I can't properly use INNER JOIN. This is the actual return output via json on php.
[
{
"id": "1",
"itinerary_customer_id": "856",
"datetime_created": "2020-04-20 19:54:16",
"documents": [
{
"id": "1",
"itinerary_id": "1",
"datetime_created": "2020-04-20 22:51:12"
},
{
"id": "2",
"itinerary_id": "1",
"datetime_created": "2020-04-20 22:51:12"
},
]
},
{
"id": "2",
"itinerary_customer_id": "857",
"datetime_created": "2020-04-20 19:54:16",
"documents": [
{
"id": "3",
"itinerary_id": "2",
"datetime_created": "2020-04-20 22:51:12"
},
{
"id": "4",
"itinerary_id": "2",
"datetime_created": "2020-04-20 22:51:12"
},
]
}
]
Its look like array json and there's possible array inside each data.
Here's my existing code.
$sql = "SELECT * FROM itinerary INNER JOIN itinerary_documents ON itinerary_documents.itinerary_id = itinerary.id WHERE itinerary_customer_id = '".$customer_id."' ";
$result = $mysql->query($sql);
if ($result->num_rows > 0) {
while ($row[] = $result->fetch_assoc()) {
$item = $row;
$json = json_encode($item);
}
}else{
$item = array("error"=> true, "message"=> "No Itinerary found.");
$json = json_encode($item);
}
echo $json;
Related
I have a json data generated with the following php code
$index = array();
foreach($rows as $row)
{
$row['data'] []= (object) [];
$index[$row['cat_id']] = $row;
}
// build the tree
foreach($index as $id => &$row)
{
if ($id === 0) continue;
$parent = $row['parent'];
$index [$parent]['children'][] = &$row;
}
unset($row);
// obtain root node
$index = $index[0]['children'][0];
$json_data = json_encode($index, JSON_PRETTY_PRINT);
which produces the following json
{
"cat_id": "1",
"id": "RT",
"name": "root",
"parent": "0",
"url": "www.test.com",
"data": [
{}
],
"children": [
{
"cat_id": "4",
"id": "CI.001",
"name": "Test2",
"parent": "2",
"url": "www.test.com",
"data": [
{}
]
}
what i want is the output to be like this
var something = [{
"cat_id": "1",
"id": "RT",
"name": "root",
"parent": "0",
"url": "www.test.com",
"data": [
{}
],
"children": [
{
"cat_id": "4",
"id": "CI.001",
"name": "Test2",
"parent": "2",
"url": "www.test.com",
"data": [
{}
]
}];
I have looked through the web with some suggesting that it is not json but php array i'm new to json. How can I solve this ?
Here is is my solution at the moment.
ob_start();
echo "var javascript_array = [". $json_data . "];\n";
$content = ob_get_contents();
file_put_contents('../core/json/tree.js', $content);
Any suggestions and improvements will be appreciated.
This is my PHP code for json output:
$sql="SELECT id,name FROM languages ORDER BY id";
$result=mysqli_query($conn,$sql);
// Fetch all
$result = mysqli_fetch_all($result,MYSQLI_ASSOC);
$out_put = json_encode($result);
echo $out_put;
This is the json output of the above php code:
{
"0": {
"id": "1",
"name": "English"
},
"1": {
"id": "2",
"name": "Kanada"
},
"2": {
"id": "3",
"name": "Hindi"
},
"3": {
"id": "4",
"name": "Telugu"
}
}
But I want output like this:
{
"Responsecode":200,
"Message":"Sucess",
"languagelist": [
{
"id": "1",
"name": "English"
},
{
"id": "2",
"name": "Kannada"
},
{
"id": "3",
"name": "Hindi"
},
{
"id": "4",
"name": "Telugu"
}
]
}
I am trying to create API and I am new in it. Please help. Thank you in advance.
Just write
$out_put = json_encode([
"Responsecode" => 200,
"Message" => "Sucess",
"languagelist" => $result
]);
You can do it by this way:
$output['Responsecode'] = 200;
$output['Message'] = "Sucess";
$output['languagelist'] = $result;
$out_put = json_encode($output);
I've tried things like json_combine and array_merge but I can't figure out how to do this.
$query2 = "SELECT DISTINCT cat_id,cat_name FROM review WHERE user_id = ? AND public_or_private = 0";
$stmt2 = $con->prepare($query2) or die(mysqli_error($con));
$stmt2->bind_param('i', $user_id) or die ("MySQLi-stmt binding failed ".$stmt2->error);
$stmt2->execute() or die ("MySQLi-stmt execute failed ".$stmt2->error);
$result2 = $stmt2->get_result();
$array1 = array();
while ($row = mysqli_fetch_assoc($result2)) {
$array1['results'][] = $row;
}
echo json_encode($array1);
The json_encode gives me:
{"results":[{"cat_id":4,"cat_name":"dentist"}]}
And further down in my code I have:
$query3 = "SELECT DISTINCT cat_id,cat_name FROM review WHERE public_or_private = 2";
$result3 = mysqli_query($con,$query3);
$array2 = array();
while($row = mysqli_fetch_assoc($result3)) {
$array2['results'][] = $row;
}
echo json_encode($array2);
The json_encode gives me:
{
"results": [{
"cat_id": "8",
"cat_name": "dental hygienist"
}, {
"cat_id": "5",
"cat_name": "stocktaker"
}, {
"cat_id": "9",
"cat_name": "builder"
}]
}
So in total I have two json arrays:
{
"results": [{
"cat_id": 4,
"cat_name": "dentist"
}]
}
{
"results": [{
"cat_id": "8",
"cat_name": "dental hygienist"
}, {
"cat_id": "5",
"cat_name": "stocktaker"
},
{
"cat_id": "9",
"cat_name": "builder"
}
]
}
But how can I combine these into one like:
{
"results": [{
"cat_id": 4,
"cat_name": "dentist"
}, {
"cat_id": "8",
"cat_name": "dental hygienist"
}, {
"cat_id": "5",
"cat_name": "stocktaker"
},
{
"cat_id": "9",
"cat_name": "builder"
}
]
}
I tried things like:
$jsonArray = array();
foreach (array_combine( $array1, $array2 ) as $name => $value) {
$jsonArray[] = array('cat_id' => $name, 'cat_name' => $value);
}
echo $json = json_encode($jsonArray);
but still couldn't get it to work properly.
I guess you want to use array_merge_recursive instead.
echo json_encode(array_merge_recursive($array1, $array2));
Its not array_combine
You need to merge both array
$array1 = json_decode($array1, true);
$array2 = json_decode($array2, true);
$final_array = array_merge($array1['results'], $array2['results']);
Assuming you already have your arrays, you can do this:
$res1 = [
"results"=> [[
"cat_id"=> 4,
"cat_name"=> "dentist"
]]
];
$res2 = [
"results"=> [[
"cat_id"=> "8",
"cat_name"=> "dental hygienist"
], [
"cat_id"=> "5",
"cat_name"=> "stocktaker"
],
[
"cat_id"=> "9",
"cat_name"=> "builder"
]
]
];
$combinedArray = array_merge_recursive($res1, $res2);
$jsonCombinedArray = json_encode($combinedArray);
This results into
{
"results": [
{"cat_id":4,"cat_name":"dentist"},
{"cat_id":"8","cat_name":"dental hygienist"},
{"cat_id":"5","cat_name":"stocktaker"},
{"cat_id":"9","cat_name":"builder"}
]
}
I am trying to iterate both index of JSON(Players and Buildings), so that i can a get new result in jQuery
I have two index of JSON one having information of Players and second index having information of Building related Player.
I want to Parse it so that i can get Player and its building name.
My Actual JSON result
{
"Players": [
{
"id": "35",
"building_id": "8",
"room_num": "101",
},
{
"id": "36",
"building_id": "9",
"room_num": "102",
},
{
"id": "37",
"building_id": "10",
"room_num": "103",
},
{
"id": "38",
"building_id": "11",
"room_num": "104",
}
],
"Buildings": [
{
"id": "8",
"name": "ABC"
},
{
"id": "9",
"name": "DEF"
},
{
"id": "10",
"name": "GHI"
},
{
"id": "11",
"name": "JKL"
}
]
}
Need this
"information": [
{
"player_id": "35",
"Buildings_name": "ABC"
},
{
"player_id": "36",
"Buildings_name": "DEF"
},
{
"player_id": "37",
"Buildings_name": "GHI"
},
{
"player_id": "38",
"Buildings_name": "JKL"
}
]
}
Here you go, this go for each player and check if there are buildings and will map them to new structure. This will not filter values for buildings that do not have mapping to players, and will not include the buildings with no players.
var x = {
"Players": [
{
"id": "35",
"building_id": "8",
"room_num": "101",
},
{
"id": "36",
"building_id": "9",
"room_num": "102",
},
{
"id": "37",
"building_id": "10",
"room_num": "103",
},
{
"id": "38",
"building_id": "11",
"room_num": "104",
}
],
"Buildings": [
{
"id": "8",
"name": "ABC"
},
{
"id": "9",
"name": "DEF"
},
{
"id": "10",
"name": "GHI"
},
{
"id": "11",
"name": "JKL"
}
]
};
var res = $.map(x.Players, function(item) {
return {
player_id: item.id,
building_name: $.grep(x.Buildings, function(i) {
return i.id == item.building_id
}).length != 0 ? $.grep(x.Buildings, function(i) {
return i.id == item.building_id
})[0].name : undefined
}
})
and if you want to filter values that do not have relationships e.g INNER join
var resInnerJoin = $.grep($.map(x.Players, function(item) {
return {
player_id: item.id,
building_name: $.grep(x.Buildings, function(i) {
return i.id == item.building_id
}).length != 0 ? $.grep(x.Buildings, function(i) {
return i.id == item.building_id
})[0].name : undefined
}
}), function(it) {
return it.building_name != undefined
})
If you need it in PHP :
$json = '{...}';
// create and PHP array with you json data.
$array = json_decode($json, true);
// make an array with buildings informations and with building id as key
$buildings = array();
foreach( $array['Buildings'] as $b ) $buildings[$b['id']] = $b;
$informations = array();
for ( $i = 0 ; $i < count($array['Players']) ; $i++ )
{
$informations[$i] = array(
'player_id' => $array['Players'][$i]['id'],
'Buildings_name' => $buildings[$array['Players'][$i]['building_id']]['name']
);
}
$informations = json_encode($informations);
var_dump($informations);
I have:
$all = array(
array('id'=>1, 'cat'=>'Main','type'=>'Name0'),
array('id'=>2, 'cat'=>'Main','type'=>'Name1'),
array('id'=>3, 'cat'=>'Main','type'=>'Name3'),
array('id'=>4, 'cat'=>'Main','type'=>'Name4'),
array('id'=>5, 'cat'=>'Secondary','type'=>'Name5'),
array('id'=>6, 'cat'=>'Secondary','type'=>'Name6'),
array('id'=>7, 'cat'=>'Secondary','type'=>'Name7'),
array('id'=>8, 'cat'=>'Other','type'=>'Name8'),
array('id'=>9, 'cat'=>'Other','type'=>'Name9'),
array('id'=>10, 'cat'=>'Other','type'=>'Name10'),
array('id'=>11, 'cat'=>'Other','type'=>'Name11'),
);
$result = array();
foreach($all as $array){
$result[$array['cat']][] = array('id'=>$array['id'],'type'=>$array['type']);
}
$json_type = json_encode($result);
Which returns:
{"Main":[{"id":"1","type":"name1"},{"id":"2","type":"name2"},{"id":"3","type":"name3"},{"id":"4","type":"name4"}],"Secondary":[{"id":"5","type":"name5"},{"id":"6","type":"name6"},{"id":"7","type":"name7"}],"Other":[{"id":"8","type":"name8"},{"id":"9","type":"name9"},{"id":"10","type":"name10"},{"id":"11","type":"name11"}]}
But I need it to return as:
[
{
"text": "Main",
"children": [
{
"id": "1",
"text": "name1"
},
{
"id": "2",
"text": "name2"
},
{
"id": "3",
"text": "name3"
},
{
"id": "4",
"text": "name4"
}
]
},
{
"text": "Secondary",
"children": [
{
"id": "5",
"text": "name5"
},
{
"id": "6",
"text": "name6"
},
{
"id": "7",
"text": "name7"
}
]
},
{
"text": "Other",
"children": [
{
"id": "8",
"text": "name8"
},
{
"id": "9",
"text": "name9"
},
{
"id": "10",
"text": "name10"
},
{
"id": "11",
"text": "name11"
}
]
}
]
To work with the select2 JQuery plugin, I'm working with.
the 'children' name doesn't matter, I think that's just a placeholder so it gets parsed correctly. I'm not sure how I would go about it, I've been trying str_replace() but even that hasn't been working out so great.
I would to it in 2 loops. The first one to group results by category, the 2nd one to format it to fit your needs:
$temp = array();
foreach($all as $array){
if (!isset($temp[$array['cat']])) {
$temp[$array['cat']] = array();
}
$temp[$array['cat']][] = array('id'=>$array['id'], 'type'=>$array['type']);
}
$result = array();
foreach ($temp as $key=>$value) {
$result[] = array('text'=>$key, 'children'=>$value);
}
echo json_encode($result);
This produces the following output:
[{"text":"Main","children":[{"id":1,"type":"Name0"},{"id":2,"type":"Name1"},{"id":3,"type":"Name3"},{"id":4,"type":"Name4"}]},{"text":"Secondary","children":[{"id":5,"type":"Name5"},{"id":6,"type":"Name6"},{"id":7,"type":"Name7"}]},{"text":"Other","children":[{"id":8,"type":"Name8"},{"id":9,"type":"Name9"},{"id":10,"type":"Name10"},{"id":11,"type":"Name11"}]}]