how to access the value of blob column(image) in controller laravel - php

Question

I make live search in laravel by ajax jquery
i send html code from controller to view but i can't display the value of blob column
function search (Request $request) {
if($request->ajax())
{ $output='';
$data=Club::all();
foreach($data as $record)
{
$output.='
<tr>
<td > '.$record->name.'</td>
<td > '.$record->country.'</td>
<td ><img src="data:image/png;charset=utf8;base64,{{base64_encode('.$record-
>logo.')}}" ></img></td> //this is uncorrect what is the correct syntax here???
</tr>
';
}
echo json_encode($output);
}
}

Answer 1

Try to return the data rather than display them using echo
json_encode() shall receive object or array, not HTML, return data from your API then format it in front-end.
if($request->ajax())
{ $output='';
$data=Club::all();
return json_encode($data); \\ return rather than display
}

Answer 2

if($request->ajax())
{
$output='';
$data=Club::all();
$path = $record->logo;
$type = pathinfo($path, PATHINFO_EXTENSION);
$data = file_get_contents($path);
$base64 = 'data:image/' . $type . ';base64,' . base64_encode($data);
foreach($data as $record)
{
$output.='
<tr>
<td > '.$record->name.'</td>
<td > '.$record->country.'</td>
<td ><img src="'.$base64.'" ></img></td> //this is uncorrect what is the correct syntax here???
</tr>
';
}
echo json_encode($output);
}