Laravel version: 7.0 Here is my table.
Schema::create('model_email_form', function (Blueprint $table) {
$table->id();
$table->string('model_type');
$table->unsignedBigInteger('model_id');
$table->unsignedBigInteger('email_id');
$table->unsignedBigInteger('form_id');
$table->timestamps();
});
Here is my Service model.
public function forms()
{
return $this->morphToMany(
Form::class,
'model',
'model_email_form',
'model_id',
'form_id'
);
}
public function emails()
{
return $this->morphToMany(
Email::class,
'model',
'model_email_form',
'model_id',
'email_id'
);
}
I inserted data in model_email_form table but when I get service model object, emails and forms have null object.
Can anyone help me?
From your question and comments:
There are Form, Email and Service. Forms can be associated with any number of different types of models. Emails can be associated with any number of different types of models. A Service can have many Forms and a Service can have many Emails.
Using that as the basis, this would be our schema:
Schema::create('forms', function (Blueprint $table) {
$table->bigIncrements('id');
$table->string('name'); // as an example
...
$table->timestamps();
});
Schema::create('formables', function (Blueprint $table) {
$table->unsignedBigInteger('form_id'); // the id of the form
$table->unsignedBigInteger('formable_id'); // the associated model's id
$table->string('formable_type'); // The associated model's class name
});
Schema::create('emails', function (Blueprint $table) {
$table->bigIncrements('id');
$table->string('subject'); // as an example
...
$table->timestamps();
});
Schema::create('emailables', function (Blueprint $table) {
$table->unsignedBigInteger('email_id'); // the id of the email
$table->unsignedBigInteger('emailable_id'); // the associated model's id
$table->string('emailable_type'); // The associated model's class name
});
Schema::create('services', function (Blueprint $table) {
$table->bigIncrements('id');
$table->string('name'); // as an example
...
$table->timestamps();
});
With that schema, we can create the following models with the following relationships:
class Form extends Model
{
public function services()
{
return $this->morphedByMany(Service::class, 'formable');
}
// Add the other morphedByMany relationships of forms
}
class Email extends Model
{
public function services()
{
return $this->morphedByMany(Service::class, 'emailable');
}
// Add the other morphedByMany relationships of emails
}
class Service extends Model
{
public function forms()
{
return $this->morphedToMany(Form::class, 'formable');
}
public function emails()
{
return $this->morphedToMany(Email::class, 'emailable');
}
}
Related
I have a customer model that has many contacts. I defined a relationship to get the most recent contact of the customer using the "Has One Of Many" relationship in Laravel 8:
Models
class Customer extends Model
{
use HasFactory;
public function contacts()
{
return $this->hasMany(Contact::class);
}
public function latestContact()
{
return $this->hasOne(Contact::class)->ofMany('contacted_at', 'max')->withDefault();
}
}
class Contact extends Model
{
use HasFactory;
protected $casts = [
'contacted_at' => 'datetime',
];
public function customer()
{
return $this->belongsTo(Customer::class);
}
}
Migration (contact model)
class CreateContactsTable extends Migration
{
public function up()
{
Schema::create('contacts', function (Blueprint $table) {
$table->id();
$table->timestamps();
$table->softDeletes();
$table->foreignID('customer_id');
$table->string('type');
$table->dateTime('contacted_at');
});
}
}
In my view, I want to show all customers and order them by their latest contact. However, I can't figure out how to do that.
I tried to achieve it via the join method but then I obviously get various entries per customer.
$query = Customer::select('customers.*', 'contacts.contacted_at as contacted_at')
->join('contacts', 'customers.id', '=', 'contacts.customer_id')
->orderby('contacts.contacted_at')
->with('latestContact')
Knowing Laravel there must be a nice way or helper to achieve this. Any ideas?
I think the cleanest way to do this is by using a subquery join:
$latestContacts = Contact::select('customer_id',DB::raw('max(contacted_at) as latest_contact'))->groupBy('customer_id');
$query = Customer::select('customers.*', 'latest_contacts.latest_contact')
->joinSub($latestContacts, 'latest_contacts', function ($join){
$join->on([['customer.id', 'latest_contacts.customer_id']]);
})
->orderBy('latest_contacts.latest_contact')
->get();
More info: https://laravel.com/docs/8.x/queries#subquery-joins
I suspect there is an issue with your migration, the foreign key constraint is defined like this:
Check the documentation:
https://laravel.com/docs/8.x/migrations#foreign-key-constraints
Method 1: define foreign key constraint
public function up()
{
Schema::create('contacts', function (Blueprint $table) {
$table->id();
$table->foreignId('consumer_id')->constrained();
$table->string('type');
$table->dateTime('contacted_at');
$table->timestamps();
$table->softDeletes();
});
}
Method 2: define foreign key constraint
public function up()
{
Schema::create('contacts', function (Blueprint $table) {
$table->id();
$table->unsignedBigInteger('customer_id');
$table->foreign('customer_id')->references('id')->on('customers');
$table->string('type');
$table->dateTime('contacted_at');
$table->timestamps();
$table->softDeletes();
});
}
I want to enter some data from another table and save it in a table. I try to use relationship one to many, but I'm confused to save data
This is my database
public function up()
{
Schema::create('jenis_analisas', function (Blueprint $table) {
$table->bigIncrements('id');
$table->string('jenis_analisa', 100);
$table->unsignedBigInteger('kategori_id')->nullable();
$table->integer('harga');
$table->timestamps();
$table->foreign('kategori_id')->references('id')->on('kategoris');
});
}
public function up()
{
Schema::create('permintaan_analisas', function (Blueprint $table) {
$table->bigIncrements('id');
$table->unsignedBigInteger('pelanggan_id');
$table->string('judul_penelitian', 100);
$table->string('jenis_contoh', 50);
$table->string('jumlah_contoh');
$table->string('asal_contoh', 200);
$table->unsignedBigInteger('jenisanalisa_id')->nullable();
$table->timestamps();
$table->foreign('pelanggan_id')->references('id')->on('pelanggans');
$table->foreign('jenisanalisa_id')->references('id')->on('jenis_analisas');
});
}
This is my model
class JenisAnalisa extends Model
{
public function kategori()
{
return $this->belongsTo('App\Kategori');
}
public function permintaananalisa()
{
return $this->hasMany('App\PermintaanAnalisa');
}
}
class PermintaanAnalisa extends Model
{
public function jenisanalisa()
{
return $this->belongsTo('App\JenisAnalisa');
}
}
I want to insert multiple data from jenis_analisas table into permintaan_analisas table.
I have a table has many relation to other tables but it seperated with entity value please look at this :
i have this schema
public function up()
{
Schema::create('cards', function(Blueprint $table) {
$table->increments('id');
$table->timestamps();
$table->integer('user_id')->unsigned()->nullable();
$table->integer('entity_id');
$table->string('entity');
$table->integer('qty')->nullable()->default('1');
});
}
public function up()
{
Schema::create('tickets', function(Blueprint $table) {
$table->increments('id');
$table->timestamps();
$table->string('title');
$table->string('summary');
$table->integer('amount');
$table->integer('stock')->default('0');
$table->integer('discount')->default('0');
});
}
public function up()
{
Schema::create('products', function(Blueprint $table) {
$table->increments('id');
$table->timestamps();
$table->integer('title');
$table->integer('amount');
$table->integer('discount');
$table->text('description');
$table->integer('stock')->default('0');
});
}
and this relation in models
class Card extends Model
{
protected $table = 'cards';
public $timestamps = true;
public function ticket()
{
return $this->belongsTo('App\Models\Ticket', 'entity_id');
}
public function product()
{
return $this->belongsTo('App\Models\Product', 'entity_id');
}
}
i need to set where entity = 'ticket' before use belongsTo i mean is a table hase relation to many table base entity_id and i seperated it by entity column and base same vlue most have realation just.
You can do simply in your eloquent model file. do like this :
public function ticketWithCondition()
{
return $this->belongsTo('App\Models\Ticket', 'entity_id')->where('entity' , 'ticket');
}
public function ticket()
{
return $this->belongsTo('App\Models\Ticket', 'entity_id');
}
call like this :
// for show Card with EntityCondition
$comments = Card::find(123)->with('ticketWithCondition');
// for show comments without EntityCondition
$comments = Card::find(123)->with('ticket');
I have two models: Dish and DishCategory. I decided to implement a "One to many" relationship.
Here's a migration for Dish model:
Schema::create('dishes', function (Blueprint $table) {
$table->increments('id');
$table->string('dish', 50);
$table->string('photo');
$table->double('price', 8, 2);
$table->integer('category_id');
$table->integer('type_id'); /* 1 - menu for delivery; 0 - general menu */
});
And a migration for DishCategory model:
Schema::create('dish_categories', function (Blueprint $table) {
$table->increments('id');
$table->string('category');
});
I've created a method called dish() in DishCategory model:
public function dish()
{
return $this->hasMany('App\Dish');
}
And dish_category() in Dish model:3
public function dish_category()
{
return $this->belongsTo('App\DishCategory', 'category_id');
}
I'm trying to set up a foreign key in my relationship, so it's been set up in dish_category() method as a second parameter of belongsTo(). But it doesn't work. What is the workaround?
Change the dish() relationship definition to:
public function dish()
{
return $this->hasMany('App\Dish', 'category_id');
}
And dish_category() is defined correctly.
If you also want to add a constraint, add this to the dishes table migration:
Schema::table('dishes', function (Blueprint $table) {
$table->foreign('category_id')->references('id')->on('dish_categories');
});
I have a many-to-many relationship between my client and tag tables. A client can have many tags, and each tag can be related to multiple clients.
On the client show view, I'm trying to display the client info plus all tags associated to this client.
How do I change the query below to retrieve the client rows with all its related tags?
public function show($id)
{
$client = Client::findOrFail($id);
return view('clients.show')->with(['client' => $client]);
}
Client model
public function clienttag()
{
return $this->belongsToMany('App\Clienttag');
}
Clienttag model
public function client()
{
return $this->belongsToMany('App\Client');
}
Client_clientags table migration
public function up()
{
Schema::create('client_clienttag', function(Blueprint $table)
{
$table->integer('client_id')->unsigned();
$table->foreign('client_id')->references('id')->on('clients')->onDelete('cascade');
$table->integer('clienttag_id')->unsigned();
$table->foreign('clienttag_id')->references('id')->on('clienttags')->onDelete('cascade');
$table->timestamps();
});
}
Clients table migration
public function up()
{
Schema::create('clients', function(Blueprint $table)
{
$table->increments('id');
$table->string('first_name');
$table->string('last_name');
$table->rememberToken();
$table->timestamps();
});
}
Clienttags table migration
public function up()
{
Schema::create('clienttags', function(Blueprint $table)
{
$table->increments('id');
$table->string('tag');
$table->text('description');
$table->rememberToken();
$table->timestamps();
});
}
You can use "Eager Loading" methods like the following
public function show($id)
{
$client = Client::with('clienttag')->findOrFail($id);
return view('clients.show')->with(['client' => $client]);
}
Check documentation at http://laravel.com/docs/5.1/eloquent-relationships#eager-loading
Then at your view you can print your tags
#foreach ($client->clienttag as $tag)
{!! $tag->tagname!!} (or whatever your field in clienttags table name is)
#endforeach