Keep options selected in multiple combobox - php

Question

this is a code that generates a multiple dropdown list from a MySQL database and creates a table after clicking on a submit button with a selected option by default.
I need the table to be created when the page is loaded and also the dropdown list to keep the options selected after clicking the button.
Thanks in advance.
<?php
include 'conBBDD_1.php';
$db_handle = new conBBDD();
$TourResult = $db_handle->runQuery("SELECT DISTINCT bbcTour FROM concerts ORDER BY bbcDate DESC");
?>
<form method="POST" name="Search" action="example.php">
<?php
if (! empty($TourResult)) {
$format = "Tour 2020";
$select = 'selected';
echo "<select name='tour[]' id='bb_tour' multiple='multiple'>";
foreach ($TourResult as $key => $value) {
echo "<option value='" . $TourResult[$key]['bbcTour']."'";
if($TourResult[$key]['bbcTour']==$format) // to select one option only
echo $select. ">";
else
echo ">";
echo $TourResult[$key]['bbcTour'].'</option>' . "\n";
}
}
echo "</select>";
?>
<input type="submit" id="button" value="OK">
</form>

Answer 1

I don't quite understand the issue, but have cleaned this up for you.
If the issue is that (like your comment) you just want one item to be selected, remove the 'multiple' attribute from the select tag here.
Otherwise the 'multiple' tag and 'selected' just need to be lone strings w/ values.
<?php
include 'conBBDD_1.php';
$db_handle = new conBBDD();
$TourResult = $db_handle->runQuery("SELECT DISTINCT bbcTour FROM concerts ORDER BY bbcDate DESC");
echo '<form method="POST" name="Search" action="example.php">';
echo "<select name='tour[]' id='bb_tour' multiple>";
if (!empty($TourResults)) {
$format = "Tour 2020";
foreach ($TourResults as $Tour) {
echo "<option value='" . $Tour . "'";
if($Tour === $format) {
echo ' selected';
}
}
echo ">" . $Tour . "</option>\n";
}
echo "</select>";
echo "</form>";
?>