arr['id']; //Prints 1