how to pass a variable to a layout page PHP - php

Question

Hello im using two files 1. layout.html.php(for all the HTML code) 2.layout.php(for all the PHP code)
Im trying to send a variable from the layout.php to layout.html.php file
The variable is equal to a list of all jobs from a database table
See code below
I want to use this list of jobs in a unordered list as links in layout.html.php file
I would appreciate any help i can get with this
CODE FOR LAYOUT.HTML.PHP
<li>Jobs
<ul>
<?php
foreach ($jobs as $job){?>
<li><?= $job['name']?> </li>
<?php }?>
</ul>
CODE FOR LAYOUT.PHP
<?php
require '../loadTemplate.php';
$stmt = $pdo->prepare('SELECT * FROM job');
$stmt->execute();
$jobs= $stmt->fetchAll();
$templateVars = ['stmt' => $jobs];
$output = loadTemplate('../templates/layout.html.php',['stmt' => $jobs]);
require '../templates/layout.html.php';
?>

Answer 1

If in a file A you got the variable X:
<?php
$frase = "abcdef";
?>
Then if you want to use the same variable in another file you can use:
<?php
include('A.php');
echo $frase;
?>
There is other ways to do that. You can also use the Session, cookies, or just pass in the url.
In my case, I like to do in that way:
I have a page home.php. In that page I represents a consult. So, in home.php I got:
<?php
include 'php/db.php'
$result = BuscaDados();
while($row = $result->fetch_assoc()){
// here you get all lines
}
?>
In db.php I got a implementation of my functions that return the consult. Try it out.