I need to send a response from the ajax to the php code. Alert msg as to be displayed when success.. I have to get entered date should be displayed in the url and response as to be sent..
<script>
$(document).ready(function() {
$('#txtdate').change(function(){
date = $(this).val();
$.ajax({
type: 'GET',
url: "http://localhost/data/check_date.php?date=" +date ,
success: function() {
alert(data);
}
});
});
});
</script>
Two error:
1:
date = $(this).val();
to
var date = $(this).val();
2:
url: "http://localhost/data/check_date.php?date=" +date ",
to
url: "http://localhost/data/check_date.php?date=" +date ,
3:
success: function() {
to
success: function(data) {
All script:
<script>
$(document).ready(function() {
$('#txtdate').change(function(){
var date = $(this).val();
$.ajax({
type: 'GET',
url: "http://localhost/data/check_date.php?date=" +date ,
success: function(data) {
alert(data);
}
});
});
});
</script>
Remove " mentioned at the end of the url because date is variable to be passed through url.
To overcome all mistakes change your whole code to
<script>
$(document).ready(function() {
$('#txtdate').change(function(){
var date = $(this).val();
$.ajax({
type: 'GET',
url: "http://localhost/data/check_date.php?date=" +date,
success: function(date) {
alert(date);
}
});
});
});
</script>
var date = $(this).val();
$.ajax({
type: 'GET',
url: "http://localhost/data/check_date.php?date=" +date ,
dataType: 'text',
success: function(data) { //add data in the function which is returned from the file
alert(data);
}
});
also try opening your network tab by clicking F12 in your browser before doing ajax request, if there's some error in your php file you can view it here in network tab, see if it helps
Related
Im using google chrome 65.0.3325.181 on windows 10, xampp is on to run the php. title explains the rest.
html/php:
$(document).ready(function (){
$('#sel_edificio').load('data.php');
$( ".form-control" ).change(function() {
var dato = 50;//document.getElementById("sel_edificio").value;
$.ajax({
method: "POST",
data: {'key': dato},
url: "uno.php",
success: function(status){
var asd = $('#test').load('uno.php');
//document.getElementById("NumEstudiantes").value(key);
}
});
});
});
</script>
uno.php:
<?php
echo $_POST['key'];
?>
error:
Notice: Undefined index: key in C:\xampp\htdocs\jqbd\uno.php on line 2
You are sending request two time, try this:
html/php
$(document).ready(function (){
$('#sel_edificio').load('data.php');
$( ".form-control" ).change(function() {
var dato = 50;//document.getElementById("sel_edificio").value;
$.ajax({
method: "POST",
data: {'key': dato},
url: "uno.php",
success: function(data){
$('#test').html(data);
}
});
});
});
change ajax method to type, try this
$.ajax({
type: "POST",
data: {'key': dato},
dataType: "json",
url: "uno.php",
success: function(status){
//var asd = $('#test').load('uno.php');
$('#test').load('uno.php', { key: dato });//document.getElementById("NumEstudiantes").value(key);
}
});
I am passing empcode using key press event, but my whole empcode is not transfered and the last digit is cut.
Here is my code:
$(document).ready(function(){
$("#e_code").keypress(function(){
//var dataString=document.getElementById("e_code").value;
var dataString = 'e_code='+ $(this).val();
$.ajax({
type: "POST",
url: "getdata.php",
data: dataString,
cache: false,
success: function (html) {
$('#details').html(html);
$('#custTrnHistory').show()
}
});
});
});
on getdata file code is
write code in keyup instead of keypress
$("#e_code").keyup(function(){
You can bind your keypress on document --- try this
$(document).on('keypress',"#e_code",function(){
Try this
$(document).ready(function(){
var minlength = 5; //change as per the the length of empcode
$("#e_code").keyup(function () {
var inputvalue= $(this).val();
if (inputvalue.length >= minlength ) {
var dataString = 'e_code='+ $(this).val();
$.ajax({
type: "POST",
url: "getdata.php",
data: dataString,
cache: false,
success: function (html) {
$('#details').html(html);
$('#custTrnHistory').show()
}
});
}
});
});
why isn't this working?
jQuery AJAX Code:
$("header input").bind("keyup", function()
{
var searchString= $("header input").val();
var dataString = 'search=' + searchString;
alert(dataString);
$.ajax({
type: "POST",
url: "index.php",
data: dataString,
cache: false
});
});
PHP Code(Just a test Code):
if($_POST["search"]) {
echo "TEST MESSAGE!";
}
It doesn't show The echo :/
thanks for ur help ;)
You need to display the data you receive from the ajax call.
Example, to put the result into a <div> called YourresultDiv:
Try with this
$("header input").on("keyup", function () {
var searchString = $("header input").val();
var dataString = 'search=' + searchString;
alert(dataString);
$.ajax({
type: "POST",
url: "index.php",
data: dataString,
cache: false,
success: function (data) {
$('#YourresultDiv').html(data);
alert("Successful");
}
});
});
Hopes this will help you....
$("header input").bind("keyup", function()
{
var searchString= $("header input").val();
var dataString = 'search=' + searchString;
alert(dataString);
$.ajax({
type: "POST",
url: "index.php",
data: dataString,
cache: false,
async: false
},success: function (data) {
$('div#posteddata').append(data);
}
);
});
<html>
<head>
</head>
<body>
<div id="posteddata"></div>
</body>
</html>
You need to specify an element you want to update.. for example
<div id="result"> </div>
and then append a success event handler to your ajax call
$("header input").bind("keyup", function () {
var searchString = $("header input").val();
var dataString = 'search=' + searchString;
alert(dataString);
$.ajax({
type: "POST",
url: "index.php",
data: dataString,
cache: false
}).success(function (data) {
$("#result").html(data);
}).fail(function () {
alert("Ajax failed!");
});
});
Try with this
In js add
success: function (data) {
// success handler
}
as your response handler
if($_POST["data"]) {
// search = search string available here in $_POST['data']
echo "TEST MESSAGE!";
}
where is your call back function in $.ajax() function,with callback function only,you can display anything through an ajax request..
So try this.
$("header input").on("keyup", function () {
var searchString = $("header input").val();
var dataString = 'search=' + searchString;
alert(dataString);
$.ajax({
type: "POST",
url: "index.php",
data: dataString,
cache: false,
success: function (data) {
$('#Yourdiv').html(data); // or $('#Yourdiv')text(data);
}
});
});
Without success function,you can see the echoed statement in your network segment in console.
for that, press F12,then you will get a link like
XHR finished loading: POST "http://localhost/yourproject/func_name.Click on that link and you will goto network segment and from there,click on the function name and then in response or preview tab,you canb see the echoed statement..
try it.
I have a html link with a value inside like this.
<a data-toggle='modal' data-id='1' href='#myModal' class='marker' title='Edit'>Link</a>
I have a Js script that trigger a php that I want to send the value data-id
<script>
$(document).on("click", ".marker", function () {
var myBookId = $(this).data('id');
$.ajax({
type: "post",
url: "update.php", //
data: myBookId,
success: function(msg) {
$("#thanks").html(msg)
},
error: function() {
alert("failure");
}
});
});
</script>
And in my php I have this
if (isset($_POST['myBookId'])) {
$emp_id = strip_tags($_POST['myBookId']);
echo $emp_id;
But something is wrong the value is not pass.
Your problem is on the params of the AJAX call. Try this way:
data: { myBookId: myBookId },
try
$('.marker')click(function(){
var myBookId = $().attr('data-id');
$.ajax({
type: "post",
url: "update.php", //
data: myBookId,
success: function(msg){
$("#thanks").html(msg)
},
error: function(){
alert("failure");
}
});
return false;
});
I want to send the data via ajax to other page. I have isolated the problem. This is the code.
Thank you all for your help..But no effect..
updated code
It worked...
<script>
$(document).ready(function(){
$(".edit").click(function(event) {
event.preventDefault(); //<--- to prevent the default behaviour
var box = 1233;
var size=123;
var itemname=123;
var potency=123;
var quantity=12333;
var dataString ={
'box' :box,
'size':size ,
'itemname':itemname,
'potency':potency,
'quantity':quantity
};
$.ajax({
url: "dd.php",
type: "post",
data: dataString,
success: function(data) {
alert(data);
},
error: function(data) {
alert(data);
}
});
});
});
</script>
So I click the link,it navigates, to dd.php which has
<?php
echo json_encode(array('itemcode'=>$_POST['itemname']));
echo $_POST['itemname'];
?>
I get Object Object as alert. What am doing wrong? Pls throw some light here..thanks you..
$(document).ready(function(){
$(".edit").click(function(event) {
event.preventDefault();
var data = {"box":1233,
"size":565,
"itemname":565,
"potency":876,
"quantity":234};
$.ajax({
url: "dd.php",
type: "post",
data: data,
dataType: "json",
success: function(data) {
if(console){
console.log(data);
}
},
error: function(data) {
if(console){
console.log(data);
}
}
});
});
});
few things to consider... you can post data as object..which is clean and easier to use
$(".edit").click(function(event) {
event.preventDefault(); //<--- to prevent the default behaviour
var box = 1233;
....
var dataString ={'box':box,'size':size,'itemname':itemname,'potency':potency,'quantity':quantity};
$.ajax({
url: "dd.php",
type: "post",
data: dataString,
dataType: "json", //<--- here this means the response is expected as JSON from the server
success: function(data) {
alert(data.itemcode); //<--here alert itemcode
},
error: function(data) {
alert(data);
}
});
so you need to send the response as json in PHP
<?php
echo json_encode(array('itemcode'=>$_POST['itemname']))
?>
Here you are using querystring as sent in GET request.
If you want to send the data in same form, you can use this with GET request type:
$.ajax({
url: "dd.php"+dataString,
type: "get",
dataType: "json",
success: function(data) {
console.log(data);
alert(data.itemcode);
},
error: function(data) {
alert(data);
}
});
Or for POST request,you will have to put data in json object form, So you can use :
var dataString ={
'box' :box,
'size':size ,
'itemname':itemname,
'potency':potency,
'quantity':quantity
};
$.ajax({
url: "dd.php",
type: "post",
data: dataString,
dataType: "json",
success: function(data) {
console.log(data);
alert(data.itemcode);
},
error: function(data) {
alert(data);
}
});
});
And put echo in your php code :
<?php
echo json_encode(array('itemcode'=>$_POST['itemname']))
?>
Javascript alert shows [Object object] for object. You can see response using console.log or can use that key with alert.
For more information, refer jQuery.ajax()