Mongo distinct query with sort not working - php

I'm running a query in mongo using php like this:
$column ='address.roadname';
(new MongoDB\Client())->db->mycollection->distinct($column,[],['$sort'=> [$column => 1]]);
The query gives results, but those are not sorted.
What am I missing?
The data are just strings "nested" into inner object
What I expect is a list of street names sorted alphabetically
sample data:
[
{
"name": "tizio",
"address": [
{
"roadType": "via",
"roadname": "Roma",
"number": "12 bis",
"city": "Milano"
},
{
"roadType": "via",
"roadname": "Emilia",
"number": "124",
"city": "Modena"
},
{
"roadType": "via",
"roadname": "Appia",
"number": "89",
"city": "Genova"
}
]
},
{
"name": "caio",
"address": [
{
"roadType": "vicolo",
"roadname": "stretto",
"number": "12",
"town": "Monza"
},
{
"roadType": "largo",
"roadname": "Garibaldi",
"number": "24",
"city": "Modena"
},
{
"roadType": "piazza",
"roadname": "Armi",
"number": "26",
"city": "Rovigo"
}
]
},
{
"name": "sempronio",
"address": [
{
"roadname": "Roma",
"number": "15",
"city": "Milano"
},
{
"roadType": "via",
"roadname": "Po",
"number": "4",
"city": "Torino"
},
{
"roadType": "largo",
"roadname": "Garibaldi",
"number": "9",
"community": "Genova"
}
]
}
]
what I expect:
Appia,Armi,Emilia,Garibaldi,Po,Roma,Stretto
note: if I run it on mongo console
db.mycollection.distinct("address.roadname").sort()
I got the expected result

The PHP implementation of distinct does have a sort option, see https://docs.mongodb.com/php-library/v1.7/reference/method/MongoDBCollection-distinct/
In your shell example,
db.mycollection.distinct("address.roadname")
returns an array, so when you run .sort() on that it is using the javascript Array.sort method.
The PHP distinct function also returns an array, so use the sort function on it.

Related

MongoDB querying nested documents with filters

My MongoDB document looks something like this -
{
"VENDOR_ID": "101",
"NAME": "Test",
"DELETEFLAG": "1",
"DATETIME_MODIFIED": "2021-04-22 05:31:27am",
"CONTACT": [{
"CONTACT_ID": "111",
"CONTACT_TYPE": "CONTACT",
"DELETEFLAG": "1",
"LID": "197",
"USER_ID": "101",
"VALUE": "222222222222"
}, {
"CONTACT_ID": "222",
"CONTACT_TYPE": "EMAIL",
"DELETEFLAG": "1",
"LID": "197",
"USER_ID": "101",
"VALUE": "Test#gmail.com"
}, {
"CONTACT_ID": "333",
"CONTACT_TYPE": "CONTACT",
"DELETEFLAG": "2",
"LID": "197",
"USER_ID": "101",
"VALUE": "444444444444"
}, {
"CONTACT_ID": "444",
"CONTACT_TYPE": "CONTACT",
"DELETEFLAG": "2",
"LID": "197",
"USER_ID": "101",
"VALUE": "888888888888"
}]
}
I want to fetch all the Contacts for which the **DELETEFLAG** is set to 1. My collection can have multiple vendor documents.
I'm using PHP and fetching all the VENDORS with DELETEFLAG set to 1 along with their contacts. My query looks something like this -
$filterproduct = array(
"CONTACT.DELETEFLAG"=>'1',
"DELETEFLAG" => '1',
"LID"=>$LID,
);
$resultproduct1 = $this->GetMany($collectionName,$filterproduct,$fetchArr);
If I understand, you maybe want this:
db.collection.aggregate([
{ $unwind: "$CONTACT" },
{
$match: {
"CONTACT.DELETEFLAG": "1",
},
},
]);
Yopu break all documents in contacts with $unwind and so, get only new generated documents with CONTACT.DELETEFLAG = 1 with $match.

Sort Multiple Array to Numeric order (1,2,....,9,10,11) and Alphabetical order in PHP

How can I sort multidimensional array in numeric order first and then in alphabetical order in PHP. I have one array :
{
"id": "220",
"pin_list": [
{
"id": "1",
"name": "1. La Sagrada Familia",
},
{
"id": "2",
"name": "2. Park Guell",
},
{
"id": "3",
"name": "10. Casa Batllo",
},
{
"id": "4",
"name": "11. Cathedral of Barcelona",
},
{
"id": "5",
"name": "3. Picasso Museum",
},
{
"id": "6",
"name": "Zebra",
},
{
"id": "7",
"name": "Apple",
},
{
"id": "8",
"name": "Monkey",
}
]
}
I want this array to sort in Numeric first and rest are in alphabetical order. So basically want array output like this :
{
"id": "220",
"pin_list": [
{
"id": "1",
"name": "1. La Sagrada Familia",
},
{
"id": "2",
"name": "2. Park Guell",
},
{
"id": "5",
"name": "3. Picasso Museum",
},
{
"id": "3",
"name": "10. Casa Batllo",
},
{
"id": "4",
"name": "11. Cathedral of Barcelona",
},
{
"id": "7",
"name": "Apple",
},
{
"id": "8",
"name": "Monkey",
},
{
"id": "6",
"name": "Zebra",
}
]
}
I tried natsort and array_multisort but not able to get desired output. Any idea how to do this?
You can use usort on the pin_list element of the array (assuming you have decoded this JSON to an associative array), using strnatcmp to compare the name values:
usort($array['pin_list'], function ($a, $b) {
return strnatcmp($a['name'], $b['name']);
});
Demo on 3v4l.org

What is the most efficient way to change a list to a nested object in php

I have a list of (the result of a query in DB) like this:
[
{
"id": "1",
"parent_id": null,
"title": "مدادنوکی",
"url": "/medadnoki"
},
{
"id": "2",
"parent_id": null,
"title": "جامعه",
"url": "/commiunity"
},
{
"id": "5",
"parent_id": "1",
"title": "درباره ی مدادنوکی",
"url": "/about"
},
{
"id": "6",
"parent_id": "1",
"title": "درباره ی مدادنوکی",
"url": "/about"
},
{
"id": "7",
"parent_id": "2",
"title": "همکاران",
"url": "/co-worker"
},
{
"id": "8",
"parent_id": "2",
"title": "اساتید",
"url": "/masters"
}
]
But I want to create an object like this:
[
{
"title": "مدادنوکی",
"url": "/medadnoki",
"subs" : [
{
"title": "درباره مدادنوکی",
"url": "/about"
},
{
"title": "درباره مدادنوکی",
"url": "/about"
},
{
"title": "درباره مدادنوکی",
"url": "/about"
},
{
"title": "درباره مدادنوکی",
"url": "/about"
}
]
},
{
"title": "جامعه",
"url": "/soc",
"subs" : [
{
"title": "همکاران",
"url": "/co-work"
},
{
"title": "اساتید",
"url": "/masters"
}
]
}
]
I have handled this process with two foreach in php and it means I process data twice and it is not efficient and will be slow.
Is there any Idea to doing this with just one foreach?
using one foreach means faster than two foreach twice and It will show the result in big data
Assuming you have the results in an order where the parents appear in the results before any children they may have, this should work:
$nested = [];
foreach($results as $r) {
if($r['parent_id'] === null) {
$nested[$r['id']] = [
'title' => $r['title'],
'url' => $r['url'],
'subs' => []
];
continue;
}
$nested[$r['parent_id']]['subs'][] = [
'title' => $r['title'],
'url' => $r['url']
];
}
$nested = array_values($nested);

Get the values in PHP of three objects in Tripadvisor JSON API file

Been struggling with this for too long now, so am kindly asking for your help.
How can I, using PHP, get the values of the text fields in the reviews of which there are three in this JSON file below.
Want to use a foreach loop for this, thanks for helping me out!
{
"address_obj": {
"street1": "Rustenburgerstreet 384",
"street2": null,
"city": "Amsterdam",
"state": "North Holland Province",
"country": "The Netherlands",
"postalcode": "1072 HG",
"address_string": "Rustenburgerstreet 384, 1072 HG Amsterdam The Netherlands"
},
"percent_recommended": null,
"latitude": "52.35162",
"rating": "5.0",
"attraction_types": [
{
"name": "concerts",
"localized_name": "Concerts"
},
{
"name": "blues bars",
"localized_name": "Blues Bars"
},
{
"name": "jazz bars",
"localized_name": "Jazz Bars"
},
{
"name": "bar/ clubs",
"localized_name": "Bars & Clubs"
}
],
"wikipedia_info": null,
"location_id": "3724036",
"review_rating_count": {
"1": "0",
"2": "0",
"3": "1",
"4": "4",
"5": "35"
},
"ranking_data": {
"ranking_string": "#12 of 73 Theater & Concerts in Amsterdam",
"ranking_out_of": "73",
"geo_location_id": "188590",
"ranking": "12",
"geo_location_name": "Amsterdam"
},
"photo_count": "35",
"location_string": "Amsterdam, North Holland Province",
"trip_types": [
{
"name": "business",
"value": "0",
"localized_name": "Business"
},
{
"name": "couples",
"value": "8",
"localized_name": "Couples"
},
{
"name": "solo",
"value": "7",
"localized_name": "Solo travel"
},
{
"name": "family",
"value": "0",
"localized_name": "Family"
},
{
"name": "friends",
"value": "21",
"localized_name": "Friends getaway"
}
],
"web_url": "Attraction_Review-g188590-d3724036-Reviews-m34757-CC_Music_Cafe-Amsterdam_North_Holland_Province.html",
"reviews": [
{
"id": "353301385",
"lang": "en",
"location_id": "3724036",
"published_date": "2016-03-06T05:20:19-0500",
"rating": 5,
"helpful_votes": "0",
"rating_image_url": "img/cdsi/img2/ratings/traveler/s5.0-34757-5.png",
"url": "ShowUserReviews-g188590-d3724036-r353301385-CC_Music_Cafe-Amsterdam_North_Holland_Province.html#review353301385",
"trip_type": "Solo travel",
"travel_date": "2016-02",
"text": "I am a regular visitor of CC Muziekcafé Amsterdam but have felt at home from the very first time. What I like about CC is the atmosphere where great music and hospitality are mixed in the best way...",
"user": {
"username": "Yvon H",
"user_location": {
"name": "Groningen Province, The Netherlands",
"id": "188570"
}
},
"title": "A great place to hear live music and meet all sorts of interesting people, both local and traveling",
"is_machine_translated": false
},
{
"id": "351658487",
"lang": "en",
"location_id": "3724036",
"published_date": "2016-02-28T11:13:12-0500",
"rating": 5,
"helpful_votes": "0",
"rating_image_url": "img/cdsi/img2/ratings/traveler/s5.0-34757-5.png",
"url": "ShowUserReviews-g188590-d3724036-r351658487-CC_Music_Cafe-Amsterdam_North_Holland_Province.html#review351658487",
"trip_type": "Friends getaway",
"travel_date": "2016-02",
"text": "4th time we have been here, another great night at the music cafe, friendly people and a barman who knows how to just put enough swear words in to sound cool",
"user": {
"username": "Francois S",
"user_location": {
"name": "Cardiff, United Kingdom",
"id": "186460"
}
},
"title": "Jazz funk Jam session night Thursday",
"is_machine_translated": false
},
{
"id": "350605184",
"lang": "en",
"location_id": "3724036",
"published_date": "2016-02-24T10:18:57-0500",
"rating": 5,
"helpful_votes": "1",
"rating_image_url": "img/cdsi/img2/ratings/traveler/s5.0-34757-5.png",
"url": "ShowUserReviews-g188590-d3724036-r350605184-CC_Music_Cafe-Amsterdam_North_Holland_Province.html#review350605184",
"trip_type": "Couples",
"travel_date": "2015-09",
"text": "CC muziekcafe is a very cosy place with excellent live music and interaction with the musicians. What really makes the place is the owner Rene who knows a lot about music and now and then even sings...",
"user": {
"username": "ImagineNL",
"user_location": {
"name": "Schagen, The Netherlands",
"id": "609049"
}
},
"title": "Cupid",
"is_machine_translated": false
}
],
You can use this code
<?php
$json = <<<EOF
{
"address_obj": {
"street1": "Rustenburgerstreet 384",
"street2": null,
"city": "Amsterdam",
"state": "North Holland Province",
"country": "The Netherlands",
"postalcode": "1072 HG",
"address_string": "Rustenburgerstreet 384, 1072 HG Amsterdam The Netherlands"
},
"percent_recommended": null,
"latitude": "52.35162",
"rating": "5.0",
"attraction_types": [
{
"name": "concerts",
"localized_name": "Concerts"
},
{
"name": "blues bars",
"localized_name": "Blues Bars"
},
{
"name": "jazz bars",
"localized_name": "Jazz Bars"
},
{
"name": "bar/ clubs",
"localized_name": "Bars & Clubs"
}
],
"wikipedia_info": null,
"location_id": "3724036",
"review_rating_count": {
"1": "0",
"2": "0",
"3": "1",
"4": "4",
"5": "35"
},
"ranking_data": {
"ranking_string": "#12 of 73 Theater & Concerts in Amsterdam",
"ranking_out_of": "73",
"geo_location_id": "188590",
"ranking": "12",
"geo_location_name": "Amsterdam"
},
"photo_count": "35",
"location_string": "Amsterdam, North Holland Province",
"trip_types": [
{
"name": "business",
"value": "0",
"localized_name": "Business"
},
{
"name": "couples",
"value": "8",
"localized_name": "Couples"
},
{
"name": "solo",
"value": "7",
"localized_name": "Solo travel"
},
{
"name": "family",
"value": "0",
"localized_name": "Family"
},
{
"name": "friends",
"value": "21",
"localized_name": "Friends getaway"
}
],
"web_url": "Attraction_Review-g188590-d3724036-Reviews-m34757-CC_Music_Cafe-Amsterdam_North_Holland_Province.html",
"reviews": [
{
"id": "353301385",
"lang": "en",
"location_id": "3724036",
"published_date": "2016-03-06T05:20:19-0500",
"rating": 5,
"helpful_votes": "0",
"rating_image_url": "img/cdsi/img2/ratings/traveler/s5.0-34757-5.png",
"url": "ShowUserReviews-g188590-d3724036-r353301385-CC_Music_Cafe-Amsterdam_North_Holland_Province.html#review353301385",
"trip_type": "Solo travel",
"travel_date": "2016-02",
"text": "I am a regular visitor of CC Muziekcafé Amsterdam but have felt at home from the very first time. What I like about CC is the atmosphere where great music and hospitality are mixed in the best way...",
"user": {
"username": "Yvon H",
"user_location": {
"name": "Groningen Province, The Netherlands",
"id": "188570"
}
},
"title": "A great place to hear live music and meet all sorts of interesting people, both local and traveling",
"is_machine_translated": false
},
{
"id": "351658487",
"lang": "en",
"location_id": "3724036",
"published_date": "2016-02-28T11:13:12-0500",
"rating": 5,
"helpful_votes": "0",
"rating_image_url": "img/cdsi/img2/ratings/traveler/s5.0-34757-5.png",
"url": "ShowUserReviews-g188590-d3724036-r351658487-CC_Music_Cafe-Amsterdam_North_Holland_Province.html#review351658487",
"trip_type": "Friends getaway",
"travel_date": "2016-02",
"text": "4th time we have been here, another great night at the music cafe, friendly people and a barman who knows how to just put enough swear words in to sound cool",
"user": {
"username": "Francois S",
"user_location": {
"name": "Cardiff, United Kingdom",
"id": "186460"
}
},
"title": "Jazz funk Jam session night Thursday",
"is_machine_translated": false
},
{
"id": "350605184",
"lang": "en",
"location_id": "3724036",
"published_date": "2016-02-24T10:18:57-0500",
"rating": 5,
"helpful_votes": "1",
"rating_image_url": "img/cdsi/img2/ratings/traveler/s5.0-34757-5.png",
"url": "ShowUserReviews-g188590-d3724036-r350605184-CC_Music_Cafe-Amsterdam_North_Holland_Province.html#review350605184",
"trip_type": "Couples",
"travel_date": "2015-09",
"text": "CC muziekcafe is a very cosy place with excellent live music and interaction with the musicians. What really makes the place is the owner Rene who knows a lot about music and now and then even sings...",
"user": {
"username": "ImagineNL",
"user_location": {
"name": "Schagen, The Netherlands",
"id": "609049"
}
},
"title": "Cupid",
"is_machine_translated": false
}
]
}
EOF;
$array = json_decode($json, true);
$texts = array_map(
function($item) {
return $item['text'];
}, $array['reviews']
);
It doesn't seem like you need a foreach to fetch the reviews element. Not sure if I understood your question correct, but did you want something like this:
$assoc_json = json_decode($your_json, true);
var_dump($assoc_json['reviews']);
The above turns your json into an associative array, and just access the review element.
A simple, naive approach would be:
//Loads your json file 'tripadvisor' into jsonString
$jsonString = file_get_contents("/tripadvisor.json");
//Turns your string into an associative array
$tripJsonAssoc = json_decode($jsonString, true);
//Iterate through each review and store it in result
$result = array();
foreach($tripJsonAssoc['reviews'] as $review) {
$result[] = array('text' => $review['text'],
'rating' => $review['rating']);
}
//Do what you need to do with result
//...
Or you can just do your own stuff inside the foreach loop.
This answer gives you another way (more elegant) to create the 'result' array, but since you asked for a 'foreach', I thought I would add my 5 cents.

Parsing Rome2Rio json file with PHP

I am trying to extract a segment from the json file of Rome2Rio API with PHP but I cant get an output.
The json file from rome2rio:
{
"serveTime": 1,
"places": [
{ "kind": "town", "name": "Kozani", "longName": "Kozani, Greece", "pos": "40.29892,21.7972", "countryCode": "GR", "regionCode": "ESYE13" },
{ "kind": "city", "name": "Thessaloniki", "longName": "Thessaloniki, Greece", "pos": "40.64032,22.93527", "countryCode": "GR", "regionCode": "ESYE12" }
],
"airports": [],
"airlines": [],
"aircrafts": [],
"agencies": [{
"code": "KTEL",
"name": "KTEL",
"url": "http://www.ktelbus.com/?module=default\u0026pages_id=15\u0026lang=en",
"iconPath": "/logos/Trains/KTELgr.png",
"iconSize": "27,23",
"iconOffset": "0,0"
}
],
"routes": [
{ "name": "Bus", "distance": 121.04, "duration": 120, "totalTransferDuration": 0, "indicativePrice": { "price": 9, "currency": "EUR", "isFreeTransfer": 0 },
"stops": [
{ "name": "Kozani", "pos": "40.30032,21.79763", "kind": "station", "countryCode": "GR", "timeZone": "Europe/Athens" },
{ "name": "Thessaloniki", "pos": "40.6545,22.90233", "kind": "station", "countryCode": "GR", "timeZone": "Europe/Athens" }
]
The PHP code I wrote is:
$json_rome2rio = file_get_contents("http://free.rome2rio.com/api/1.2/json/Search?key=&oName=kozani&dName=thessaloniki");
$parsed_json_r = json_decode($json_rome2rio);
echo $parsed_json_r->agencies->name;
The agencies property contains an array of agencies (note the square brackets). To access the name as you're after, you can do the following:
echo $parsed_json_r->agencies[0]->name;
This assumes that at least one agency is returned and that the agency you are after is the first one if more than one is returned.

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